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b^2 + b^2= 2b^2

Now if it was b^2 * b^2 = b^(2+2) = b^4

Hope this helped.

Thank You So Much!!!

b^2+b^2=2b^2

$${{\mathtt{b}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{b}}}^{{\mathtt{4}}}$$

3y-5y=1-14

-2y=-13

y=13/2

b2= bxb

The answer???

Sorry but I don't know that. :/

Algebra is equations and the questions involve letters such as x and y. For example:

2x+1=11

OR

3y+14=5y+1

Hope this helped :)

2/3 * x = 22

22/(2/3) = x

22*3/2 = x

66/2 = x

33 = x

is that it?

Now we use the calculator to solve this quickly.

12556/632

=19.8670886075949367

then short the answer for 2 decimal nums.

so that answer is 19.87//

-(3 + p) (-p)

-(-3p - p^2)

3p +p^2

56 -8[(5 +40 -12)/20]

56 -8(33/20)

56 -66/5

(280 - 66)/5

114/5

22.8//

I think this is a simpy quiz. but are sure that quiz is true?????????????

4x + 3 +5x +y

4x +5x +y +3

9x +y + 3 this is the answer for ur easy quiz......

(x+9)/3 = 8

(x+9)    = 8*3

(x+9)    = 24

x          = 24 -9

x          = 15

x =15 .It is the answer for x

(x-2)^2 = (2x-7)^2

x^2-4x + 4 =4x^2 -28x +49

24x -45 =3x^2

3x^2 -24x + 45 =0

x^2 -8x +15 =0

(x -3) (x-5) =0

x -3=0 or x-5 =0

x=3     or  x=5

on that time, x has two answers. so that both them are suitable to value of x

maybe............

the answer is 35 over 21  when you divide 2 fractions u flip one of the fractions upside down and multiply them so i did 7/3 times 5/7 = 35/21

Ok I finished my earlier post.    :)

yup obvs haha thanks

(x - 1)² = (2x + 7)² 

Take square root of both sides.  There are two possibilities:

1.    x - 1 = 2x + 7    so  x = -8

2.    x - 1 = -(2x + 7)  so  x - 1 = -2x - 7  so  3x = -6  so x = -2

.

Don't worry Rosala, your answer was correct.

I just want people to think about things a bit.  That is all.  :)

You make it look kinda hard anon ;)

$$\\0=6x^2-18x\\\\
0=6x(x-3)\\\\
x=0\;\;or\;\;x-3=0\\\\
x=0\;\;or\;\;x=3\\\\$$

You snuck in again when I wasn't looking.  lol. 

So, are you happy with my answer ?

it was a simultaneous equation with a quadratic and yh it is an 1.6x lol

$${\mathtt{0}} = {\mathtt{\,-\,}}{\frac{{\mathtt{P}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{or}}{\mathtt{\,-\,}}{\sqrt{{\left({\frac{{\mathtt{p}}}{{\mathtt{2}}}}\right)}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{q}}}}$$   where p=b and q=c when a=1 in the general form of a quadratic equation 0=ax^2+bx+c. So first divide the right part of your equation so that the constant in front of x^2 equals 1 and then apply the given formula above.