We have 12 girls and we can pick any three.....and we have 10 boys and we can pick any three
So C(12,3) * C(10,3) = 26,400 ways
Headingnorth's answer would have been correct if he/she had divided each of the products in both sets of parentheses by 3!........The reason for this is, for example, the set of {Ted, Bob, Dave} would be the same as (Bob, Ted, Dave}......and there are 3! = 6 arrangements of this set....but....it's basically the same set.......without the division by 3! in both cases, we're "overcounting" by a factor of 6 x 6 = 36......
{That's OK, Headingnorth, it was a really good try !!! .....I still gave you 3 points !!! }