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 -38-26.5-42 in inches

(no comment) lol

If you are looking for K then: K=0.5

Thanks, GUH  !!!

Very nice, Melody.....maybe one day I'll catch on to probabiity.....but, it's not probable...!!!!

The number 780000000000 can be written as 7.80 × 10¹¹ in scientific notation. 

I believe that's a question only you can answer...

Oh yea, I didn't even notice LOL

Well the asker got both questions answered:)

Melody, the poster seems to have asked one question in the "large print" and a different one in the "fine print"......LOL!!!

Thanks TayJay :)

you add them then you divide them by 2

What if there are 2 middle ones TayJay?

Use the definition of the derivative to find the derivative $$\small{\text{$f(x)=x^2-2$}}$$

$$\\\lim \limits_{h \to 0}
\left[
\frac{f\left( x+h \right) - f\left( x \right)}{h}
\right] \small{\text{$\quad f(x+h) = (x+h)^2-2 \qquad f(x) = x^2-2 $ }}\\\\
\lim \limits_{h \to 0}
\left[
\frac{\left( (x+h)^2-2 \right) - \left( x^2-2 \right)}{h}
\right]
=
\lim \limits_{h \to 0}
\left[
\frac{ x^2+2*x*h+h^2-2 - x^2+2}{h}
\right]
=
\lim \limits_{h \to 0}
\left[
\frac{ 2*x*h+h^2}{h}
\right] \\\\
=
\lim \limits_{h \to 0}
\left[
\frac{ 2*x*h}{h}+\frac{ h^2}{h}
\right]
=
\lim \limits_{h \to 0}
\left[
2*x+ h
\right] = 2x$$

The derivative is the gradient of the tangent to the curve at any given point.

if the curve is a line as it is in f(x)=2x-2 then the gradient stays the same all the time.

The gradient of this line is 2.  Therefore the derivative is 2.  

Yep..that looks correct.....I love these "Brain Teasers".....!!!

I'm just doing this one to see if I can solve it without "cheating" and looking at other's answers.....!!!

Let N be the total number of stamps....so we have

C + D   = 49/70N   (1)

B + D  = 60/70N    (2)

B + C = 620

Adding (1) and(2), we have

620 + 2D  = (109/70)N  → D = (109/140)N - 310

So

B + C + D  = N

620 + (109/140)N - 310  = N

310 = (31/140)N →   N = 1400

So D has  (109/140)(1400) - 310 = 780

And B has

780 +  = (6/7)(1400) → D = 1200 - 780 = 420

So D - B = 780 - 420 = 360 more

first put your numbers in order from least to greatest then find the number in the middle

You are welcome :)

its ok Melody.....

but..if your saying so much...then fine..i'll take the points!

thank you!

I am sorry Rosala, I shall go back and recify the problem.    

(I'll give you some points to to amke up for my negligence. :))

Melody you forgot me.......the helper!

The number of ways 10 people can stand in a queue is 10!

now lets treat the 3 fiends as siamese triplets.  that means there are the triplets and 7 other people in the queue.  that is 8 altogether.

that would be 8! permuations BUT  the 'triplets' can be joined in 3! orders. 

So the number of ways that the friends can be together is    8!3!

so the probability that the friends are in the queue together is      $$\frac{8!3!}{10!}=\frac{2*3}{9*10}=\frac{1*1}{3*5}=\frac{1}{15}$$