All Answers 358098 Answers

Urgh...?

...

Nice answer Rosala! 

Rosala your summer holiday has ended?

Mines hasn't even started ... 16days left.

Yeah. Thank you so much for helping me!! 

$$\\$An area is the calculation of the inside of the shape$\\\\
$I'll answer each question from left to right starting from rectangle$\\\\
$Each square is 1cm^2\;\mathbf{approximately}\\\\
1)\;5cm^2\\\\
2)\;5cm^2\\\\
3)\;5cm^2\\\\
4)\;5cm^2\\\\
5)\;5cm^2\\\\
6)\;5cm^2\quad\\\\$$

$$\\$(This one was slightly harder, but i saw if you look at the row of the shape, which is 4 squares, it's half shaded diagnolly so approximately it's four, the bottom square on the left is fully shaded apart from the corner which is slightly not shaded approximately a square, the one to the left of the square i was just talking about matched perfectly with the square to left the left of that. As for the triangle at the bottom of the shape those two squares make 1. 2+1+1+1 =5)\\\\
This is the shape on the bottom right corner.$$$

Hi Mellie,

Thanks for the points:)

Did you understand our answers ?

Ok so there are 6 male  and 4 female to choose from.

P(at least 4 males) = 5*(6/10)*(5/9)*(4/8)*(3/7)*(4/6) + (6/10)*(5/9)*(4/8)*(3/7)*(2/6)

$${\mathtt{5}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{10}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{9}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{8}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{7}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{6}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{10}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{9}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{8}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{7}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{6}}}}\right) = {\frac{{\mathtt{11}}}{{\mathtt{42}}}} = {\mathtt{0.261\: \!904\: \!761\: \!904\: \!761\: \!9}}$$

lol looks like someones too serious about the game....paper beats rock only as it can cover the whole rock......but its not always that true.....

No it isnt.

its true that its 19 though

I can magically prove that 9+10=19 and not 21

Yea well I can ....now    LOL

Although I still get muddled as to whether it is dio or dia  

BUT then I think - no it is definitely not a diaphram  :))

The hypotenuse would have to be 15

3*3=9

4*3=12

5*3=15

5.2 × 10^7 + 7.25 × 10^6 + 1.8 × 10^7

=5.2 × 10^7 + 0.725 × 10^7 + 1.8 × 10^7

=(5.2  + 0.725  + 1.8 )× 10^7

=7.725*10^7

I think we should ask Mellie if she can actually spell "Diophantine"............LOL!!!!!

You showed me Heron's formula.       I still had to look it up though.   

I was going to do it the usual way which would not have been very difficult but then I thought it was the ideal situation for ME to use Heron's formula :))      

Thanks Chris, we both need more practice at these.

Has Mellie posted other diophantine equation questions ?  I think she has ://

Heron's Formula strikes, again  !!!!!!  ........ LOL!!!

Could be 8 kittens or 12 or 16 kittens.

Depends on if 2 adults have the same kittens ;/

It takes 2 to reproduce even if you are a cat :)

If the perimeter is 48 inches then each side is 8 inches.

The angle at the centre that subtends to adjacent vertices is 360/6 = 60degrees.

Therefore the hexagon consists of 6 equilateral triangles of sidelength 8 units.

Using Heron's formula

$$\\Area = 6 \;\; *\;\; \sqrt{s(s-a)(s-b)(s-c)}\qquad where\quad s=(a+b+c)/2\\\\
s=24/2=12\\\\
Area = 6 \;\; * \;\; \sqrt{12(12-8)(12-8)(12-8)}\\\\
Area = 6 \;\; * \;\; \sqrt{12*64}\\\\
Area = 6 \;\; * \;\; 8\sqrt{4*3}\\\\
Area = 6 \;\; * \;\; 16\sqrt{3}\\\\
Area = 96\sqrt{3}\;\;inches^2\\\\$$

Thanks for the lollipop, Melody......I'm going to add your answer to my "Watchlist" and look at it in more detail later......!!!!

Excuse me, if I may have the mic, I dont think that will happen today, Invisible Brad.

you see, I am the latest addition to the superhero line, and my ability is Level 6 Magic. I am able to make and use all kinds of magic, which means i can magically see you, Brad

and dr.minyak, i can magically make capt.man invulnerable to sad jolly beetle tears

and i can magically burn the sad tears

Thanks Alan,

Or if you are using a different calculator you can use the change of base rule

$$log_{1.1} (1000) =\frac{log1000}{log1.1}$$

you can use any base you like :)

$${\frac{{log}_{10}\left({\mathtt{1\,000}}\right)}{{log}_{10}\left({\mathtt{1.1}}\right)}} = {\mathtt{72.476\: \!573\: \!784\: \!290\: \!347\: \!8}}$$

A triangle, hmmm

180-30=150-55=95

the missing angle, or X, equals 95 degrees

Factor 

$$\\4(6x+8)+(3x^2+4x)\\\\
=4(6x+8)+x(3x+4)\\\\
=4\cdot 2(3x+4) + x(3x+4)\\\\
=8(3x+4) + x(3x+4)\\\\
=(3x+4)(8 + x)$$