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+22

0

37.5% can also be written as 375/1000. If we write it that way the equation becomes,

x/(10000+x)=375/1000

Then we cross multiply,

x/(10000+x)=375/1000 (1000)(x)=(375)(10000+x) 1000x=3750000+375x

Subtract 375x from both sides,

1000x=3750000+375x 625x=3750000

Then divide both sides by 625 to solve for x getting x=6000. Hope that helped.

CyphersumSep 14, 2013

0

An irrational number is a number which can not be represented by a division of two integers.

So -3.14 = -314/100 is a rational number.

GuestSep 14, 2013

0

assuming you have earned the 2/9th's of the 30$ today, you can say that
(2/9) x 30 =
.222 x 30 = 6.67
So today you have earned
$30 + $6.67
Therefore, you need to determine how far away that is from reaching the $100 target
100 - 36.67 = $63.33
You would need to earn $63.33 dollars today to reach $100 total sales

GuestSep 14, 2013

0

the first one is B and D
The second one is A,C and E

GuestSep 14, 2013

+4

0

Hey Danielle, I am literally confuse about solution..
How can you calculate Period Rate 14.55%/12 ? Its yearly rate?

Ranjela4Sep 14, 2013

+4

0

I'll soon reply you with solution of Question..
It sounds interesting question for me..

Ranjela4Sep 14, 2013

0

Actually its 8/5

GuestSep 14, 2013

0

Normal division.
2 : 3

2 is bigger than 3, so we know it must be a number less than 1 (0,xxxx)

Now append a zero to 2:

[1] 20 : 3 = (18 + 2) : 3 = 18/3 + 2/3 = 6 + 2/3

So far we have 0,6xxx

But as you can see, wie have the same division (2/3) again. Now repeat [1]...

GuestSep 14, 2013

0

2 = x
3 100
The 100 represents 100/100 parts of 1, so x is a percent.

200 3x
2 = x
3 100
Now you cross multiply 100*2 and x*3. These values will equal each other, so you now need to write an equation.
200= 3x
3 ~~ 3
you divide each side by 3 and get
66.6% repeating, equal to .6 repeating.
_
.6

GuestSep 14, 2013

+16

0

Now, if I was doing this on a piece of paper, I would want to make sure all the decimals were lined up when solving this. Then I would start to add/subtract the amounts, probably tackling them two at a time. Now that's kind of hard to do on the forum, so I'll just let you know that the answer will be $125.18.

SburbanMathematicianSep 14, 2013

+16

0

5 is the reciprocal.

SburbanMathematicianSep 14, 2013

Sep 13, 2013

+22

0

Since the roots of the polynomial are 1,2, and k, and the lead coefficient is -1 the factors of the polynomial are going to be (-x+1),(x-2), and (x-k).

Therefore f(x)=(-x+1)(x-2)(x-k)

(-x+1)(x-2)(x-k)=-x^3 + (-k+3)x^2 + (3k-2)x + 2k

Dividing this polynomial by (x-3) using synthetic division we get a remainder of 2k-6.

We know that f(x) divided by (x-3) has a remainder of 8. So, 2k-6=8 k=7

If k=7 then f(x)=-x^3+10x^2-23x+14. You can check by dividing this polynomial by (x-3) and seeing if you get a remainder of 8.

Hope that helps.

CyphersumSep 13, 2013

+104

0

-10z ≤ 15 [/(-10)]

z ≥ -3/2

ApfelkuchenSep 13, 2013

+104

0

f(x) = -x ³ + bx ² + cx + d
f(x) = 0 with x ₀ = 0, x ₁ = 1, x ₂ = k

Because of x ₀ we know: d = 0

So we have the equation f(x) = -x ³ + bx ² + cx
f(1) = -(1 ³) + b(1 ²) + c1 = 0 b + c = 1 b = 1-c

Remainder of division is 8, so we conclude:
(-x ³ + bx ² + cx):(x-3) = -x ² + x(b-3) + (c + 3(b - 3)) + 3(c + 3(b - 3))/(x-3)

3(c + 3(b - 3)) = 8 = 3c + 9b - 27 3c + 9b = 35

Insert b = 1-c into the last equation and solve for c:
3c + 9(1-c) = 35 = 3c + 9 - 9c = 9 - 6c c = -26/6 = -13/3

Insert c = -13/3 into f(1):
b = 1-(-13/3) = 16/3

So we have the final equation: f(x) = -x ³ + (16x ²)/3 - 13x/3 = -x(x ² - 16x/3 + 13/3)

Now just solve x ² - 16x/3 + 13/3 = 0

[input]x^2 - 16x/3 + 13/3 = 0[/input]

Edit: Misread. Actual roots are x ₀ = 1, x ₁ = 2, x ₂ = k
So we have:
f(1) = -(1 ³) + b(1 ²) + c1 + d = 0 b + c + d = 1
f(2) = -(2 ³) + b(2 ²) + 2c + d = -8 + 4b + 2c + d = 0 4b + 2c + d = 8
f(k) = -(k ³) + b(k ²) + kc + d = 0

So the actual division would result into:
(-x ³ + bx ² + cx + d):(x-3) = -x ² + x(b-3) + (c + 3(b - 3)) + (3(c + 3(b - 3)) + d)/(x-3)

(3(c + 3(b - 3)) + d) = 8 9b + 3c + d = 35

Gauss-Jordan:
[1] 1 1 1 1
[2] 4 2 1 8
[3] 9 3 1 35

[2] - [1], [3] - [1]
[1] 1 1 1 1
[2] 3 1 0 7
[3] 8 2 0 34

[3] - 2x[2]
[1] 1 1 1 1
[2] 3 1 0 7
[3] 2 0 0 20 2b = 20 b = 10

Insert b = 10 into [2]
3*10 + c = 7 c = 7-30 = -23

Insert b = 10 and c = -23 into [1]
10 - 23 + d = 1 d = 14

Final equation f(x) = -x ³ + 10x ² - 23x + 14

ApfelkuchenSep 13, 2013

+259

0

x-o.2x+o.o7(x-0.2x)=73.53 => (x - 0.2x)(1 + 0.07) = 73.53 => (x - 0.2x)*1.07 = 73.53 => 0.8x*1.07 = 73.53 => 0.856x = 73.53 => 856x = 73530 => x = 36765/428

solve(x-(0.2x)+0.07(x-(0.2x))=73.53,x)

scrutinizerSep 13, 2013

0

GuestSep 13, 2013

0

10 dishes x 8 veg. x ( 13 x 12 ) desserts = multiply yourself

GuestSep 13, 2013

0

Yeah, thanks. I know that.
But the problem is I don't know what it means by two different classifications.

GuestSep 13, 2013

0

tan(a) = O/A
With a = 30° and O = 4 feet

A = O/tan(a) = 4[feet]/tan(30°) =
[input]4[feet]/tan(30)[/input]

GuestSep 13, 2013

0

Your characteristics of each set are:
Z: A set of integers. So natural numbers with a sign (negative and positive) and zero. eg. -x, 0, x
Q: A set of rational numbers. A rational number is a division of two integers like 3/5

So Z ∪ Q = { 16 , -8 , 0 , -1/9 , 6.4 , 2 , sqrt(2.89) } if
Z = {16, -8, 0, 2} and
Q = {64/4, -8, 0, -1/9, 6.4, sqrt(4), sqrt(2.89)}

{ 64/4 , -8 , 0 , -1/9 , 6.4 , square root(4) , square root(-9) , square root(2.89) , cube root(144) } = Z ∪ Q ∪ R

With R being a set of real numbers R = {64/4 , -8 , 0 , -1/9 , 6.4 , square root(4) , square root(-9) , square root(2.89) , cube root(144)}

GuestSep 13, 2013

0

Someone help please...

GuestSep 13, 2013

0

There is a thing called Wikipedia.
http://en.wikipedia.org/wiki/Cramer's_rule

GuestSep 13, 2013

0

Oops...then I'm wrong.
ThANkS, Guest,

GuestSep 13, 2013

0

GuestSep 13, 2013

0

Normally -25^2 = -(25^2)

GuestSep 13, 2013

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