you tecnically cant do that since its infinite

10 x 5 is 50

1 divided by 23 dummy

If you are asked to solve then here:

x= 5±3 sqrt(5)

Separate the problem into two equations because of the plus/minus (+/-) symbol.

So 5 + 3 sqrt(5) and 5 - 3 sqrt(5)

Now simplify each equation individually and you should then get two answers (one each).

The mean is also called the average.

The average (avg) is calculated by adding all the numbers in the sequence, then dividing the sum by the number of numbers in the sequence.

Take the sum of 15,7,6,9,10,12,11, then divide it by 7 because there are seven numbers in this sequence.

$${\mathtt{50}} = {\mathtt{5\times 10^{1}}}$$

you go 1 then 16 then 99 then 4444444444444444 then 2

Here yo go.....

(12)

10 + 5e^(2x) = 17     subtract 10 from both sides

5e^(2x)  = 7       divide by 5 on each side

e^(2x)  = 7/5  = 1.4      take the ln of both sides

lne^(2x)  = ln1.4      and we can write

(2x) * lne = ln 1.4     and ln e  = 1, so we can ignore this

2x = ln 1.4       divide by 2

x = [ln 1.4 ] / 2  ≈ .168

(11)

4e^x - 4 = 2     divide through by 2

2e^x - 2  = 1    add 2 to both sides

2e^x  =  3        divide both sides by 2

e^x = 3/2  = 1.5    take the ln of both sides

ln e^x = ln 1.5    and we can write

x * ln e = ln 1.5    and ln e  = 1, so we can ignore this

x = ln 1.5 ≈ .4055

We only need to show that two sides are parallel

The slope between  (0,5) and (6, -1)   =  [-1 - 5] / [6 - 0] =  -6/6 = -1

And the slope between (8,3) and (4,7) =  [7 - 3] / [ 4 - 8] = 4/-4 = -1

So  AB ll CD

Also  the distance between AD and BC are equal, so this is an isoceles trapezoid.

Here's  a pic......

im about to cry becuse he wont post on this :(

6⁷ / 6⁵  =  6² =   36

4x-10+2x=4-2/3(6x-9)

4x -10  + 2x = 4 - 4x + 6    simplify

6x - 10  = 10 - 4x      add 10 to both sides

6x = 20 - 4x     add 4x to both sides

10x = 20     divide by 10 on both sides

x = 2

36 Do i really need a more detailed answer???

If you mean for personal excercise, then I would suggest 5-6 times a week for maybe 30-60 minutes. The number one thing to remember is that it's not how much of the excercise you can do, but having a constant routine that you do. That's my opinion :)

Well....swimming in salt water is easier {it's more buoyant}....just watch out for the jellyfish  ....!!!!

I'll toss you a lifesaver ring if you get near Shreveport.....LOL!!!!

The top is 53!. The bottom is 48!5!. So the 48 cancels with the 53 on top except for 53×52×51×50×49. That should be more manageable. Then divide that big number by 5!, which is 120.

i actually have to leave here soon becuz of practice. its from 4-6pm CT :D

u bet ya! lol

LOL!!!......if the Atlantic HAS flooded......all that swimming practice is gonna' come in handy  !!!!!!

lol! XD gtg c u ltr

omg. chris u know wat i mean! ugh. -.-