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The triangle inequality states that for any triangle with sides of length a, b, and c, $$a+b>c$$, $$a+c>b$$, and $$b+c>a$$. If we call the unknown side x, we know that $$22+x>40$$ Therefore, the only possible solution is x = 20.

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The sum of any three angles in a triangle = 180

Just sum each of the choices......any sum that doesn't equal 180 is out of the club...!!!

It can't be the last two because

9 + 2 < 15

And

3 + 5  is not greater than 8   (this choice produces a "degenerate" triangle....one with "0" area)

Only the first choice is correct

Furballs ahoy!  You can't fit that many in your house without k*****g a couple unintentionally!

ok than thank you

Originally, we have ....(2/5) (4/9)

Let's look at each option

a)  (5/5) x (4/9)  = 20/ 45

b)  (4/5) x (5/9)  = 20/45

c)  (3/5) x (6/9)  = 18 / 45

d) (2/5) x (7/9)  = 14 / 45

Notice that the last option minimizes the chances of a winner....!!!!

so which one would it be?

This is known as the "Triangle Inequality"...for our purposes here.....it says that the sum of any two sides of a triangle  is greater than the remaining side.....

Knowing this......see if you can figure this out.....

Hint......the second choice is no good because  4 + 6 < 12.....!!!

Well get a piece a paper a ruler and a pencil now try making a triangle with all four.....

All could!  Depends on what kind of triangle

to conver 2/5 in to a decimal isto divdive it and you well get 0.4 when you want it as a percent you move the demacial tothe left and you get 40percent

2/3y=18   multiply both sides by 3/2

y = (3/2)*(18)    simplify

y = 27

What are the choices???

1+1 eqaul to wo because say u have one cat and you get a nother cat and when you count all of your cat you well see that you got 2 cat

The area of the "large" rectangle is given by

(2 + 3 + 2 + 3) * (6)  = 

(5 + 5 ) * (6)  =

(10) * (6)  = 60 cm ^2

And the area of the two small squares is (2 * 2)  = 4 cm^2

So....the total area is  (60 + 4) in^2   = 64 cm^2

thanks man! hope i get it right this time! :)

x=0

zero                                                           

The base is  (10 in )^2   = 100 in^2

There are 4 triangles each having an area of (1/2)(10)(3) = 15 in^2

So 4 times this is  4 (15 in^2) = 60 in^2

So....the total surface area = (100 + 60) in^2   = 160 in^2

Triangular prism.....!!!    ...   both bases are triangles and the lateral sides are parallel....!!!

Correct .....!!!

Substitute -2 for x and  3 for y in the equation...so we have

3(-2)  + 5(3)  =   9   ???

Is this true???....If so, then (-2, 3) is a solution.....!!!!

3(-2)+5(3)=9

-6+15=9

9=9 it is a solution

Here's another way to do this....

We want to draw one white ball from nine in the first urn....and there are 18 ways to choose one ball from the first urn

Then, we want to draw one white ball from the second urn......and there are 11 ways to choose a ball from the second urn

So we have......

C(9, 1)/ C(18,1)  x  C(8,1) / C(11, 1)  =

( 9 / 18 ) x ( 8  / 11) =

(1 /2 ) x (8 / 11) =

8 / 22 =

4 / 11 =

about  36.36%