Thanks Chris, yes these odds are dreadful!
Beats me - i havent even thought about it and if i did it may not help much. :)
I just reproduced what was there.
Shouldn't each of the individual factors in your product have this form?
(n-sub-i C k-sub-i) · (n minus n-sub-i C k minus k-sub-i) / n C k
thank you lots
Yes...... putting a "negative" into "-x" would result in a positive!!!......glad I could be a "lifesaver"....!!!
Try watching and learning form this
http://www.youtube.com/watch?v=do_IbHId2Os
As far as notation goes I think that this is what you are after?
$$P(A)=\displaystyle \lim_{i=1}^X}\;\;\frac{^{n{_i}}C_{k_i}}{^nC_k}$$
this is written in LaTex. I opened the LaTex formula button and typed in
P(A)=\displaystyle \lim_{i=1}^X}\;\;\frac{^{n{_i}}C_{k_i}}{^nC_k}
This is all too much for me at the moment but I would try using known quatities of things.
If I could work out what to do for the known quatities then I would extrapolate to get a formula for the unknown quanities.
I am not saying it will necessarily work but that is how I would try to attack the problem.
good luck
You can get the anser to that from any calculator.
NO !!!!!
YOU CAN ONLY FIND THE ARC SINE OR ARC COS (INVERSE SINE OR INVERSE COS)
OF NUMBERS (RATIOS) BETWEEN -1 AND 1 INCLUSIVE
Try watching this video
http://www.youtube.com/watch?v=rR95Cbcjzus
NO
think about it.
In a right angled triangle cos= adjacent / hypotenuse
the hypotenuse is the longest side so this fraction must be less than 1
When dealing with angles that are not acute
$$-1\le cos\theta\le1$$
Not much since it is virtual.
$$\\\cos180^0=-1\\\\ \int\;cosx\;dx=\;sin(x)+c\\\\$$
Look through this post
http://web2.0calc.com/questions/indices-especially-negative-indices
(y^3)^3 = y^9
Here's the graph with the solution point......https://www.desmos.com/calculator/sjmoeapakx
If you have 3^-2, this means that you need to take the reciprocal; make it 1 / 3^2 = 1/9.
(When you take the reciprocal, turn the negative exponent into a positive exponent.)
So, 4^-3 means 1 / 4^3 = 1/64.
Etc.
Just what is the question?
Since g( x ) = f( 2x ) ---> g( x - 4 ) = f( 2(x - 4) ) = f( 2x - 8 )
Since h( x ) = g( x - 4 ) ---> h( x ) = f( 2x - 8 ) = f( 2(x - 4) )
Multiply the number of glasses of water you drink in a day
times the number of days in a year
times the number of years.
The coefficients to be used are 1 4 6 4 1
So: 1(2x)^4 + 4(2x)^3(-y)^1 + 6(2x)^2(-y)^2 + 4(2x)^1(-y)^3 + (-y)^4
What did I do wrong?