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the radii are in the ratio 1:2

so the area has to be in the ratio     $$1^2:2^2\quad=\quad 1:4$$

the big one's area is 64pi 

so the little ones area is          $$64\pi/4 = 16\pi \quad cm^2$$

plus 8.5 percent of what?

What happened to the original question? 

How did you know what it was ?

9000*(1.12)^20

40 - 12 = 28

(x+2)(32/x+4).......just "FOIL" this....

First 

x* 32/x  = 32

Outside

4 * x = 4x

Inside

32/x * 2 = 64/x

Last

4 * 2  = 8

So we have

32 + 4x + 64/x + 8 =

40 +4x + 64/x

It doesn't matter....just make sure you subtract the y's and xs in the same order....let me prove this

(6, 4) (2,5)

First way    [ 5 - 4 ] / [ 2 - 6 ]  =  1/-4  = -1/4

Second way  [4 - 5 ] / [ 6 - 2] = -1/4

Note, that I subtracted the y's and the x's in the same  order both times and got the same result...!!!

Ifi had "mixed" the order like this

[5 - 4] / [ 6 - 2]  = 1/4

I would have gotten the wrong answer....!!

Maybe you have a"split" personality....!!!....LOL!!!

{I still like "jillybean,' though }

y=2x^2+3x-14

First, factor out the 2

y = 2(x^2 + (3/2)x - 7)

Take 1/2 of the coefficient on x (3/4), square it =9/16.....then add and subtract it...so we have

y =2(x^2 +(3/2)x +9/16 - 7- 9/16)     factor the first three terms in the parentheses

y = 2[(x + 3/4)^2 - 112/16 - 9/16]       distribute the 2 across the terms in parentheses

y= 2(x + 3/4)^2 - 112/8 - 9/8 =

y= 2(x + 3/4)^2 - 121/8  .... and that's in vertex form

The vertex is (-3/4, -121/8)

I'll do a couple

To find the geometric mean, in this case, multiply the numbers together and take the square root

5)   √(10 * 14)  = √(2 * 5 * 2 *7)  = √(4 * 35)  = 2√35

6)  √(4 * 12.25) = √50 = √(25 * 2) = 5√2

The rest are similar.......

thankyou sir something my teacher couldnt even teach me in a week you taught me in 1 sentence thankyou :)

Call x the area of A and y the area of B

And we know that

x + y = 39

And that

2x + (1/3)y = 33

Using the first equation, we have that  y = 39 - x   and subbing for y in the second, we have

2x + (1/3)(39 - x)  = 33  simplify

2x + 13 - (1/3)x = 33   multiply through by 3 to clear the fraction

6x + 39 - x  = 99

5x + 39 = 99 subtract 39 from both sides

5x = 60     divide by 5 on both sides

x =  12 sq units     this is the area of A

And 39 - 12  = 27 sq units ....  is the area of B

log ₃₂ (4)   we can use the change of base rule to evaluate this

log(4) / log(32)  = .4

And BlackNinja is indeed correct....!!!

I assume that the heptagon is inscribed in a circle.

We have 7 equal triangles, each of whose area is given by

(1/2)(8)^2*sin(360/7) = about 25.010 m^2

So....7 times this  =

7 * 25.019 = 175.13 m^2

how do i find the apothem if the radius is 8

thats all there is

Im Only In Algebra I But I Think Its 0.4

To Answer The Question I Need More Info About The Problem

Well A = (1/2)(numberofsides)(lengthofaside)(apothem)

the answer to your question is 15

18 x 5/6 = 15

9 x 7 = 63

To find x, you must first take the log base 3 of both sides, so it's D. 

The answer is 2.49

Since 12 times 12 is 144, that means its 12^2, and when you put that into a square root, it only equals 12 since it gets rid of the square root 2. Does that make sense, if you aren't askiung this as a stupid question.