All Answers 358134 Answers

the calculator is on the home page :)

I've got another idea.

The circumference is  pi* diameter.

pi is about 3

SO

If the circumference is 30 inches then the diameter must be about 30/3 = 10 inches (that is a little less than a foot)

Which of those is a bit less than 1 foot across ?

GOOD WORK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

EMINEM THE RAP GOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

That is a great diagram and explanation Zac :)

Yours is good too DarkBlaze347                            

I like the answers that you are giving DarkBlaze347.  Askers should do some work for themselves :)

NEXT POST: TOMORROW!!!!!!!!!!!!!!!!!!!

PSDT- IT IS A PUBLIC CHAT ROOM, BUT JUST FOR MUSIC THEMES OR OTHER SIMILAR, BUT PLEASE DONT SPAMM.

I enjoyed your you tube clip Dbg     

$$\sum$$      is the greek letter Capital Sigma

In mathematics it means 'sum of'

for example

$$\\\displaystyle \sum_{n=2}^5\;n\;\;=2+3+4+5=14\\\\\\
\displaystyle \sum_{n=1}^5\;4n\;\;=4*1+4*2+4*3+4*4+4*5=4+8+12+16+20 =60\\\\$$

Good answer DarkBlaze347

better now???????????

im working on it...

give me 5 minutes

 cool whenis the first one

frikkn hard

Geno's interpretation is valid but I interpreted it differently.

$$\\(4.0*10^{-1}) \div (8.0*10^{-4} )\\\\
=\frac{(4.0*10^{-1}) }{ (8.0*10^{-4} )}\\\\
=\frac{4}{ 8}*\frac{10^{-1} }{ 10^{-4} }\\\\
=\frac{1}{ 2}*10^{-1--4} \\\\
=0.5*10^{3} \\\\
=500 \\\\$$

The cat hair is 500 times thicker than the human hair  :)   

That sounds like an awful lot - That cat sure have fat hairs!

Anonymous people are no longer alllowed to post links or pictures.  

I suggest that you become a member :)

From the figure shown below, DE is the diameter of circle A and BC is the radius of circle B. If DE = 60 cm and AC = 10 cm, find the area of the shaded region

$$h=\overline{AC}=10~\rm{cm}
\qquad r_{A} = \frac{ \overline{DE} }{2}= 30~\rm{cm}
\qquad r_{B} = \overline{CB} \\\\
r_A^2 = h\cdot(2\cdot r_B-h)\qquad \Rightarrow\qquad
r_B = \frac{h+\dfrac{r_A^2}{h} }{2}=\frac {10+90}{2}= 50 ~\rm{cm}\\\\
\small{\text{Angle DBE $=B
\qquad B\ensurement{^{\circ}} = 2\cdot\arcsin{ \left( \dfrac{r_A}{r_B} \right)} $}} \\\\
\small{ A_{Blue}= \pi\cdot r_B^2 - \pi \frac{\cdot r_A^2}{2}
-\left[
\pi \cdot r_B^2 \cdot \frac{B\ensurement{^{\circ}} } { 360\ensurement{^{\circ}} } - \frac{1}{2}\cdot (2\cdot r_A)\cdot(r_B - h)
\right]
$}} \\\\
\small{ A_{Blue}= \pi\cdot r_B^2 - \pi \frac{\cdot r_A^2}{2}
-\left[
\pi \cdot r_B^2 \cdot \frac{ 2\cdot\arcsin{ \left( \dfrac{r_A}{r_B} \right)} } { 360\ensurement{^{\circ}} } - \frac{1}{2}\cdot (2\cdot r_A)\cdot(r_B - h)
\right]
$}} \\\\
\small{ A_{Blue}= \pi\cdot r_B^2 - \pi \frac{\cdot r_A^2}{2}
-\left[
\pi \cdot r_B^2 \cdot \frac{ \arcsin{ \left( \dfrac{r_A}{r_B} \right)} } { 180\ensurement{^{\circ}} } - r_A\cdot(r_B - h)
\right]
$}}$$

$$\small{ A_{Blue}= \pi\cdot r_B^2
\left(
1- \frac{ \arcsin{ \left( \dfrac{r_A}{r_B} \right)} } { 180\ensurement{^{\circ}} }
\right)
- \pi \frac{\cdot r_A^2}{2}+ r_A\cdot(r_B - h)
\right]
$}} \\\\
\small{ A_{Blue}= \pi\cdot 50^2
\left(
1- \frac{ \arcsin{ \left( \dfrac{30}{50} \right)} } { 180\ensurement{^{\circ}} }
\right)
- \pi \frac{\cdot 30^2}{2}+ 30\cdot(50 - 10)
\right]
$}} \\\\
\small{ A_{Blue}= \pi\cdot 50^2\cdot
0.7951672353008667 - \pi \frac{\cdot 30^2}{2}+ 1200\right]
$}} \\\\
\small{ A_{Blue}= 6031.5121678758663628914 ~\rm{cm^2}
$}}\\\\
A_{Blue} \approx 6031.5122 ~\rm{cm^2}$$

Yes there is an app for your android phone.    

Anon, I think it is you that has dyslexia !!  

Or perhaps it is just CRD    (Chronic rudeness disease)!   You should get that looked at!

$$\\y=2012^{2012}\\\\
log y=log(2012^{2012})\\\\
log y=2012log(2012)\\\\$$

$${\mathtt{2\,012}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{2\,012}}\right) = {\mathtt{6\,646.899\: \!488\: \!484\: \!386\: \!68}}$$

$$\\log y = 6646.89948848438668\\\\
y=10^{6646.89948848438668}\\\\
y=10^{6646}*10^{0.89948848438668}\\\\
y=10^{0.89948848438668}*10^{6646}\\\\$$

$${{\mathtt{10}}}^{\left({\mathtt{0.899\: \!488\: \!484\: \!386\: \!68}}\right)} = {\mathtt{7.933\: \!932\: \!191\: \!378\: \!429\: \!9}}$$

so

$$\\2012^{2012}=7.9339321913784299 \times 10^{6646}$$

That is an approximations  :)

I learned to do this from CPhill.    Thanks Chris  

Very, very nice anon,

One more step is needed :)

$$\\-7 \ge x\\
x\le-7$$

When you swap sides you have to turn the inequality around  :)

Pressing equals twice on the Web2 calculator often works    :/

$${\mathtt{0.54}} = {\frac{{\mathtt{27}}}{{\mathtt{50}}}}$$

This is a fabulous answer, thanks MathsGod1

Look at all your brilliant LaTex too   :)))

I like it Zegroes can be Zeros!!!

He will be stuck inside Sisyphus's boulder for ever.

On second thoughts, I like having him about.  He better stay Zegroes afterall !

Hi Kitty,

It is great to see you in Camelot !!

 All Princesses should visit the Realm of their birth sometimes :)

84%  ???...that's not bad, Z-Man.....!!!!

Good luck to you MG  :))