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-20-12 = -32

Does that mean that you are double the trouble?    LOL

Looks good to me Chris :)

doesn't have one unless you can provide equation

$$pH = -log([H+])$$

According to logarithmic identities, if we raise both sides to the power of the logarithmic base, we can eliminate the log. To do this, we first divide both sides by -1:

$$-pH = log([H+])$$

Then, we raise both sides to the power of 10, thus eliminating the logarithm. Leaving us with:

$$10^-^p^H = [H^+]$$

Hope this helps. 

oh, then no because it will have a negative charge Maybe

i think no

No its not a question 

those are Steps and I put my question at the bottom 

I think the answer is C 

D / R = T  .....so ...  18.4m / (35m/s) = about .526 sec

125/8 = 16 boxes

A) 33.52 is what percent of 8

Just divide (33.52 by 8) x 100%  = 419%

B) 76.8% of what is 40.32    76.8% = .768  ... and  "of" means multiply.. and we'll let "what" = N  ...so we have

.768 x N  = 40.32     divide both sides by ,768

N = 40.32 / .768 = 52.5 = N

9370 x .24 = 2248.8

We have the number of possible hands that include no queens or one queen.

For the number that include no queens, we want to select 5 cards from any of 12 ranks, not including the queens. So we have C(48,5) =1,712,304

For the number that include one queen, and no more, we want to choose 1 of the 4 queens and then any 4 cards from the other 48. So we have C(4,1)*C(48,4) = 778,320

And adding these together, we get,  2,490,624

10^1.36 = 22.9087

Notice that 8/13 of every ml is made of compond B

So.....(8/13) * 1014 = 624 ml

Ok, there is a b stuck inside of the parentheses, so multiply to get it out

3b + 21 ( because 3x7=21)

So far tit looks like this : 3b + 21 + 8
Now you add the 21 to the 8, which = 29

The answer is 3b + 29

-----------------------------------

The answer is 4

We an use a proportion here........

12/ 320 = x / 296    cross-multiply

12*296 = 320*x     divide both sides by 320

12*296/320 = x = 11.1 gallons

By the Pythagorean Theorem, we have

L = √[40^2 + 48^2] = √3904 = 62 inches (rounded)

(1/2)^(-1/2) =

1 / (1/2)^(1/2) =

1/√(1/2) =

1/1  / √2 / 1 =

√2

Alan,

The question was written just like this $$(\ln(x))^2$$ EXCEPT  the exponent was before the variable and after the ln. Does this mean the same thing as what you have written?

The other part is correct though: $$\frac{1}{x(1+4etc.)}$$

Thanks jillybean! I am at the llama hospital right now... ugh..