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No MG  

Any number divided by itself equals 1   (except for 0)

so 

$$90=\frac{90}{1}$$

2/5+-1/3*6=-4/5

Remember that the domain for inverse sine is     $$-\pi/2\le \pi/2$$

So only 1st and 4th quadrant answers are relevant.  :)

9+10=21

Jam is made from 4 parts fruit to 3 parts sugar. How much sugar is needed to make jam from 1kg of fruit?

$$\\\frac{x \;sugar}{1000g fruit}=\frac{3sugar}{4fruit}\\\\
x \;sugar=\frac{3sugar}{4fruit}\times(1000g fruit)\\\\
$The fruit cancels out, so does the 4$\\\\
x \;sugar=\frac{3sugar}{1}\times(250g)\\\\
x \;sugar=750gsugar\\\\
x=750g$$

So Faisal is correct         750g   is   0.75Kg   of sugar is needed.

$$\frac{d}{dx}\;x(2-x)\\\\
=\frac{d}{dx}\;(2x-x^2)\\\\
=2-2x$$

9+10 is 19

of means times and1/3*22.3=7.43 so thats the anwser

The number that defines the universe is 299792458 (m/s), as it is the speed of light, responsible for the way time and matter behave. You could also be looking for the diameter of the observable universe, which is approximately 4 with 83 zeros in dm³. Hope I helped you 

You add $1 on to get $43.50

9+10 is 19

I'm guessing 90/100

How do you describe the transformations from the parent graph of (x) = Sqrt(x) When the problem is g(x) = -1/2 sqrt(1/5(x+5))+7

I always find these fascinating - lets look at the 2 graphs

Now I think I will look at it one step at a time.

(x) = Sqrt(x) When the problem is g(x) = -1/2 sqrt(1/5(x+5))+7

$$\\f(x) = \sqrt{x} \\\\
$First move the graph 5 places to the LEFT$\\\\
f_2(x) = \sqrt{x+5} \\\\
$now multiply all the y values by a factor of $ \frac{1}{2\sqrt{5}}\\\\
f_3(x) =\frac{1}{2\sqrt{5}} \sqrt{x+5} \\\\
$now simplify$\\\\
f_3(x) = \frac{1}{2 }\sqrt{\frac{x+5}{5}}\\\\
$now reflect the graph in the y axis (mult by -1)$\\\\
f_4(x) = \frac{-1}{2 }\sqrt{\frac{x+5}{5}}\\\\
$Now raise the graph by 7 units$\\\\
g(x) = \frac{-1}{2 }\sqrt{\frac{x+5}{5}}+7$$

I have done this transformation - bit by bit - in Desmos

x(2-x)=2x-x^2 

wen u dreivate u will get

2-2x   

LET a +b+c+d+e+f+g+h =30 , also a,b,c,d.....>orequal to 2

let p=a-2 , q=b-2 , r=c-2 ........

now , (p+2)+(q+2)+......=30

so , p+q+r+......=14

therefore total number of solutions is (14+8-1)C(8-1) =(21)C(7)

I HOPE YOU UNDERSTOOD

derivate x(2-x)

Do you mean

_7P^3                $$_7P^3$$

OR MORE LIKELY YOU MEAN

^7P_3                 $$^7P_3$$

these are both written in LaTex  I had to press the [LaTex Formula] button and enter it in there.  :)

Now if you want to put it into the calc you can do it like this - I am using the [Calculation] Button

nPr(7,3)               $${\left({\frac{{\mathtt{7}}{!}}{({\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)} = {\mathtt{210}}$$

I have no idea ;/

$$\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right){\mathtt{\,\times\,}}{\mathtt{7}} = {\frac{{\mathtt{119}}}{{\mathtt{3}}}} = {\mathtt{39.666\: \!666\: \!666\: \!666\: \!666\: \!7}}$$

It is good to make use of the calculation button - than you can do calculations straight into your post!

Thank you Alan .

Thank you Melody .  

Thank you all 

A paralellogram with 4 right angles is a rectangle.

A judge without any thumbs - mmm - Justice Fingers ?

Hi Reinout and civonamzuk,

Excellent answers from both of you - thank you  !

You need to check your (7,35), (7,42) and (7,51) pairs Melody.  I get the following:

probability = 9/21 or 3/7

.

use

acos

asin

atan