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In the triangle PQR, let X represent the point where angle P and side QR connect, and let Y represent the foot of the perpendicular that runs from X to side PR. The length of XY is  2.25 × √(3) units.

What are triangles?

By drawing straight lines from three non-collinear points, a triangle is a three-sided polygon.

It is a basic geometric shape having several properties and applications in science, technology, engineering, and other fields.

Depending on the size of their angles and side lengths, triangles can be divided into different categories.

Due to the fact that PQ = QR = PR, triangle PQR is an equilateral triangle.

Let's write x as the length of each angle in this triangle. Since the angle P is divided into two equal halves by the angle bisector, the measures of the angles PXQ and QXR are both x/2.

Let's write d to represent XY's length. Trigonometry can be used to determine the length of XY since triangle PXY is a right triangle. Specifically, we have

tan(30) = XY / PY

Since PY = PQ - QY and PQ = QR = 9, we have PY = 9 - QY. Therefore:

tan(30) = XY / (9 - QY)

Solving for XY, we get:

XY = (9 - QY) tan(30)

QY needs to be located. The Pythagorean theorem can be used to determine QY because triangle QYX is also a right triangle:

QY² + XY² = QX²

Triangle QRX being a 30-60-90 triangle gives us:

QX = QR / 2 = 4.5

Therefore:

QY² + XY² = 4.5²

QY² + (9 - QY)² tan²(30) = 4.5²

The result of simplifying and solving for QY is:

QY = 2.25

Inputting this value into the XY expression yields the following result:

XY = (9 - 2.25) tan(30) = 2.25 × √(3)

May 1, 2023
 #1
avatar+141 
+1

71.4% of the students bring an umbrella only.

What is the percentage?

Percentage is a way of expressing a number as a fraction of 100. It is represented by the symbol %. It is a useful way of comparing values and calculating changes over time. 

Let's denote the total number of students in Margo's school by the letter N. We can use a Venn diagram to represent the number of students who bring a raincoat, an umbrella, or both, as shown below:

           RAINCOAT         UMBRELLA

          ________         ________

         |                  |       |                 |

         |                  |       |                 |

         |                  |       |                 |

         |      A         |       |        C       |

         |                  |       |                 |

         |                  |       |                 |

         |________|       |________|

          BOTH (B)         ONLY (D)

 

We know from the problem statement that 50% of the students bring both a raincoat and an umbrella. Therefore, the number of students who bring both is equal to 0.5N.

 

We also know that the total number of umbrellas brought is twice the number of raincoats. Let's denote the number of raincoats brought by the letter A. Then the number of umbrellas brought is equal to 2A.

 

We can use these values to fill in the Venn diagram. The total number of students is N, so the number of students who bring only a raincoat is (A - 0.5N) and the number of students who bring only an umbrella is (2A - 0.5N). The number of students who bring both is 0.5N.

 

To find the percentage of students who bring an umbrella only, we need to divide the number of students who bring only an umbrella by the total number of students and multiply by 100:

 

(2A - 0.5N) / N * 100

We can simplify this expression using the fact that the number of umbrellas brought is twice the number of raincoats:

 

(2A - 0.5N) / N * 100

= (2 * A - 0.5N) / N * 100

= (3A - 0.5N) / N * 100

We can't directly solve for the value of A, but we can use the fact that the sum of the numbers in the Venn diagram adds up to N:

 

A - 0.5N + 0.5N + 2A - 0.5N = N

3.5A - N = N

A = 2N / 7

Substituting this value of A into the expression for the percentage of students who bring an umbrella only, we get:

 

(3A - 0.5N) / N * 100

= (3 * 2N / 7 - 0.5N) / N * 100

= 71.4%

 

Therefore, 71.4% of the students bring an umbrella only.

May 1, 2023
 #2
avatar+141 
+1

Therefore, the side length of the cube is 1/3, as required.

What is tetrahedron?

Four triangular faces make up the three-dimensional shape of a tetrahedron. The foundation of the pyramid is one of the triangles, with the other three triangles joining it.

Let D be the vertex of the cube on face ABC. 

Since the opposite vertex of the cube is at O, we have OD = 1. 

Let the side length of the cube be x.

Consider triangle AOB.

AB² = AO² + OB² = 1 + 1 = 2

Similarly, find that BC² = AC² = 2.

Since ABC is a right triangle with angles A, B, and C being 90° -

sin A = BC / AB = √2 / 2

sin B = AC / AB = √2 / 2

sin C = BC / AC = 1

Consider tetrahedron ABCO. Since AOB, AOC, and BOC are right angles -

∠AOCB = π - ∠AOC - ∠BOC = π/2

∠AOBC = π - ∠AOB - ∠BOC = π/2

∠ABCO = π - ∠AOC - ∠AOB = π/2

So triangles AOC, AOB, and BOC are all right triangles with hypotenuse 1 and angles A, B, and C, respectively. 

Using the sine rule -

sin AOC = AO / OC = 1

sin AOB = sin BOC = BO / OC = 1

Therefore, the areas of triangles AOC, AOB, and BOC are -

Area(AOC) = (1/2) × AO × OC × sin AOC = (1/2) × 1 × 1 × 1 = 1/2

Area(AOB) = Area(BOC) = (1/2) × BO × OC × sin AOB = (1/2) × 1 × 1 × 1 = 1/2

Now, consider triangle AOD.

sin AOD = sin(180° - AOB - AOC) = sin(BOC) = √2 / 2

Using the sine rule -

AD / sin AOD = OD / sin OAD

AD / (√2 / 2) = 1 / x

AD = (√2 / 2) * (1 / x)

The area of triangle AOD is -

Area(AOD) = (1/2) × AD × OD × sin AOD = (1/2) × (√2 / 2) × (1 / x) × 1 × (√2 / 2) = 1 / (2x²)

Now, consider the tetrahedron ABCO. 

The volume of the tetrahedron is -

V = (1/3) × Area(ABC) × OD = (1/3) × (√3 / 4) × 1 = √3 / 12

The volume of the cube is -

V = x³

Since the cube is inscribed in the tetrahedron -

√3 / 12 = x³

So, now there is -

x = 1/3

Therefore, the side length of the cube is 1/3, as required

May 1, 2023

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