All Answers 358108 Answers

I don't know how to do this 

BUT

Well the probablility of getting double 2 or double 6 is 2/36 = 1/18

So he has 1/18 chance of winning $15

and a 17/18 chance of losing $5

So maybe

$$\left({\frac{{\mathtt{1}}}{{\mathtt{18}}}}{\mathtt{\,\times\,}}{\mathtt{15}}\right){\mathtt{\,-\,}}\left({\frac{{\mathtt{17}}}{{\mathtt{18}}}}{\mathtt{\,\times\,}}{\mathtt{5}}\right) = {\mathtt{\,-\,}}{\frac{{\mathtt{35}}}{{\mathtt{9}}}} = -{\mathtt{3.888\: \!888\: \!888\: \!888\: \!888\: \!9}}$$

So the person should expect to lose $3.89

This probably is not correct.  I am totally guessing.  Sorry.

If you find out how it is done please let us know.  If I find out I will post it on this thread.  

Someone else probably knows how to do it. I shall ask around.  :))

I am really not sure how this works but I think

$$\left({\frac{{\mathtt{1}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{10}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{5}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{1}}\right) = {\frac{{\mathtt{25}}}{{\mathtt{8}}}} = {\mathtt{3.125}}$$

So I think the expected value of the draw is      $3.125    or     $3.13    rounded of to the nearest cent.

NO it is not 

$$\\-2>-2\quad false\\\\
-2\ge-2\quad true\\$$

$$\\\sqrt[3]{-27x^9y^{12}}\\\\
=(-27)^{1/3}(x^9)^{1/3}(y^{12})^{1/3}\\\\
=-3x^3y^4$$

8(-3/2x+6)=-9(4/3x-8) 

$$\begin{array}{rll}
8(\frac{-3x}{2}+6)&=&-9(\frac{4x}{3}-8) \\\\
\frac{-3*8x}{2}+6*8&=&\frac{-9*4x}{3}--9*8 \\\\
-12x+48&=&-12x+72 \\\\
48&=&72 \\\\
\end{array}\\\\
No Solution$$

Anything divided by zero is undefined - you cannot divide by 0 

Here is more discussion of this

Okay Takahiro,

You were in Guizhou.      Where abouts in Guizhou were you?    

I noticed Takahiro,

When I saw you on today I was really pleased.     

I should have welcomed you back.

Sorry.

I am very pleased that you are back though.

Where abouts in China were you?  That sounds really interesting.  :)))   

Good point 7up - i didn't think of that.   LOL

10(1/5a+4)<10(1/5a-3)

$$\\10(\frac{a}{5}+4)<10(\frac{a}{5}-3)\\$$

divide both sides by 10

$$\frac{a}{5}+4<\frac{a}{5}-3\\\\$$

subtract a/5 from both sides

4<-3

this is NEVER true

No solution.

Perhaps this is not the question that you intended?  Perhaps you needed to use more brackets?

$$$a+1\:=\:\sqrt{b+1}$$$

What do you want me to do with this ?

$${\frac{{\mathtt{46}}}{{\mathtt{7.36}}}}{\mathtt{\,\times\,}}{\mathtt{100}} = {\mathtt{625}}$$

The answer is 625%      (not 6.25)

Alan has pointed out that my answer is not completely correct - Thank you Alan

I always like people to make me aware when I make mistakes.  :))

I have now fixed the mistake.

$$\\x+10\ge 10\\
x\ge0\\\\
x+10\le9\\
x\le -1\\\\
so\\
x\le -1 \quad and \quad x\ge 0\\\\$$

-------------------------------------------------------

The Intersection is an empty set

x cannot be less than -1 and greater than 0 both at the same time!

 ------------------------------------------------------

The union is   $$x\le -1 \quad and \quad x\ge 0$$

I didn't got it as well as I can >< 

may be there are some information I missed

I think that you mean

asin(7.6/9.8)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{7.6}}}{{\mathtt{9.8}}}}\right)} = {\mathtt{50.851\: \!312\: \!357\: \!747^{\circ}}}$$

I'd do it more simple mathematician

2x+2y=4

If x=0 then 2y=4 so y=2    (0,2)

If y=0 then 2x=4 so x=2     (2,0)

plot the points and draw the line through them.

Yes, you just need to know 2 points that are on the line.

If you have the y intercept and one other point then you can find the gradient and use the formula

y=mx+b

where m is the gradient and b is th y intercept

(7/2)*(5/2)=35/4 = 8 and 3/4

Work is a form of energy transfer.  The energy transferred to the water by the pump is used, first, to raise the water to the surface (potential energy) and then any remaining energy that has been transferred appears as kinetic energy as the water shoots out (presumably from a hose) at the top.

Not sure if this answers your question!

.

Just put it straight into the home page calc as it is. 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{28}}^\circ\right)}{\mathtt{\,-\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{28}}^\circ\right)} = {\mathtt{0.413\: \!476\: \!030\: \!073}}$$

$$You\; mean\; like\\

\sqrt{x}=x^{1/2}\\

\sqrt[3]{x}=x^{1/3}\\$$

Nice , thank you 

Yes Rosala,

She is cute and yummy LOL :)))

In the first on I just got rid of the sqrtx in the denominator of the numerator.

And in the last one I expanded the bottom and collected the y^2 terms.

That is all.  :)