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No prob.....!!!!

When we have a negative exponent on a term, we just bring that term "across" the fraction bar and write the term with a positive exponent...so we have....

14^5 / 14^-9  =

14^5 (14^9)  =

14^14

thank you CPhill :)

im not exactly shore but if you go on khan academy they have a circle graphing chart that can help you :)

P = 2L + 2W    write as

P = 2(L + W)   divide both sides by 2

P/2  = L + W    subtract  L from both sides

P/2 - L  = W    

And that's solving for W

ur mom

Hit he "2nd" button and then you will see the 'asin" button  

:) the more questions you answer the higher your + gets

This won't factor....it's "irreducible" as a product of linear factors.....

Let C be the cost of a child's ticket.....and 2C be the cost of an adult ticket....then

2 child's tickets cost 2(C)  = 2C

And 2 adult tickets cost 2(2C)  = 4C

So the total cost is given by

2C + 4C = 24   simplify

6C = 24     divide both sides by 6

C = 4    and the cost of a child's ticket in dollars

And 2(4) = 8  = the cost of an adult ticket in dollars

I don't really know how to write an equation for this, but if the total cost for two adults and two kids is $24 and the child's ticket costs half of the adults ticket then it is 8 dollars for an adult and 4 dollars for a child.

8 goes in 24  three times. So 2 times, for the adult tickets, and then u devide the last one by two, which is 4. 

does that make sense?

Hope this helps!!

Let N be the number......so we have

N^2 - N  = 4N - 1      add 1 to both sides and subtract 4N from both sides

N^2 - 5N + 1  = 0  using the onsite calculator and substituting x for N, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{21}}}}{\mathtt{\,-\,}}{\mathtt{5}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{21}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{0.208\: \!712\: \!152\: \!522\: \!08}}\\
{\mathtt{x}} = {\mathtt{4.791\: \!287\: \!847\: \!477\: \!92}}\\
\end{array} \right\}$$

Those are the two solutions......!!!!

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Ohhh okay! Thank you! 

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Thank you CPhill and garmoon! 

"PM" = Private Messages.....it's basically our "email" for members.....!!!

Never mind, you already solved it! Good job!   

Okay, so I found this video that explains what the distributive property is. 

1+1=2. Anybody can figure that out.