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It is incorrect.   

a)  18nCr3 · (0.2)^4 · (0.8)^(19 - 4)  =  0.046

b)  19nCr3 · (0.2)^4 · (0.8)^(20 - 4)  =  0.044

c)  20nCr3 · (0.2)^4 · (0.8)^(21 - 4)  =  0.041

The only way that the product operates is if all of the individual circuits work.

The probabilty that any circuit works is 0.99.

The probability that all 40 circuits works is (0.99)^40  =  0.669

If the problem is:  (y² - 11y + 24) / (y² - 13y + 40)

     =  [ (y - 8)(y - 3) ] / [ (y - 8)(y - 5) ]

     =  (y - 3) / (y - 5)

179 087 875 / 1 000 000 000

which can be reduced by dividing both the numerator and the denominator by 5 (three times).

Because so few pairs are given, there can be many answers; one answer is:  1.5x² + 2.5x + 5.

There is a neat way to determine if the set of values is quadratic and how to find the formula. If your problems are quadratic, post back and we can tell you how to find the formula.

a)  n = number in the batch, so n = 50

     p = probability of non-conformance = 5/50  =  1/10

b)  P(X≤2)  =  P(X=0) + P(X=1) + P(X=2)

                 =  50nCr0·(1/10)^0·(9/10)·50 + 50nCr1·(1/10)^1·(9/10)·49 + 50nCr2·(1/10)^2·(9/10)·48  

                  =  0.112

c)  P(X≥49)  =   P(X=49) + P(X=50)

                  =  50nCr49·(1/10)^49·(9/10)·1 + 50nCr50·(1/10)^50·(9/10)·0

                  =  $.51 x 10^-48

Let  L  represent the length of the longer leg.

Then  L - 8  represents the length of the shorter leg and  L + 8  represents the length of the longer leg.

Using the Pythagorean theorem:  (L)² + (L - 8)²  =  (L + 8)²

Multiplying out:                         L²  + L² - 16L + 64  =  L² + 16L + 64

Subtract 64 from both sides:      L²  + L² - 16L  =  L² + 16L

Subtract L² from both sides:      L² - 16L  =  16L

Subtract 16L from both sides:    L² - 32L  =  0

Factor:                                     L(L - 32)  =  0

Either     L = 0  (impossible)     or     L - 32  = 0     --->     L  =  32

If  L = 32,  then  L - 8  = 24     and     L + 8 = 40 

Let  L  represent length.

Let W  represent width.

Since the length is 6 yd longer than its width:  L  =  6 + W

The formula for perimeter:  P  =  2L + 2W   

Since the perimeter is 44 yds:     44  =  2L + 2W

Substituting:                             44  =  2(6 + W) + 2W

                                                44  =  12 + 2W + 2W

                                                44  =  12 + 4W

                                                32  =  4W

                                                 W  =  8 yds

Since  L  =  6 + W  --->  L  =  14 yds

Let L represent length     W represent width     and     A represent area.

Since the length is 3 ft more than twice the width, we can write this as     L = 3 + 2W

The formula for the area of a rectangle is     A = L x W

Since the area is 77,     77  =  L x W

Substituting:               77  =  (3 + 2W) x W

Multiplying out:           77  =  3W + 2W²

Rewriting:                  2W² + 3W  =  77

Subtracting:               2W² + 3W - 77  =  0

Factoring:                   (2W - 11)(W + 7)  =  0

So, either  2W - 11 = 0   --->  2W  =  11   --->   W = 5.5 ft

           or  W + 7  =  0   --->   W  =  -7    (not possible)

Since  L  =  3 + 2W   --->   L  =  3 + 2(5.5)  =  14 ft

Try Google, you can find a lot of things there ...

Poisson Distribution:  P(x, μ)  =  (e^-μ)(μ^x) / x!

Average number hitting the disk  =  0.1 x 100  =  10

With  μ - 10  and  x = 12:

      P(12, 10)  =  (e^-10)(10^12) / 12!   =   0.095  (approximately)

 thx m8

a)  The probability of randomly choosing someone with blood type O-negative is 12/200.

     The probability of randomly choosing someone without blood type O-negative is 188/200.

     The probability of randomly choosing three type-O and seventeen non-type-O is:

          (12/200)^3 x (188/200)^17 x the number of ways that this can occur.

     Since the order in which these are chosen is unimportant, it is a combination, so we been the combination of           choosing three out of twenty:  20nCr3

     Our probabiltiy has become:  20nCr3 x (12/200)^3 x (188/200)^17  =  0.086   (approx.)

b)  "At least one" means "one or more", so the easiest way is to find the probability that none have type O-              negative blood and subtract this from 1.000.

     The probability that none has type O-negative blood is:  20nCr0 x (12/200)^0 x (188/200)^20  =  0.290

     Subtracting this from 1.000 gives a probability of 0.710.

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There are 6 · 6 outcomes for tossing two dice.

Of these ways there are 6 ways to get a sum of 7:  1&6, 2&5, 3&4, 4&3, 5&2, and 6&1.

There are 5 ways to get a sum of 6:  1&5, 2&4, 3&3, 4&2, and 5&1.

The probability of getting a 7 from a roll of two dice is 6/36.    (Let me call this outcome A.)

The probability of getting a 6 from a roll of two dice is 5/36.    (Let me call this outcome B.)

The probability of getting any other outcome is 25/36.            (Let me call this outcome X.)

The number of ways to arrange AABBXXXXXX is 10! / [ 2! · 2! · 6! ]  =  1260 ways 

So the probability is   1260 · (6/36)² · (5/36)² · (25/36)^6  =  0.0198 (approximately) 

We just need to evaluate

cos^-1 [ ( 3√3  + 4 ) / 10 ] = about 23.13 degrees.....this could also be a 4th quadrant angle = [ 360 - 23.13 ] degrees = 336.87 degrees

if a=-2 b=4 and c=4 what is the value to the following question 2ab-c2

We have

2(-2)(4) - (4)(2) =

(-4)(4) - 8 =

-16 - 8 =

-24

For the first, remember that  ( a^m ) ⁿ  =   a ^{m x n}

So we have

(2 ³ ) ²  = 2 ^{3 x 2} =   2 ⁶  = 64

For the second, remember the rule that  aⁿ x a^m   =  a^m+n

So...... 2³ x 2² = 2³⁺² = 2⁵  = 32

Does that help ??

the first one : u multiplie 3 by 2

the second one : u add 3 and 2

  please explain how  thx :)

1st : 2^6

2nd : 2^5

1.95×10−4M/s×1.17×10−4 M/s

This is just

(1.95 x 1.17) x (10^-4 x 10^-4)     

So we have

2.2815 x 10^-8

 thx bro :)