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A town has a population of 14000 and grows at 5% every year. What will be the population after 14 years, to the nearest whole number? 

14,000 x 1.05                                    end of 1st year 

14,000 x 1.05 x 1.05                          end of 2nd year 

14,000 x 1.05 x 1.05 x 1.05                end of 3rd year 

14,000 x 1.05 x 1.05 x 1.05 x 1.05      end of 4th year 

and so on.  You keep multiplying the previous amount by 1.05 until  

you've got to the end of the 14th year.  This can be expressed as 

14,000 x 1.05¹⁴  which works out to 27,719. 

The population will be 27685.

Hi Tiggsy

okay, you gave for odds we have (3*3*1*3) =27..agrre

for odd/even, you calculated (3*3*1*2) = 18...agree

I have calculated evens....and got (3*2*1*1) = 6

and even/odd is (3*4*1*2) = 24

everything added together is 75?

The area is 30.

First find the base. The base is found using phytagoreas theory. We should have 36+64=100. The square root of 100 is 10. Now use the triangle area formula to find the area. 1/2*60=30.

Hi guest,

Thanks for your input, I'm looking at this now...no, the denominator is 840,Yep sorry, the 1st question (Which I did not post here), gave a different scenario, saying that a lock code must be even numbered, and may not contain digits 0 and 1. Digits may not be repeated. Calculate how many possible combinations are there to open the lock...This question here, is question 2, the second part...sorry about the confusion. So, we originally have 10 numbers. 0 an 1 may not be used, so we have 8 numbers, however the code must be even numbered, so we need to reserve one of the evens for the 4th spot, that leaves 7 numbers available... 

First spot is one of 7 numbers, 2nd spot one of 6 numbers, 3rd spot one of 5 numbers and 4th spot, one of 4 numbers..

Thanks for your ijput, I'm looking at that now

1. 2865 more license plates are possible.

2. The number of possible ways is 20.

3. The number of possible values of X + Y is 18.

CM = 6*sqrt(3).

6 C 3 ==20 combinations. Divide them by 2 and you will have: 10 pairs of X + Y

6 P 3 ==120 permutations. Same as above.

(a,b,c) = (8,-1,10)

R ==15  x  2^-(48/16)

R ==15  x  2^-3

R== 1.875 g - what remains of the metal compound after 48 hours.

L=Leya,  H=Hiro,  J=Jane

L =4H

J =2L

L  +  J =468, solve for L, H, J

Use substitution to get 

L =156 - cards that Leya has

H =39 - cards that Hiro has

J =312 - cards that jane has.

Put it in variable form and solve for the variable, then plug it in.

BC = 30, BZ = 16

The answer is 1.8 kg of pears.

x - y = 14.

The smallest distance is 20*sqrt(5)/3.

The area is 40.

The answer is y = -28.

The answer is y = 4x + 15.

The only way for 3 squares to be colored red is if the first, third, and last squares are red. 

This means that the two remaining squares (second and fourth) must be either red or blue. 

So, there are \(2 \times 2 = \color{brown}\boxed{4}\) ways to color the five squares. 

There are 10 ways.

(a) There are 32 ways.

(b) There are 144 ways.

There are 640 possible sequences.

By power of a point, XY = 20.

The answer is 60.