I would say the board and trigger, but that is just me
i am glad someone gets it
That actually makes a lot of sense
does anyone get it
the answer is a stapler
that's wat i was thinking... its the only thing i thought of
A spider? or an arachnid of some sort.
3x-2y=4
-6x+4y=7 solve with inversion method
$$\small{\text{ $ A = \begin{pmatrix} 3 & -2 \\ -6 &4 \end{pmatrix} \qquad det ~ A = \begin{vmatrix} 3& -2 \\ -6& 4 \end{vmatrix}=3 \cdot 4 -(-6)\cdot (-2) = 12 - 12 = 0 $}}$$
det A = 0, no solution
i just sent a joke
wait! i was here first!!! lol
The equation you are looking for is y=.7x plus seven. While x is the amount of years.
ill talk with ya!!! :P
Meeeeee !!!!!!!
oh,you know i was just joking right
It is a warning system so we know when a*s-holes are around.
why do you smell lol
just joking
$$\\3a \sqrt{45 b^3} + 2a \sqrt{80 b^2} - 7 \sqrt{20 a^2 b^3}\\\\ 3a \sqrt{9b^2* 5b} + 2a \sqrt{16 b^2*5} - 7 \sqrt{4 a^2 b^2*5b}\\\\ 3a*3b \sqrt{5b} + 2a *4b\sqrt{5} - 7*2ab \sqrt{5b}\\\\ 9ab\sqrt{5b} + 8ab\sqrt{5} - 14ab \sqrt{5b}\\\\ 9ab\sqrt{5b} - 14ab \sqrt{5b}+ 8ab\sqrt{5} \\\\ -5ab \sqrt{5b}+ 8ab\sqrt{5} \\\\ 8ab\sqrt{5} -5ab \sqrt{5b}\\\\$$
The letters are meant to be under the square root sign
oops
Ok, so this is exactly how it was stated
