All Answers 358108 Answers

Assuming that Earth's orbit is circular . . .

Circumference = pi times diameter

Since the sun is the center, the diameter is 2*93000000 = 186000000

C = pi*186000000 = 584336233.5677 miles.

So every 365 days Earth travels 584336233.567701542 miles.

Every 1 day it must travel 584336233.5677/365 =  1600921.187856717 miles.

And every hour 1600921.1878/24 = 66705.049494030 miles.

The speed is 66,705.05 miles/hour (nearest hundredth) 

365 days = 365*24 hours

Circumferential distance travelled in 365*24 hours = 2*pi*93,000,000 miles

Linear speed = distance/time = 2*pi*93,000,000/(365*24) miles per hour

$${\frac{{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{93\,000\,000}}}{\left({\mathtt{365}}{\mathtt{\,\times\,}}{\mathtt{24}}\right)}} = {\mathtt{66\,705.049\: \!494\: \!029\: \!856\: \!433\: \!1}}$$

speed = 66,705.05 miles per hour to nearest hundredth (or did you mean to nearest hundred, in which case speed = 66,700 miles per hour).

.

Depends how many scouts there are!

.

Area = 2*(1/2)*a*b + a*h + b*h + c*h  or  Area = ab + (a+b+c)h

.

$$5x+\frac{2}{2}=2x-1$$

$$5x+1=2x-1$$

$$5x=2x-2$$

$$3x=-2$$

$$x=\frac{-2}{3}$$

A = P*(1 + r)^n

We should convert the annual rate of 0.35% or 0.0035 into a quarterly rate . . . 0.0035/4 = 0.000875

The period is 120 months, 10 years or 40 quarters 

A = 100,000*(1+0.000875)^40

A = $103560.39

Mmm   I like being a Queen again  :))

Thanks Heather 

Mathcad, you ARE assuming that there are 100 products.

 Alan has tried to show you where you logic falls in a heap 

Nice answer MathsGod1    

I thought this was a really cool question.  Thanks for providing it Alan.

Isn't any one of you high school students going to show us what you are made of and answer it.

You could at least give it a try :/    

65t = t hours

Divide both sides by t.

65 = 1 hour (t/t = 1)

For two hours multiply 65 by two to get 130 miles.

Looks like you answered your own question . . . 

I am assuming we are talking about a price in square feet . . .

A = length times width

15 and 1/3 = 46/3

8 and a half = 8.5

$${\frac{{\mathtt{46}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{8.5}} = {\frac{{\mathtt{391}}}{{\mathtt{3}}}} = {\mathtt{130.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$ square feet

So we need to purchase 131 square feet's worth (assuming they don't deal in fractions).

131*4.75 = $622.25

it is 5/8 . as the actual valule of -5/8 is 5/8

$${\frac{{\mathtt{2}}}{{\mathtt{13}}}} = {\mathtt{0.153\: \!846\: \!153\: \!846\: \!153\: \!8}}$$ (you can use a calculator for this)

x to the power of 4 can be written as x^4. If you are enquiring about the calculator then look for the button that reads "$$x^y$$".

Trout Population = starting population*(1 + rate)^number of years

$$P = SP\times{(1+0.15)^n$$

$$500 = 225\times{(1+0.15)^n$$

$$1.15^n = \frac{20}{9}$$

Now I'm not sure how you find n. It is somewhere between 5 and 6.

Without going into the third dimension I don't see how this is possible.

For two sheep you could just have them x distance apart.

The only way I see 3 sheep being arranged in that way is in the shape of an equilateral triangle, where all the sides are x.

Where could the other sheep go so that it is an equal distance from all the other sheep without hovering x amount above the center of the triangle?

how much bigger than 127 is 154

This is asking what the difference is between 127 and 154.

We can look at this as 154 - 127 = 27

So 154 is 27 units bigger than 127 (127 + 27 = 154)

It is 483.514 ALLAHU AKBAR!

have you tried solving this problem with pemdas?

do exponents first, then division, then subtraction