All Answers 358087 Answers

Thanks Alan,

Much appreciated :)

could Geno or someone else talk me through this some more.  Why isn't it 0?

$$\sqrt{-54}\\
=\sqrt{-1*9*6}\\
=\sqrt{-1}*\sqrt{9}*\sqrt{6}\\
=i*3*\sqrt{6}\\
=3\sqrt{6}\;i\\$$

If you mean for trig - you press the [2nd] button and then use atan or acos or asin.

arc trig is the same as inverse trig.

1.24250*10^5

20c0(0.5)^0(0.5)^20=1*1*0.5^20

$${{\mathtt{0.5}}}^{{\mathtt{20}}} = {\mathtt{0.000\: \!000\: \!953\: \!674\: \!316\: \!4}}$$    or

$${{\mathtt{2}}}^{{\mathtt{20}}} = {\mathtt{1\,048\,576}}$$

$$\frac{1}{1048576}$$

120/252 is just 10/21 or 0.47619 simplified

The slope is represented by m, not x.

Oh ok sorry

∞·0 is an "indeterminate" expression, meaning that it can have one of many values.

In calculus, you look at how this result was created; looking at how it was created can then lead to a value for that problem. The value might be 0, it might be ∞, or it might be 7 (or any other number).

Anon correct, 10 in base 4

-1000 = 5t(6.73 - t)

First we distribute 5t using the distributitive property:

-1000 = 5t(6.73) + 5t(t)

So we have:

-1000 = 33.65t + 5t

We can then add together the two t's:

-1000 = 38.65t

Now we divide both sides by 38.65 to fully isolate t:

-1000/38.65 = 38.65t/38.65

$${\mathtt{\,-\,}}{\frac{{\mathtt{1\,000}}}{{\mathtt{38.65}}}} = -{\mathtt{25.873\: \!221\: \!216\: \!041\: \!397\: \!2}}$$=t

Yes anon! 10 in base 4.

But in base 10, our counting system, it's 4.

Actually yeah, he totally right. 

$$\mathrm{If\ you \ select\ an\ appropriate\ base\ it\ becomes\ valid:}

\textcolor[rgb]{0,0,1}{9_{(ten)}\ +\ 10_{(ten)}\ =\ 21_{(nine)}}$$

I might be incorrect but

2 + 2 is 10 in base four

I meant something like this:

      $${\mathtt{0}}$$ $${\mathtt{25}}$$     

$${\mathtt{5}}$$$${\sqrt{{\mathtt{125}}}}$$

    - $${\mathtt{10}}$$ |

       __ ↓

         $${\mathtt{25}}$$

       - $${\mathtt{25}}$$

         ___

          $${\mathtt{0}}$$ $${\mathtt{0}}$$

For explanation of long division, not calculation.

What long division?

Math formual is easier to use than LaTex  but it does not do as many things.

If you want a fraction or a poser written properly just open Math formual and write it in there.

ex

3/4*6^2

I'll enter is in [Math Formula] just as it is ( and press enter and ok)

$${\frac{{\mathtt{3}}}{{\mathtt{4}}}}{\mathtt{\,\times\,}}{{\mathtt{6}}}^{{\mathtt{2}}}$$       and this is the output

---------------------------------------------------

Now if I want the same thing using LaTex I would enter

\frac{3}{4}\times 6^2

and this would be the result

$$\frac{3}{4}\times 6^2$$

----------------------------------------------------

It would be great is you learn bot hthese tools.

Familiarise yourself with Math Formula first because it is easy.

Thanks for the tip.

Melody how do you do the long division bracket with Math Formula or LaTeX Formula?

First let me test the rule:

$${\mathtt{\,-\,}}{\mathtt{0.25}}{\mathtt{\,\times\,}}\left(-{\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{5}} = {\mathtt{6}}$$

$${\mathtt{\,-\,}}{\mathtt{0.25}}{\mathtt{\,\times\,}}\left({\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{5}} = {\mathtt{4}}$$

$${\mathtt{\,-\,}}{\mathtt{0.25}}{\mathtt{\,\times\,}}\left({\mathtt{8}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{5}} = {\mathtt{3}}$$

$${\mathtt{\,-\,}}{\mathtt{0.25}}{\mathtt{\,\times\,}}\left(-{\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{5}} = {\mathtt{6}}$$

It looks like Melody is accurate.

$$\\Is\;\; 2-(((2*x^2)/y^2))$ the same as $((2-(2*x^2))/y^2)\\\\
1st=2-(\frac{2x^2}{y^2})=\frac{2y^2-2x^2}{y^2}\\\\
2nd=\frac{2-2x^2}{y^2}$$

So you can see that they are different.

thank you guys sooo much got er' down! thanks again!

If geno3141 is correct, wouldn't it simplify further to y  =  (-1/4)x + 11?