All Answers 358812 Answers

multiply it by 100 and add the percent sign :)

first I will do base 10

$$\\9615476\\
=9*10^6+6*10^5+1*10^4+5*10^3+4*10^2+7*10+6*1$$

Now I will do base 2

1001110 base 2

 $$\\=1*2^6+0*2^5+0*2^4+1*2^3+1*2^2+1*2^1+0\\
=2^6+0+0+2^3+2^2+2^1+0\\
=64+8+4+2\\
=78 \;base\; 10$$

OR 

you could just use this calculator

I have 7 different math books and 4 different history books. In how many ways can I line the 11 books up on a shelf if a history book must be in the middle and each end must be a math book?

M -  - - - H - - - - M           Total of 7 maths and 4 history and all are different

first*last*middle* rest(8)

7*6*4*8*7*6*5*4*3*2*1 = 7*6*4*8! =6,773,760

I think that is the same a Geno :)

I do not understand your question Mellie  

I do not understand this question, :?

You have asked this question about a thousand times today !

well if a square has 4 then a square has 21

I don't understand what is being asked but maybe someone else will.  :/

Great work anon

$$(4\div 0.4)\div 0.4 +4=29$$

That number has 12 zeros - so it is  10^12

the square root is 10^6

9/2=4.5

5*4.5=22.5 cups of water.

Thank you 

This was my first step in this forum ,sorry

Hi anika,

I am here everyday mainly for answering questions and I have an account :)

I would be interested how other people use this forum too :)

yes

$$log_{10}15 =\frac{log_x15}{log_x10}$$

x can be any positive number except for 1

$$\\150n=180(n-2)\\
150n=180n-360\\
360=30n\\
n=360/30\\
n=12 sides\\$$

That is really cute - thanks anon :)

Start by factoring out the 5 :)

180(8-2) = 180*6

The coetfficent is the number in front of the letter/s

For example:

$$5x^2+6x-3-12xy+xy^2$$

the coefficient of x^2 is 5

the coefficient of x is 6

the coefficient of xy is -12

the coefficient of xy^2 is 1

and

the constant is -3

I'll use the calc and see.

$${\left(-{\mathtt{1}}\right)}^{{\mathtt{2}}} = {\mathtt{1}}$$

$${\mathtt{\,-\,}}\left({{\mathtt{1}}}^{{\mathtt{2}}}\right) = -{\mathtt{1}}$$        The calc put the brackets in - I did not.  But the answer is correct.  :)

Neither of us made the site but thank you.  

This site is is owned and built by a brilliant man by the name of Mr. Massow.  :))

It could be any length between 0 and 14.75 not inclusive.

It would depend on the size of the angle between the other two sides :/

find the area of the triangle having the indicated sides and angle:

C=84.5°, a=32, b=40

$$\boxed{
2\cdot A = a\cdot b \cdot \sin{( C ) }
}\\\\
\small{\text{$2\cdot A = 32 \cdot 40 \cdot \sin{(84.5\ensurement{^{\circ}}}) $}} \\
\small{\text{$ 2\cdot A = 1280 \cdot 0.99539619837 $}}\\
\small{\text{$ 2\cdot A = 1274.10713391 $}}\\
\small{\text{$ A = 637.053566955 $}}$$

Line RS passes through points R (5, 3) and S (-1, 0). 

Line PQ is parallel to line RS and passes through points P (3, -1) and Q (-2, y). 

What are the coordinates of point Q ?

$$\small{\text{Line PQ is parallel to line RS - cross product }}
\boxed{|(\vec{S}-\vec{R}) \times (\vec{Q}-\vec{P})| = 0}\\ \\
\left|
\left[
\binom{-1}{0}-\binom{5}{3}
\right]
\times
\left[
\binom{-2}{y}-\binom{3}{-1}
\right]
\right| = 0\\\\
\left|
\binom{-6}{-3} \times \binom{-5}{y+1}
\right| = 0\\\\
(-6)\cdot(y+1)-(-3)\cdot(-5) = 0\\
(-6)\cdot(y+1)-15 = 0\\
(-6)\cdot(y+1)=15\\\\
y+1=-\frac{15}{6}\\\\
y=-\frac{15}{6}-1\\\\
y=-\frac{21}{6}\\\\
y= -\frac{7}{2}\\\\
y=-3.5\\\\
\boxed{\vec{Q}=\binom{-2}{-3.5}}$$