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$${\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{14}}{\mathtt{\,\times\,}}{\mathtt{9}} = {\mathtt{1\,890}}$$

Just multiply all three numbers together......the answer will be in cubic inches

7x^(1/3)-x(-2/3)=0    factor

x^(-2/3) (7x- 1) = 0

The first factor is never 0

For the second one, we have

7x - 1  = 0

Add 1 to both sides

7x = 1    divide both sides by 7

x = 1/ 7 = about .1428

Let y = x^1/3, then your equation becomes 

7y - 1/y² = 0  (I've assumed your equation is meant to be 7x^1/3 - x^-2/3 = 0)

Multiply through by y²

7y³ - 1 = 0

so

y³ = 1/7

But y³ = x so x = 1/7

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This is an identity.

LHS

1 - csc(x)*sin³(x) → 1 - sin³(x)/sin(x) → 1- sin²(x) → cos²(x)

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Use the calculator on the homepage....

x^(-4/3)-x^(-2/3)-8=0   let u = x^(-2/3)   then we have

u^2 - u -  8  = 0          add 8 to both sides

u^2 - u    =  8             complete the square on both sides

u^2 -  u  + 1/4  = 8.25        factor

(u - 1/2)^2  = 8.25              take both roots

u - 1/2 = ±√8.25                   add 1/2 to both sides

u = ±√8.25 + 1/2

So u = √8.25 + 1/2   or  u = -√8.25 + 1/2

Then, back-substituting, we have

x^(-2/3) = √8.25 + 1/2    raise both sides to the (-3) power

x*2 = (√8.25 + 1/2)^(-3) 

Take both roots

x = ±√((√8.25 + 1/2)^(-3))  = ±(√8.25 + 1/2)^(-3/2) = about ± .161

The other solution, u = -√8.25 + 1/2   leads to a non-real answer

Thanks SPIRIT!

DUDE HAT JUST TOUCHED MY HEART

its the konami code, represented as on the number pad of a keyboard, 88 up up, 22 down down, 46 left right 46 left right B A start

$${\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{8}}}}$$

$${\frac{\left({\mathtt{32}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)}{{\mathtt{40}}}}$$

$${\frac{{\mathtt{37}}}{{\mathtt{40}}}}$$

I assume we have this

1-csc (x) sin^3 (x)=cos^2x     and we'd like to show that it's an identity.....working on the ledt, we have

1 - (i1/ sin x)sin^3x =

1 - sin^2 x  =

cos^2x      which is equal to the right side

$${\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{2}}{i}\right)}^{{\mathtt{2}}}$$

$${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$$

-6=2x / 7     multiply both sides by 7

-42 = 2x     divide both sides by 2

-21 = x

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{y, x}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{y}}={\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{y}}={\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}={\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}={\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\\
{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}={\mathtt{5}}\\
{\mathtt{x}}={\mathtt{1}}\end{array}\right)}$$

3.23 hours

$${\mathtt{0.25}}{\mathtt{\,\times\,}}{\mathtt{100}} = {\mathtt{25}}$$

$0.25

please round to the nearest hundred!! im stumped

If you want the result in fraction form, express both fractions over a common denominator:

4/5 = 4*8/(5*8) = 32/40

and

1/8 = 1*5/(8*5) = 5/40

Now you have 4/5 + 1/8 = 32/40 + 5/40 = 37/40

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Actually CPhill it does look a lot like one type of a secret code..... I know some secret codes I have notebook full of secret codes I learned!

If y = 2x - 3 and y = -3x + 2 then:

2x - 3 = -3x + 2

Add 3x to both sides:

5x - 3 = 2

Add 3 to both sides

5x = 5

Divide both sides by 5

x = 1

Put this value back into y = 2x - 3 to get

y = 2*1 - 3

or y = -1

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