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1881 , 3553 , 5225 , 8778 , Total =  4 such palindromes.

Let S be the total number of students.  Then

0.2S + 42 = S

0.8S = 42

S = 42/0.8 = 52.5

Wow, the class has half a student!

Are you sure you didn't mean 40 students like to play soccer?

Tem certeza que não quis dizer que 40 alunos gostam de jogar futebol?

\((x+1)^2+(y-4)^2=4\)

700

or

12732

any number where the 7 is in the hundreds column.

I think the questioner means express as a ratio .

\(502.5=502+\frac{1}{2}=\frac{1004+1}{2}=\frac{1005}{2}\)

All the terms cancel out. 

The positive 75 cancels with the negative 75; the positive 72 cancels with the negative, and so on and so forth.

In step 2 it says the slope of \(\overline{AC}\) is \(-{1 \over 2}\), meaning the slope of the altitude is the negative reciprocal, which is 2 not -2.

The line would cross through the point \((2, 1)\), so the equation of this line would be \(y = 2x - 3\). 

So, we have to solve this system: \(y = 3\)

                                                      \(y = 2x - 3\)

Hey guest, that's completely wrong. The answer is \(4\sqrt2\).

literally just simplify

x^-y

turns into:

1/(x^y)

hope this helps!

That is not a valid answer. You need to simplify it as much as you can. 

502.5 is rational.....

The following should help:

(a)  \(100(\frac{22}{7} - \pi)/\pi = 0.04\%\) 

I'll leave you to do (b) in the same way.

\(1/2 (4 - \sqrt{10}) <= t <=1/2 (4 + \sqrt{10})\) 

t can be 1, 2 and 3.

- Eyedrop

I am assuming you are talking about LaTeX. Use \frac

- Eyedrop

\(14\sqrt{y^8}\) is another solution

- Eyedrop

All values of \(x\) can be solutions.

- Eyedrop

At the start, David has 34 dollars and Juan has 72 dollars. Juan's money stays the same after David spends some money, and we are told he has three times as much as David after David spends some of his money. 72/3 is 24 dollars, which is what David is left with. 34-24 is \(\boxed{10}\) dollars

- Eyedrop

Correct!  Search for the Clay Institute Millenium problems for the details.

Let Juan's money ==J
David's money ==J - 38

J + J - 38 ==106, solve for J
2J ==106 + 38==144
J == 144 / 2 ==$72 - Juan's money

106 - 72 ==$34 - David's money

Let the amount spent by David==D
34  -  D == 1/3 * 72==24
D ==34 - 24 ==$10 - what David spent at the store

Here's a way without matrixes: 

Adding all 4 equations gives us \(3(w+x+y+z) = 33\), meaning \(w+ x + y + z = 11\).

Using this, we know \(w = -1\), \(x = -8\), \(y = 7\), and \(z = 13\). 

So, we have \((-1 \times -8) + (7 \times 13) = \color{brown}\boxed{99}\)

PLEASE NOTE: I accidentally wrote GCD over their when I meant LCM

BTW:

60,12,6,30 GCD = 6

30,15,20,60 GCD = 5

60,12,4,20 GCD = 4

6,30,15,6 GCD = 3

6,12,4,6 GCD = 2

4,6,15,20 GCD = 1

so 60+30+20+15+12+6+6+4=153

y=(3/2)x