All Answers 358087 Answers

./-/. KAPA AWAH                  

48C3 / 52C7

$${\frac{{\left({\frac{{\mathtt{48}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{48}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)}}{{\left({\frac{{\mathtt{52}}{!}}{{\mathtt{7}}{!}{\mathtt{\,\times\,}}({\mathtt{52}}{\mathtt{\,-\,}}{\mathtt{7}}){!}}}\right)}}} = {\frac{{\mathtt{1}}}{{\mathtt{7\,735}}}} = {\mathtt{0.000\: \!129\: \!282\: \!482\: \!223\: \!7}}$$

i think that is right :/

Caps much? =/

Example, 3/4 = 0.75

but if there isnt, you  will have to convert the fraction into a decimal

if there is a slash, use slash "/"

Either press the 2nd button or hover over them and press your shift key.

.

Thanks Bertie, I shall have to take time to look at your answer  :)

Thanks for that great explanation Alan, I had vagely thought there could be problems but your explanation clarified it for me.   :)

Thank also Badinage.  Your extra inputs really helped my thoughts. :)

DIVIDE 5 BY 7 AND YOU GET 71.42857142857143%

That is an interesting graph  :)

atan(7/12)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{7}}}{{\mathtt{12}}}}\right)} = {\mathtt{30.256\: \!437\: \!163\: \!529^{\circ}}}$$

That is just the first quadrant answer, it may also equal  180+30=210 degrees

$$\small{\text{Quater $ = 25 \qquad $Dime $ = 10 \qquad $ Nickel $= 5
$}} \\
\small{\text{In \$0.55 max. 2 Quaters, max. 5 Dimes and max. 11 Nickels }} \\\\
\left(\sum\limits_{i=0}^{2} x^{(\textcolor[rgb]{0,0,1}{25}*i}) \right) \times \left (\sum\limits_{i=0}^{5} x^{(\textcolor[rgb]{0,0,1}{10}*i)} \right) \times \left(\sum\limits_{i=0}^{11} x^{(\textcolor[rgb]{0,0,1}{5}*i)} \right) \\\\
\small{\text{$=(1+x^{25}+x^{50})$}} \times
\small{\text{$(1+x^{10}+x^{20}+x^{30}+x^{40}+x^{50})$}} \\ \times
\small{\text{$(1+x^{5}+x^{10}+x^{15}+x^{20}+x^{25}+x^{30}+x^{35}+x^{40}+x^{45}+x^{50}+x^{55})$}}\\
\small{\text{$
=(x^{155})+(x^{150})+2*x^{145}+2*x^{140}+3*x^{135}+4*x^{130} $}} \\
\small{\text{$+5*x^{125}+6*x^{120}+7*x^{115}+8*x^{110}+10*x^{105}+11*x^{100} $}} \\
\small{\text{$+11*x^{95}+12*x^{90}+12*x^{85}+13*x^{80}+13*x^{75}+12*x^{70} $}} \\
\small{\text{$+12*x^{65}+11*x^{60}+\textcolor[rgb]{1,0,0}{11*x^{55}}+10*x^{50}+8*x^{45}+7*x^{40} $}} \\
\small{\text{$+6*x^{35}+5*x^{30}+4*x^{25}+3*x^{20}+2*x^{15}+2*x^{10}+(x^5)+1 $}} \\$$

The coefficient from  $$\small{\text{$\textcolor[rgb]{1,0,0}{x^{55}}$}}$$ is $$\small{\text{$\textcolor[rgb]{1,0,0}{ 11 }$}}$$. So there are 11 possibilities.