All Answers 358156 Answers

What you have is not a formula with a standardised name.  It is just the expansion for a perfect square.

quadratic formula   (it should have x = out the front like anon has written.)

It is just

$$\frac{x+2}{(x-2)^2}$$

and this cannot be simplified

That is fine cemone.  :)

I don't see what difference it makes whose computer you are on but it doesn't matter, 

if you identify yourself with your name at the bottom that will be an alternative :)

Welcome to the forum.

(You can find your posts much easier if you are a member and you can chat to people privately

and you can save the posts that interest you too  :)

4time4times5time5time5=  $$4^2*5^3$$

csc 138 degrees 23' = 1/sin( 138 degrees 23')

enter it into the calc like this :)

1/sin(138+23/60)

youvstart  it off with an open parenthess put your numerater and press the divison sign which will look like / and finish it off by putting your denominator and a close parenthese like so:    

                (a/b)

sin(2asin(3/4))

let      $$\theta=asin(3/4)$$       You should recognise that this is an angle.

$$\\sin(2\theta)=2sin\theta cos\theta\\\\
sin\theta=\frac{3}{4}\\\\
opp=3,\; hyp=4\; adj=\sqrt{16-9}=\sqrt{7}\\\\
cos\theta=\frac{\sqrt7}{4}\\\\
2sin\theta cos\theta \\\\
=2\times\frac{3}{4}\times\frac{\sqrt7}{4}\\\\
=\frac{6\sqrt7}{16}\\\\\\
sin(2asin(3/4))=\frac{3\sqrt7}{8}\\\\\\$$

draw the rectangle.

label the widths as 81 ft each

the perimeter is the distance around the outside.

it all has to add up to 346 feet

you see if you can work it out :)

do you like cheese?

$$cos\theta = \pm 4/5$$

sin is neg in the third and forth quadrant

cos is neg in  the 3rd but pos in the 4th

If you think it cos of an acute angles it is    adjacent side / hypotenuse

the hypotenuse is always the longest side so  this ratio must  be less than one.

When you extand the angle to include all angles then      $$-1\le cos(angle)\le 1$$

8-3p>40

-3p>32

now I need to divide by a neg number so I have to swap the sign around

p< 32/-3

In the imaginary number plane it is an isosceles triange.  sketch it and you will see this easily.

All five of those numbers added up equals to -33.

-33 divided by 5 equals -6.6.

$${\mathtt{5.7}}{\mathtt{\,\times\,}}\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right) = {\frac{{\mathtt{323}}}{{\mathtt{10}}}} = {\mathtt{32.3}}$$

Use the Pythagorean Therorem: $$h^2=a^2+b^2$$  where h is the hypotenuse.

Using you data, the third side of the triangle is 9.94.

From there note that the tangent function involves the opposite side over the adjacent...but you are not interested in the tangent (you already have it). You need the angle, which you can obtain through the arctangent. The arctangent (9.94/15)=33.53.

the real answer is 19 so he is incorrect

The arccos is the angle the cosine of which is between -1 and +1. There is no value of theta which will give a value of 50.

the answer is 0.6451612903225806

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1. 
   
   In quantum field theory, the mass gap is the difference in energy between the vacuum and the next lowest energy state. The energy of the vacuum is zero by definition, and assuming that all energy states can be thought of as particles in plane-waves, the mass gap is the mass of the lightest particle.