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are you asking "4 -= 3-x"? or if you're asking "-4 = 3-x", its 7

-4 = (3-7)

-4 = -4

There is no greatest common factor.

First, get 0 on one side.

x^2 + 16x - 22 = 0

Factors of 22: (22, 1) and (11, 2)

We see that there is no factors of 22 that add/subtract to get 16.

Complete the square:

x^2 + 16x + 64 = 86

(x + 8)^2 = 86

\(x + 8 = \pm\sqrt{86}\)

\(x = -8 \pm \sqrt{86}\)

well after about 10 minutes of doing the math I can say it's 80 minutes. You can check the work by doing 7 ml times 80 minutes equals 560 ml minus 800 equals 240 ml after 80 minutes in the 800 ml container. then you do 12 ml times 80 minutes equals 960 ml minus 1200 to get 240 ml in container b after 80 minutes. after 80 minutes both containers will have the same amount of water which is 240 mL

I feel dumb

Thank so much! 

(2+2)x(4/1) =x

(4)x(4)=x

4(4)= 16

16 = x

its 16

How many extra day(s) will the remaining bricklayers need?

Hello Guest!

\(C-castle\ building, b-bricklayer, d-days\\ C=\frac{C}{60_b\cdot 16_d}\cdot (5_d\cdot 60_b+(16-5+x)_d\cdot (60-5)_b)\ |\ :C\\ 60\cdot 16=5\cdot 60+(16-5+ x)\cdot 55\\ 960=300+(11+ x)\cdot 55\\ 960=300+605+55x\\ x=\dfrac{960-300-605}{55}\\ \color{blue}x=1\)

The remaining masons need an additional day.

  !

and who are you?

This should help:

Find x from these two equations.  Then you should be able to find the required area by subtracting the area of the two identical triangles from the area of the rectangle.

See https://web2.0calc.com/questions/plz-help_2147

Like so:

Can you finish?

Set -4.9t^2 + 14t - 0.4 = 6, solve the quadratic for two values of t and take the difference between them.

Answer is :       F^-1 (x) =  x/8 + 1 !

Write f(x) =8x-8 as an equation :

y = 8x-8

Interchange the variables :

x = 8y - 8

Solve for Y :

Y= x/8 + 1

Replace Y with f^-1 (x) to show the final answer:

F^-1 (x) = x/8 + 1

And the last one...verify if f^-1 (x) = x/8 + 1 is the inverse  of f(x) = 8x-8.

So answer is : F^-1 (x) = x/8 + 1 !!

Tell me if I've done something wrong! ( If you want to verify , verify it by yourself). Its just so easy!

\((x^2 + 2x + 5 - x - 4)(3x^2 - x - 4 + 2x + 8) \ge 0\\ (x^2 + x + 1)(3x^2 + x +4) \ge 0\\ \qquad \text{consider the roots of}\; x^2+x+1\\ \qquad \triangle=b^2-4ac=1-4=-3<0 \qquad\text{ no real roots}\\ \qquad \text{consider the roots of}\; 3x^2+x+4\\ \qquad \triangle=b^2-4ac=1-48=-47<0 \qquad\text{ no real roots}\\ \)

Since the coefficiant of x^4 is positive, and there are not real roots. 

this funtion will always be positve.

x is in the set of real numbers (no restrictions) 

ok

triangle LMN is congruent to triangle ONM  so LM=NO

And NP is a half of NO

And RQ=NP

So the horizontal distance from Q to L is 3 times the horizontal distance from Q to R

Triangles  RPQ and LPQ share the same base, that is PQ

But the perpendicular height of LPQ is three times that of RPQ 

Since the area of triangle RPQ is  27,

It follows that the area of LPQ is  3*27=  81u^2

a.  If it can be shown that it's the same person, or handful of people,  

     posting incorrect answers, I would think that'd be pretty conclusive. 

     See commment at https://web2.0calc.com/questions/geometry_51958  

b.  It has been going on for a long time, but I believe that lately the incidents  

     seem to have significantly increased. 

c.  I don't know if the moderators can detect these posters by their IPA number(s).  

    They're able to identify them that way at eBay, and sometimes eBay bans them. 

Two joggers are running around an oval track in opposite directions. One jogger runs around the
track in 56 seconds. They meet every 20 seconds. How many seconds does it take the second jogger
to run around the track?  

Place both joggers at the same spot on the track, and fire the starting pistol.  

At the rate of 56 seconds to go all the way around, Jogger A runs 1/56 of the track in one second. 

So when the two meet, 20 seconds later, Jogger A has run 20/56 of the way around the oval track. 

To get there at at the same time, Jogger B had to run 36/56 of the way around in the other direction. 

Since it takes Jogger B 20 seconds to run 36/56 of the way around, his speed is (36/56 oval) / (20 sec)  

Doing the arithmetic, Jogger B's speed is 36/1120 oval per second.  This is very close to 1/31.1 oval per second. 

At 1/31.1 oval per second, it takes Jogger B  31.1 seconds  to run all the way around the oval track.  

_.

Let the time taken by the 2nd jogger = T

1/56  +  1/T =1/20

1/T =1 / 20  -  1/56

T = 31 + 1/9 seconds - time taken by the 2nd jogger.

(a)  Let his average speed driving home=S

When the distance back and forth is the same, then:

Average speed =Harmonic mean

[2 x S x 15] / [S + 15] =35, solve for S

S = - 105 mph ??! - Not possible. You average speed must be less than 30 mph. Check your numbers carefully.

(b) [2*30*S] / [30 + S] ==40, solve for S

S ==60 mph

(a) 60 miles per hour

(b) 72 miles per hour

AB = 6*sqrt(3)

the answer is 32 seconds.