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2+2=4

2*2=4

2*2=2+2

20/2 x (5+5) = 100

Thanks Shaniab

janet has 83 nickels and dimes that total 6.90 how many of each type does she have

YES i am with you anon.

I think that there are 5c in a nickel and 10c in a dime.  

Yep, I checked, that is right. WE are not all yanks you know!   

Anyway, let there be N dimes.

nickels = 83*5 = 415 c

dimes = N*10 = 10N cents

415+10N = 690     remember we are working in cents

10N=690-415

10N=275

N=27.5 dimes

but you cannot have half a dime so your question has a bad smell to it.

What I mean is that it is an impossible situation.    

Thank you for answer.

Where you find that formula my book not have it.

The answer is 6.

$${\mathtt{23}}{\mathtt{\,\times\,}}{\mathtt{23}} = {\mathtt{529}}$$ 23 squared is 529

hahha oh mine bad did not read it right hahah lol

the answer is inside you, be strong and use the force my child!

Hi Shaniab,   

it says 23 squared - not square root 

Here is a number of other examples.

there is a sticky note on this topic.

the sticky notes are to the right of your screen

You have to use inverse cos or acos when you are looking for the angle

acos(3/5)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{3}}}{{\mathtt{5}}}}\right)} = {\mathtt{53.130\: \!102\: \!354\: \!156^{\circ}}}$$

Sorry, that's a little too parochial for me. You're going to have to remind me how many cents there are in a nickel, and how many there are in a dime.

I do not understand what you are asking warrior.  

Mmm I think you should give us an example of when this would happen. 

There is a calculator on the home page. 

Why not just divide both sides by 4 in the first place :)

Thw squared root 23 is 4.79 which i about five 

Scientific calculators do logarithms too.

Your question does not seem to have much to do with logarithms  

Thanks Alan,

I will do some of what Alan did only a little slower

$$\\-y^2 + x + 20y - 94 = 0\\\\
$Mult both sides by -1 $\\\\
y^2 - x - 20y + 94 = 0\\\\
y^2 - 20y- x =\;-94\\\\
(y^2 - 20y+(\frac{-20}{2})^2)- x =\;-94+(\frac{-20}{2})^2)\\\\
(y^2 - 20y+100)- x =\;-94+100\\\\
(y-10)^2- x =\;6\\\\
(y-10)^2 =\;x+6\\\\$$

this is sideways parabola that opens out in the positive direction.

I know it is a parabola because one of the varibables is squared but not the other.  And both are on the top and they are not multiplied together or anything strange like that.

I know it is sideways because it is the y that is squared, not the x.

I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is Positive

I can see that the vertex is (-6,10)

I can see other things too but that might be enough for now.  Alan's graph will hopefully backup everything that I have said. :)

PS.  There was a small error      that i have fixed.  Thanks Alan

Here are the graphs

what is the binary for p

Mmm

well lets look at a number example  Say 17

what is the highest power of 2 that goes into 17,  that would be 16

17= 16+1 = 2^4+1 = 1000+1=1001

Converting that to an equation for p would be messy.  

or it could mean

(((((((10*2)*2)*2)*2)*2)*2)*2)

=10*2^7

=10*128

=1280

I am still getting used to these questions and I still like them. :)

I'd do it the same as CPhill but I would start with a smaller number.

$$\\7^1=7\\
7^2=49\\
7^3=343\\
7^4=2401\\
$that is a really helpful one$\\
$(Any number ending is 01) raised to any positive integer n must also end in 01 because only the last 2 digits will affect the outcome and 1^n=1 $ \\\\
(7^4)^{n} $ must end in 01 for any positive integer n$\\\\
7^{2014}=7^{2012}*7^2\\
7^{2014}=7^{4*503}*7^2\\
7^{2014}=(7^4)^{503}*49\\
7^{2014}= ....01 *49\\
7^{2014}= ....49\\$$

so the last 2 digits will be 49    Just like CPhill said