All Answers 358110 Answers

It's simply 191,626 x 2.0 If you wanted any other percent you would use 191,626 x .10 (10 percent) 191,626 x .50 (50 percent) 191,626 x .86 (86 percent) 191,626 x 5.0 (500 percent) and etc for any other percent.

What do you want to do with it?  It cannot be simplified.

Just proves, Melody....you need to stay away from "tables"....LOL!!!!

Thanks Chris

You make it look so difficult Chris.   

I placed the givin equation on the claculator, I am assuming that you are looking at a circle? There for I used the negative cosine which is the second function and then cos button on the calculator. Then place the fraction 10/15 into the calculator, you can simplify to 2/3 if wanted to. After you plug it in the caluculator you get the arc measurement, I got 48.189685104221° after I plugged in the equation into the calculator. Hope that helped some what

Let S = sisters, B = brothers and FC = first cousins.....and we're told that.......

S = 3FC

S = 2B

So

B = (3/2)FC

And let "me"  = 1

So

3FC + (3/2)FC + 1  < 19

3FC + (3/2)FC < !8 

(4.5)FC  < 18

FC < 4  

But....FC has to be a multiple of 2, because if it's an odd number, the number of brothers will be a fractional amount.....!!!!!

But if FC < 4, then the only multiple of two is 2...!!!

So FC =2

S = (3)FC = 3(2) = 6

B = (3/2)FC = (3/2)(2)  = 3

So....the total children =  6 sisters, 3 brothers  (and "me")  = 10

Hi Gibson,     

$$\\15=\frac{75\sqrt{x-3}}{\left(\frac{60}{(x-10)^2\right)}}\\\\
\frac{15}{75}=\frac{\sqrt{x-3}}{\left(\frac{60}{(x-10)^2\right)}}\\\\
\frac{3}{15}=(\sqrt{x-3})\div{\left(\frac{60}{(x-10)^2\right)}}\\\\
\frac{3}{15}=(\sqrt{x-3})\times{\frac{(x-10)^2}{60}}\\\\
\frac{3*60}{15}=(\sqrt{x-3})\times(x-10)^2}\\\\
12=(\sqrt{x-3})\times(x-10)^2}\\\\
144=(x-3)\times(x-10)^4}\\\\
144=(x-3)\times(x-10)^4}\\\\
144=(x-3)(x^4-4*10x^3+6*100x^2-4*1000x+10000)\\\\
$I'd keep going but i think I will just ask the calc$$$

 EDITED: Thanks Fiora for pointing out the error.

I actually put it into the web2 'correctly' but I did not put a * between the brackets and the calc misinterpreted what I was saying.  I now find that the web2 calc will not solve this which is interesting.

I guess WolframAlpha is always the fall back calc :)

$${\mathtt{144}} = \left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\right){\mathtt{\,\times\,}}{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}\right)}^{{\mathtt{4}}} \Rightarrow {\mathtt{0}} = {{\mathtt{x}}}^{{\mathtt{5}}}{\mathtt{\,-\,}}{\mathtt{19}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{4}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{144}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{3}}}{\mathtt{\,-\,}}{\mathtt{544}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1\,024}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{912}} \Rightarrow {\mathtt{0}} = {{\mathtt{x}}}^{{\mathtt{5}}}{\mathtt{\,-\,}}{\mathtt{19}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{4}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{144}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{3}}}{\mathtt{\,-\,}}{\mathtt{544}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1\,024}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{912}}$$

x must be greater than 3

You can check it with Wolfram alpha anyway :)

2,3,6

1,4,9

I have added this to our logic puzzle thread. (in sticky threads) :)

Thank you anon for providing it :)

Yeah TR, it's called grade inflation. In your case, it's hyperinflation inflation.

To all answerers.

This table fuction is built into the web 2 forum.  

It does not do borders which is a pity but it is a great feature and I seem to be the only one that ever uses it.  Why is that?

Well, your mum had less than 19 children.

Since you have 3 times more sisters than cousins it stands to reason that you have at least one cousin.

Lets do a table

So my mum had 10 children          [Corrected - I forgot me, even though I was in the table  LOL]

This just takes us to a log in page.  

I'd really like to see your input here Awsomeee.

You will learn much better if you interact with us.

How do you think that you should start?

If the perimeter is 24, then PS = QR  = (24 - 10)/ 2 = 14/2 = 7

And the area would be the height x PS = 28

So  h x 7 = 28    divide both sides by 7

h = 4  = ST

And RT =√[RS^2 - ST^2] =    √[5^2 - 4^2 ] = √9  = 3

So RT + QR  = 3 + 7 = 10

And ST = OQ = 4

So the perimeter of the rectangle =  2(10 + 4)  = 2(14)  = 28 units

3x² - 2x  =  27

Get all the terms to one side; subtract 27 from both sides:

3x² - 2x - 27  =  0

Factor, if posible. If not, use the quadratic formula:

x = [ -b ± √( b² - 4ac) ] / (2a)       a = 3     b = -2     c = -27

x = [ -(-2) ± √( (-2)² - 4(3)(-27)) ] / (2(3))   

x =  [ 2 ± √( 328 ) ] / 6  =  [ 2 ± 2√( 82 ) ] / 6  =  [ 1 ± √( 82 ) ] / 3

To get the tax you have to do 8.75x97.50 then did the answer by 100 to get 8.53125 as the tax but because it's money you have to round to the nearest hundredth so it would be $8.53 for the tax. To get the total bill you just do 8.53+97.50 and get 106.03.

sinA = 16/18

angle A = 62.73^o

FH = 27*sin62.73^o

FH = 24

Same answer, but I like yours better, geno! 

It seems from Chris's answer that maybe this is a continuation of an earlier problem.

If that is the case can you please just continue on the same thread next time.

If you think it will help you can draw our attention to it with a new post that just has the address of the old post pasted into it  asking us to go back and take another look. 

It is much better if all questions and answers to it stay on the same thread. :)

Let  x  represent last year's taxes.

Since the taxes went up by 15%, the increase in taxes was 15% of x  or  0.15·x

This year's taxes is last year's taxes plus the increase:  x + 0.15x     which is 1.15x.

So:  1.15x = 287.50

Divide by 1.15   --->   x = $250.00