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CPhill!i cant understand your answer!is there any other way?

x + 3y = 13     ...(1)

-3x + 2y = 27  ...(2)

Rearrange (1)  as  x = 13 - 3y  ...(3)

Put this into equation (2)

-3*(13 - 3y) + 2y = 27

-39 + 9y + 2y = 27

-39 + 11y = 27

Add 39 to both sides

11y = 66

Divide both sides by 11

y = 6

Put this into equation (3)

x = 13 - 3*6

x = -5

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The lowest common multiple of 2, 4 and 5 is 20, so the required numbers must be divisible by 20.

I'm sure you can now work out which ones they are.

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The subsets are 

Φ  (i.e. the empty set)

{A}, {B}, {C}

{A,B}, {A,C}, {B, C}

9x² + 16y² = 144

Subtract 9x2 from both sides

16y² = 144 - 9x²

Divide both sides by 16

y² = (144 - 9x²)/16

Take the square root of both sides. Since there are two possibilities we create two functions in doing so:

y = (144 - 9x²)^1/2/4  and  y = -(144 - 9x²)^1/2/4

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if power = P, current = I and resistance = R then

P = I²R   so  R = P/I²

Here  R = 75/1.5 = 50 Ω

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Yes, just type abs(...)   (replacing the ... by the expression for which you want the absolute value).

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320 

It is how much of the changes gone by and so you take the slope hope this helps

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   Slope- intercept form of a line: y = mx + b. Let's examine how to graph one of these equations: y = 2x + 1. This is in  slope- intercept form, so we know that the number in front of x is the  slope (2), and that 1 is the y- intercept. i hope this helps 

   
   
   
   

dear math quit asking me to find your ex its never coming back thts how i feel about math

Thank you, I am glad that you like it.  :)

1000000*5*19-189

you can do this on the calc on the home page.  :)

NOT ME  

everyone does

4/7x - 2/7y = 6/7, (1a)    and  2/5y - 3/5x = -6/5   (2a)

Multiply both sides of (1a) by 7  and    multiply both sides of (2a) by 5

4x-2y=6    (1b)         and        2y-3x=-6     (2b)

-3x+2y=-6    (2b)

(1a)+(2b)

4x-3x-2y+2y=6+-6

x=0

Sub into (1b)

-3*0+2y=-6

0+2y=-6

y=-3

SO         x=0,     y=-3

It's Simp. Fraction form. 18/107 or are trying to find the decimal?

50-30=20

20/2=10

The answer is 10

2Reels + 5Rods = 195

4Reels + 3Rods = 131

If you multiply the first equation by -2:  -4Reels - 10Rods = -390

Leave the second equation alone:           4Reels +  3Rods =  131

                                                          -----------------------------

Now add down the columns:                                -7Rods = -259

Divide by -7:                                                          Rods = 37

If 2Reels + 5Rods = 195  and there were 37 Rods, then:    2Reels + 5(37) = 195

                                                                                      2Reels + 185    = 195

Subtract 185:                                                                               2Reels = 10

                                                                                                     Reels = 5

Check:  2Reels + 5Rods = 197   --->  2(5) + 5(37)  =  10 + 185  =  195  check!

            4Reels + 3Rods = 131  --->  4(5) + 3(37)  =  20 + 111  =  131  check!

Once you have two equations in two unknowns, look to see if you can get rid of one of the variables by adding down; then multiply one or both equations so the coefficients are negatives of each other.

x^2 means x²  but on the forum a lot of people don't know that so sometimes we will interprete x2 as x^2  

$$\dfrac{\frac{x^2}{4}+1}{\frac{x}{2}+1}\\\\\\
=\dfrac{\frac{x^2+4}{4}}{\frac{x+2}{2}}\\\\\\
=\frac{x^2+4}{4}\div \frac{x+2}{2}\\\\
=\frac{x^2+4}{4}\times \frac{2}{x+2}\\\\
=\frac{x^2+4}{2(x+2)}$$

85 - 56/n = 78        multiply everything by n

85n - 56 = 78n       rearrange

85n - 78n = 56

7n = 56       divide by 7 on both sides

n = 8

Let x be smaller number and y the larger...so...

x + y = 89    and

3x - 71 = y

Using the second equation to substitute for y in the first, we have

x + (3x -71) = 89   simplify

4x - 71 = 89      add 71 to both sides

4x = 160   divide by 4 on both sides

x = 40      so      40 + y = 89     subtract 40 from bth sides.....so......y = 49

Seriously ?????

I'll get to your problem just as soon as I finish tracking down The Golden Fleece......