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@@ End of Day Wrap   Mon 25/5/15   Sydney, Australia Time   1:50am  (Really Tues morn) ♪ ♫

Hi all,

Our stupendous answers today were presented by Zegroes, TitaniumRome, CPhill, Zegroes, MathsGod1, Thejamesmachine, Andrew1714, Didig, Mathcad, Zacismyname, Alan, Derrickid, Rosala, Awsomeee and Civonamzuk.  Thank you all   

.666666.....   = 6/9  = 2/3

And  .606060.....  = 60/99

So

(2/3) (60/99)  =  (2/99)(60/3) = (2/99)(20) = 40/99 = .040404.........

So.......the sum of the first 15 digits  = 7(4) + 7(0) + 0 = 28

You should not EXPECT to be answered at all!  

You are not paying for any service here.  

Any help at all that you get should be considered a bonus!

You are very rude Awsomeee!

$${\mathtt{9\,087}}{\mathtt{\,\times\,}}{\mathtt{2\,098}} = {\mathtt{19\,064\,526}}$$

what is 75 percent of 405

@rosala:/ Your answer is only 50%  correct!

A 100% correct  answer is:>       75%  of  405  is  303.75  

ohhh...the awnser is 55-LOL ANSWERED MY OWN QUESTION!!

Tues 26/5/15

If you would like to comment on other site issues please do so on the Lantern Thread.  Thank you.    

Interest Posts:

FTJ means 'For the juniors' 

ok.....? ummm...

wow... LOL

I corrected...

Sorry for bad english, I know that you are both ladies...

You mean her and her. Were both ladies, lol.

Thanks Dbg,

I enjoy watching and listening to your music clips.

I didn't enjoy your first eminem one so much as you but I did enjoy Sheppard, I listened to another of their songs.  :)

Thanks for the Beethoven tribute.  I suppose it is well known on the forum that I like classical music.

Here is a famous piano peice by Beethoven.

It is "Moonlight Sonata"  

The pianist, Valentia Lisitsa looks like she is carressing the piano keys with her very long fingers.     

HAHAHA!!!....love that pic, Dbg.....!!!........{and the info on Ludwig van.....}

IMPORTANT ADVISORI!!!!!!!!!!!!!

THERE ARE MORE STICKY QUESTIONS ON THE FORUM, LIKE HEATHERF WITH HER    

" FORUM NEWS CHANNEL 21 REPORT (( MORE LESS )), AND MELODY WITH HER END OF A DAY WRAP... COMMENT IT, THYRE GOOD!!

size of angle x when the opp is 4.5 ad adj is 11?

tan(x) = 4.5/11

x = 22.25^o

10r+r^2=120     rearrange

r^2 + 10r  - 120pi = 0     ........using the onsite solver, we have...

$${{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{r}}{\mathtt{\,-\,}}{\mathtt{120}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{r}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{5}}\\
{\mathtt{r}} = {\sqrt{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{5}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{r}} = -{\mathtt{25.049\: \!716\: \!168\: \!334\: \!532}}\\
{\mathtt{r}} = {\mathtt{15.049\: \!716\: \!168\: \!334\: \!532}}\\
\end{array} \right\}$$

i agree. that is called patient....im in the same condition when my test is above the head!

We can write this  infinite sum, thusly......

S = a₁ / [1 - d]    where a₁ is the first term and "d" is the common difference ...(1/5) in this case...so we have

(1/5) / [ 1 - 1/5)  =   (1/5) / (4/5)  =  (1/4)  = .25

Thanks Chris 

.511111...... =   [51 - 0] / 99  =   51/99

ok that makes sense Alan.   Thanks     

So I have to remember that the gravitational force is the hypotenuse!    I shall try  

That's a weird graph, Melody  !!!!!......good answer.....

$$\\81=6^x+2x-8x\\
81=6^x-6x\\$$