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The answer is 15.

I guess we have to make one other assumption, here.....that a cannibal remaining in the boat actually isn't on the "side" of the river......if not....there's no way to solve this....to see why.....note that........

One the first crossing.......there are either....

a) Two cannibals in the boat and one gets let out......but now there is one more cannibal on a side of the river than a photog......and this violates the original condition

b) There are two photogs in the boat.....and this will clearly violate the original condition, since there are 3 cannibals and 1  photog at the starting point......

c) There is one cannibal and one photog in the boat.......the photog has to be let off......because, if the cannibal was let off, there again would be one more cannibal on a side than a photog

I actually think the problem means to say that, if there are cannibals and photogs together on either side of the river,  the cannibals cannot ever outnumber the photogs. Thus, we could have a situation where a lone cannibal (or two together) is/are on one side of the river and no photogs on that side ......(since there is nobody to eat in that situation).....!!!

I am here!

If K(H) = 0 , this implies that.....

-((x^2+1)^2) + 4  = 0   multiply both sides by -1

(x^2+1)^2 - 4  = 0    simplify

(x^2 + 1)^2  = 4    and by the square root property, we have

x^2 + 1  = ± 2     subtract 1 from both sides

x^2  =  ± 2 - 1   ....so either.....

x^2  = -3    .......which leads to two  "non-real " solutions   ....  or .....

x^2  = 1    so that, using the square root property again,   x = ± 1

And these are the two "real" solutions.....check that they make the specified condition true .........

3sin2x=2cos^2x+1   

There are  8 parts......Mick gets 5/8 and Sharon gets the remainder.....

So (5/8)(12)  = 60/8  = £ 7.5

And Sharon gets  [12 - 7.5] = £ 4.5

Hey, ND.....good to see you back....don't be a stranger !!!!!

First, you have to turn both of these into improper fractions.

1 2/3 = 3/3 + 2/3 = 5/3

1 3/4 = 4/4 + 3/4 = 7/4

Now we have 5/3 divided by 7/4, and remeber if you want to divide to fractions you multiply by the reciprocal.

So we flip the second fraction.

$$\frac{5}{3} \times \frac{4}{7}$$

Then multiply the tops and bottoms together.

$$\frac{5 \times 4}{3 \times 7} = \mathbf{\frac{20}{21}}$$

The square root of 95 cannot be simplified any further, but you can get a decimal aproximation. 

That'd be about 

$${{\mathtt{95}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)} = {\mathtt{9.746\: \!794\: \!344\: \!808\: \!963\: \!9}}$$

It'd probably be best to use the slope intercept form here. 

That is:

y = mx + b

where m = slope

and b = the y intercept

So basically all you have to do is put in the slope and the y intercept (which is 0, because it goes through the origin) and your done

So you'll end up with

y = (7)x + (0)

or just y = 7x.

2 / (2x + 4)            exclude 2

= 2 / 2(x + 2)         shorten 2/2 = 1/1

= 1 / (x + 2)

2 / (2x + 4) = 1 / (x + 2)

Greeting asinus  :- )

any one ? 

Yeah I doubt it.

I've been here since March and I've never seen them.

I know they were past users.

They probably left the forum...

Maybe busbusy with life or something...

Maybe they forgot her password, but I can talk with you...

I connect everyday...

Thank u thank u

Your way contains more logic than mines.

As smart your method is I prefer the inversway, way it seems easier.

your welcome Melody.......i should say...these are the latest ones!

The eggs are so cool...

GOOD WORK!!!!!!

ah you cant beat me..a tie is fine but not a beating!

32x + 53 = 501

32x = 501 - 53

32x = 448

x = 448/32

x = 14

yeah....way more easy to understand ..hows this MG?

I think so rosala.

Do the inverse.

$${\mathtt{501}}{\mathtt{\,-\,}}{\mathtt{53}} = {\mathtt{448}}$$

$${\frac{{\mathtt{448}}}{{\mathtt{32}}}} = {\mathtt{14}}$$

X=14

Thanks Rosala,

Those dinasaur shoes are the BEST !!!

and that little dog looks just a tad guilty.  LOL  

that is the time when all the blessing of the bus driver come in use.....when we curse him so much!lol

Same here!

I love those mini pictures, the bus one is jokes!

Same face here.

So many times the poles have saved me.

is that " * " represented as x?