cost = 4*14*23.11 dollars

You can use the calculator to crunch the numbers!

. 

If you mean f(x) = -4x² - x and you want to know f(3) then DarkBlaze347 has supplied the right answer.

.

28% = 28/100 = 0.28;  14% = 14/100 = 0.14;  8% = 8/100 = 0.08 so:

money = 0.28*250*3.65 + 0.14*250*1.2 + 0.08*250*7.5

$${\mathtt{money}} = \left({\mathtt{0.28}}{\mathtt{\,\times\,}}{\mathtt{3.65}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.14}}{\mathtt{\,\times\,}}{\mathtt{1.2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.08}}{\mathtt{\,\times\,}}{\mathtt{7.5}}\right){\mathtt{\,\times\,}}{\mathtt{250}} \Rightarrow {\mathtt{money}} = {\mathtt{447.5}}$$

money = $447.50

.

$$\small{\text{$
\mathbf{
a_{22} = -49 \quad \mathrm{and} \quad a_{25}= -58 \quad \mathrm{find} \quad a_1
}
$}}$$

$$\mathbf{
\mathrm{Explicit~ Formula:}
& \quad a_n = a_1 + (n-1)\cdot d
} \\\\
\small{\text{$
\begin{array}{lrcl}
& a_{22} &=& a_1 + 21 \cdot d \\
& a_{25} &=& a_1 + 24 \cdot d \\
\\
\hline
\\
& a_{22} - a_1 &=& 21 \cdot d \\
& a_{25} - a_1 &=& 24 \cdot d \\
\\
\hline
\\
& \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{21} {24}\\ \\
& \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{7} {8}\\\\
& 8\cdot ( a_{22} - a_1 ) &=& 7\cdot ( a_{25} - a_1 )\\
& 8\cdot a_{22} - 8\cdot a_1 &=& 7\cdot a_{25} - 7\cdot a_1\\
& 8\cdot a_1 - 7\cdot a_1 &=& 8\cdot a_{22} - 7\cdot a_{25} \\
& \mathbf{a_1} &\mathbf{=}& \mathbf{8\cdot a_{22} - 7\cdot a_{25}} \\\\
& a_1 &=& 8\cdot (-49) - 7 \cdot (-58 ) \\
& a_1 &=& -392 + 406 \\
& \mathbf{a_1} &\mathbf{=}& \mathbf{14}
\end{array}
$}}$$

If the area of a triangle is 36 5/6 feet and the base of the triangle is 6 1/2 feet, what is the height?

A = 36 5/6 ft²,        base (b) = 6 1/2           height (h) = ?

$${\mathtt{h}} = {\frac{{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{36}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{6}}}}\right)}{\left({\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)}}$$

$${\mathtt{h}} = {\frac{\left({\mathtt{73}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}{\left({\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)}}$$

$${\mathtt{h}} = {\frac{\left({\frac{{\mathtt{442}}}{{\mathtt{6}}}}\right)}{\left({\frac{{\mathtt{39}}}{{\mathtt{6}}}}\right)}}$$

$${\mathtt{h}} = {\frac{{\mathtt{2\,652}}}{{\mathtt{234}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

h = 11 1/3 ft

-2a^4b(-3ab^5(5a^-3b^-7) ) simplify

$$\small$\text{$
\begin{array}{rcl}
-2a^4\cdot b \left [-3\cdot ab^5 ( 5a^{-3}\cdot b^{-7} ) \right] \\\\
&=& -2a^4\cdot b \left (-3\cdot 5 \cdot a\cdot a^{-3}\cdot b^5 \cdot b^{-7} \right) \\\\
&=& -2a^4\cdot b \left (-15\cdot a^{1-3}\cdot b^{5-7} \right) \\\\
&=& -2a^4\cdot b \left (-15\cdot a^{-2}\cdot b^{-2} \right) \\\\
&=& (-2)\cdot(-15)\cdot a^4\cdot b \cdot a^{-2}\cdot b^{-2} \right) \\\\
&=& 30\cdot a^4\cdot b \cdot a^{-2}\cdot b^{-2} \\\\
&=& 30\cdot a^4\cdot a^{-2} \cdot b \cdot b^{-2} \\\\
&=& 30\cdot a^{4-2} \cdot b^{1-2} \\\\
&=& 30\cdot a^{2} \cdot b^{-1}
\end{array}
$}}$$

Here's a link for a similar question and answer:>  

http://web2.0calc.com/questions/an-hd-television-has-a-list-price-of-752-if-a-series-discount-of-10-15-is-offered-what-is-the-net-cost-after-the-series-discount-use-the

That is an approximation MG,

$$\sqrt2+2$$      is the real solution it cannot be simplified :)

No anon,

The multiplication MUST be done first!    PEDMAS

I have not seen it either except when I was given the link.

This took me to a page where the ad was. 

I DID NOT click into the ad. :)

Hi Civonamzuk,

I did not understand what that question meant but your interpretation looks really good.

I'd just like to expand a little.

50.4% of X = $504.00

So divide both sides by 50.4% to get X. (The original price)

If the net cost is $504, and the series discount is 10/20/30, what is the list price?

Net cost = $504,       Series discount:  10/20/30,         List price = ?

Net cost equivalent = 0.9*0.8*0.7 = 0.504    

List price = Net cost / Net cost equivalent

List price = 504/0.504 = 1000

              = $1000

$${\frac{{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{2}}}} = {\mathtt{23.561\: \!944\: \!901\: \!923\: \!449\: \!3}}$$

$${{\mathtt{3}}}^{{\mathtt{2}}} = {\mathtt{9}}$$

$${\mathtt{9}}{\mathtt{\,\times\,}}-{\mathtt{4}} = -{\mathtt{36}}$$

$${\mathtt{\,-\,}}{\mathtt{36}}{\mathtt{\,-\,}}{\mathtt{3}} = -{\mathtt{39}}$$

f(3)=-39.

Subtract both sides by 354: 2x=y-354.

Divide both sides by 2, and x=0.5y-177.

3+3x3-3+3

(3+3)*(3-3+3) = 18

$${\mathtt{170}}{\mathtt{\,\times\,}}{\mathtt{80}}\% = {\mathtt{136}}$$

y=3x-4

y=3x+3

Both lines have the same slope but different y-intercepts, so they are parallel but not the same line. There is no solution for this system.

-58 - (-49)  = -9     is the difference in these terms which seems to imply that  -9/3 = -3 is the common difference between terms

So......

-58  = a₁ + d(n - 1)              

-58   = a₁ - 3(25 - 1)

-58  = a₁ - 72    add 72 to both sides

14  = a₁

447.50

XD

that is HILLARIOUS!!!!!!!!!!

i havent, and titanium hasnt experienced it yet

we both have ad-free computers (except on youtube)

125km / 3600 sec = x / 0.8 sec     cross-multiply

(0.8 sec)(125 km) = (3600 sec)x        divide both sides by 3600 sec

(0.8)(125 km)/ 3600  = x = .02777 km = 27.77 m

100+100000000000 = 100000000100