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Give me an example of what you want to factorise and I'll discuss the best way of doing it :)

asin

inverse sign is the same as arc sine

(2+3i) + (-4+5i)

$$\small{\text{$(2+3i) = \left( \begin{array}{c} 2 \\ 3 \end{array} \right)$}}\\
\small{\text{$(-4+5i) = \left( \begin{array}{c} -4 \\ 5 \end{array} \right)$}}\\
\small{\text{$(2+3i) + (-4+5i) = \left( \begin{array}{c} 2 \\ 3 \end{array} \right)+\left( \begin{array}{c} -4 \\ 5 \end{array} \right)
$}}\\
\small{\text{$=\left( \begin{array}{c} 2-4 \\ 3+5 \end{array} \right) $}}\\
\small{\text{$=\left( \begin{array}{c} -2 \\ 8 \end{array} \right) = (-2+8i)$}}\\$$

$$\\\sqrt{0.5(x^2-9x+22)}=0\\\\
x^2-9x+22=0\\\\
\triangle=81-88<0$$

Since the determinant is less than 0 this equation is never true.  There are no solutions.

If you were a member I might give some consideration to your complaint. 

But you are not even a member!

You are just an anonymous whinger!

You're a  whiny-assed crybaby.  I could not have said it better myself!

Thanks 2'nd anon  

older than me, older than you but younger than CPhill and my dad!

well.....i wont...but i think you need to! :)

just note down what u do in the whole day and what makes you feel good and thats what you like!

ta da!

shut up rosala

You have not said what shape this tunnel in it is obviously not a cylinder.

I'll go for the easiest option. 

A rectangular prism where the bottom is also included.  So it has 4 sides.

Here is the net that you will need.   If you fold this 'peice of paper' you will have your tunnel :))

"It would have to be 3rd dimension paper"    That is hilarious.    ROF LOL    ROF LOL

Thanks anon you have made my day.  :)))

Australia is a part of Asia - we definitely rock!!

ok

how many ways can the 3 girls sit next to each other ?   4P3 = 24

Now lets take just one of these 24 permutations and put them together with the others.

I will take the 3 girls as one (siamese triplets) + one more girl +5boys = 7  so 7! permutations.

So altogether I think that there will be   24*7! permutations

$${\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{7}}{!} = {\mathtt{120\,960}}$$           I think that is correct.

Having that 4th girl is throwing me a bit, but I think it is ok.

nothing is harder if you work with all your might and wish!

(2+3i) + (-4+5i)

=2+3i + -4+5i

=2+3i -4+5i

=-2+8i

The diameter of the bicycle is 22 inches. About how far will the tire go in one rotation ?

$$\small{\text{One Rotation $ = \pi \cdot d = 3.14\cdot 22\ \rm{inches}
= 69
$}}$$

Choice D is okay!

The endpoint of line CD are given.find the coordinates of the Midpoint M.

1: C(3,-5) and D(7,9)

$$M(x,y) = \left(\frac{3+7}{2},\frac{-5+9}{2}\right) = (5,2)$$

2: C(-8,-6) and D(-4,10)

$$M(x,y) = \left(\frac{-8-4}{2},\frac{-6+10}{2}\right) = (-6,2)$$

-2x - 1 < 11

-2x < 12

2x > 12

x > 6

x² + 24² = 25²

x² = 25² - 24²

x² = 625 - 576

x² = 49

$${\sqrt{{{\mathtt{x}}}^{{\mathtt{2}}}}} = {\sqrt{{\mathtt{49}}}}$$

x = 7

300+7x=6x+300

x=0

Thank YOU ☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺

To get cos^-1(0.4321)

Press (2nd)

Then (acos)

Then enter 0.4321

And hit the equal sign.

I'm not sure what you mean by the "Csc of (1,0)" ...

However, the Csc(0) is undefined because:

          Csc(x)  =  1/Sin(x)

--->   Csc(0)  =  1/Sin(0)

Since the Sin(0) = 0, 1/Sin(0) = 1/0 and 1/0 is undefined; therefore, Csc(0) is undefined.