All Answers 358098 Answers

i do that a lot, especially to your mom, Kid Danger. along with Ms.Swellview, Debbie's mom, etc.

well i guess flirting with girls was key to our victory over the vandalism gang known as the Wall Dogs, who damaged my playhouse as a kid even before I became indestructable

remember Veronica, Kid Danger, who most likely is your girlfriend now since she kissed you how many times, 7 times in a one hour episode?

she got distracted, and revealed the secret location of the Wall Dog's hideout for you, you spray painted the location on Jasper's back, then Charolette took a pic of Jasper's spray-painted back, sent it to me, and I found the base, took down Van Del, and the Wall Dogs ganbg is disbanned, for now

while you let Veronica live without going to jail, shot that helicopter's lights down

Thanks Chris,  I also would like to try this one.

We have this situation 

Let X be the number of scoops in and Y be the number of scoops out,  so X and Y are integers

$$46899X-13567Y=1$$      This is a diophantine equation because the solutions must be integers.

I'll rearrange this

$$\\46899X=13576Y+1\\\\
\frac{46899}{13576}*X=Y+\frac{1}{13576}\\\\
$I need the fraction part to be a proper fraction$
\frac{(3*13576+6171)}{13576}*X=Y+\frac{1}{13576}\\\\
3X+\frac{6171}{13576}*X=Y+\frac{1}{13576}\\\\
\frac{6171}{13576}*X=Y-3X+\frac{1}{13576}\\\\$$

Y-3X is an integer so I am going to replace it with Z  (I only care that it is an integer)

$$\\\frac{6171}{13576}*X=Z+\frac{1}{13576}\\\\
So\\
6171*X = 1 Mod\; 13576\\\\
X = \frac{1}{6171}\; Mod\; 13576\\\\
X = 6171^{-1}\;\; Mod\; 13576\\\\\\
$Now I am going to use the $ \underline{Euclidean\; Algorithm} \\\\
\begin{array}{rllll}
13576&=&\underline{6171}*2+\underline{1234}\qquad&(1a)\quad &1234=13576-6171*2\\\\
6171&=&\underline{1234}*5+\underline{1}\qquad&(2a)\quad &1=6171-1234*5\\\\
\end{array}
$I can stop the Euclidean algorithm now because I have the 1 that I wanted$\\\\
$Now I am going to use the \underline{Extended Euclidean Algorithm} and go 'backwards' :)$\\\\$$

$$\\\frac{6171}{13567}*X=Z+\frac{1}{13567}\\\\
So\\
6171*X = 1 Mod\; 13567\\\\
X = \frac{1}{6171}\; Mod\; 13567\\\\
X = 6171^{-1}\;\; Mod\; 13567\\\\\\
$Now I am going to use the Euclidean Algorithm$ \\\\
\begin{array}{rllll}
13576&=&\underline{6171}*2+\underline{1234}\qquad&(1a)\quad &1234=13576-6171*2\\\\
6171&=&\underline{1234}*5+\underline{1}\qquad&(2a)\quad &1=6171-1234*5\\\\
\end{array}
$I can stop the Euclidean algorithm now because I have the 1 that I wanted$\\\\
$Now I am going to use the extended Euclidean Algorithm and go 'backwards' :)$\\\\
\begin{array}{rllll}
1&=&6171-1234*5\qquad &(2b)\\\\
1&=&6171-(13576-6171*2)*5\qquad &(2a)\\\\
1&=&6171-5*13576+5*6171*2\qquad &(2a)\\\\
1&=&6171-5*13576+10*6171\qquad &(2a)\\\\
1&=&11*6171-5*13576\qquad &(2a)\\\\
&&$now 5*13576 mod 13576=0 so$\\\\
1&=&11*6171\\\\
\end{array}$$

So X=11

The number of scoops in is  11+13576N

But each scoop in is 46899 peices.

46899*(11+13576N)<600000

(11+13576N)<12.79

N has to be 0

SO  

The number of scoops in MUST be 11.        

Here are 3 lollipops, one for me, one for CPhill and one for Mellie.  

BECAUSE WE DESERVE THEM  

I just realized that some otf the LaTex was not displaying.

Hopefully there is no more problems.

I'm not sure what you're asking, here......

also, dr. maniac, go get a profile picture if you arent cowardice.

and invisible brad. post a pic of that selfie you took with capt. man. that one was goooood

wow, what would Capt. Man say now about poor Tommy getting an F on his last test?

he tried to be my dad for 3 days, and complained that I had a C+ in History

and Ms.Shapen always tries to put my history test score in front of my locker (which is an F obviously cuz im too busy with crime fighting, making my family chili meatballs, which are not spicy, and school homework and school tests, along with science projects)

Simplify  Express your answer in simplest radical form in terms of .

$$\boxed{~~ \text{Formula: } \sqrt[n]{a\cdot b}
= \sqrt[n]{a}\cdot \sqrt[n]{b} ~~}$$

$$\root 3 \of {x \root 3 \of {x \root 3 \of {x \sqrt{x}}}} \\\\
= \root 3 \of {x} \cdot \root 3 \of {\root 3 \of {x \root 3 \of {x \sqrt{x}}}}\\\\
=
\root 3 \of {x} \cdot
\root 9 \of {x \root 3 \of {x \sqrt{x}}}\\\\
=
\root 3 \of {x} \cdot
\root 9 \of {x} \cdot
\root 9 \of {\root 3 \of {x \sqrt{x}}}\\\\
=
\root 3 \of {x} \cdot
\root 9 \of {x} \cdot
\root 27 \of {x \sqrt{x}}\\\\
=
\root 3 \of {x} \cdot
\root 9 \of {x} \cdot
\root 27 \of {x} \cdot
\root 27 \of {\sqrt{x}}\\\\
=
\root 3 \of {x} \cdot
\root 9 \of {x} \cdot
\root 27 \of {x} \cdot
\root 54 \of {x}\\\\
=
x^{\frac13}
\cdot x^{\frac19}
\cdot x^{\frac1{27}}
\cdot x^{\frac1{54}}\\\\
=
x^{\frac13+\frac19+\frac1{27}+ \frac1{54}}\\\\
=
x^{\frac13 \cdot \frac{18}{18}
+\frac19 \cdot \frac{6}{6}
+\frac1{27} \cdot \frac{2}{2} + \frac1{54}}\\\\
=x^{\frac{18+6+2+1}{54} } \\\\$$

$$\\=x^{\frac{27}{54}}\\\\
=x^{\frac{1}{2} } \\\\
\mathbf{= \sqrt{x}}$$

flirting?heh

guys these days just want more girls ;)

thats probably the new rule of life

hold up, let me drink this gatorade fruit punch

it allows me to punch you in the face (that's why i only drink fruit punches, no cherry, apple, lime, orage, etc.)

i already defeated a tempting girl, and now my next challenge is Invisible Brad and Dr. Maniac? why couldn't it be Veronica or that upcoming history test?

hey brad, want to go for a city walk around down town swellview and get some root beers?

dr.maniac i will figure out how to get rid of you later

Enter  log(1000,1.1)

i.e. enter log(number, base)

.

Not in this world!

9*9 -6*(-7) = 81 + 42 = 123

.

52 kg * 9.8 m/s² =  509.6 $${\frac{{\mathtt{kg}}{\mathtt{\,\times\,}}{\mathtt{m}}}{{{\mathtt{s}}}^{{\mathtt{2}}}}}$$   = 509.6 N   (Newton )

You need to register in order to upload images.

.

The n'th term of a geometric sequence is given by a*r^n-1, where a is the first term and r is the common ratio.

(1/3)r^8-1 = 128/3

r⁷ = 128

So r = 2

.

What are you after here?  

Are k and i just variables?  

Does   $$i=\sqrt{-1}$$    ????

1/10 ki power 1/3

$$(\frac{ki}{10})^{1/3}=\sqrt[3]{\frac{ki}{10}}$$

You can't possibly have "x = 9x" unless x is 0.

9x / (5*4) can be re-written:

9x / (5*4)

= 9x / 20

= (9/20) x

= 0.45x

Easier way:

90*4=360

81.5*5=407.5

lowest possible for test 4 = 407.5-360=47.5

But lowest possible integer result is 48

Any more reduction - any takers ?      LOL

Tom took five math tests and got an integer score on each of them. He never scored higher than 90, and his lowest score was the fourth test. If his average score, rounded to the nearest integer, was 82, what is the lowest possible score he could have gotten on the fourth test?

The average could have been between 81.5 and 82.5

Say he scored 90 on all the other tests that is a total of 360 for the four other tests

so

$$\\81.5\le \frac{360+fourth}{5}<82.5\\\\
407.5\le 360+fourth<412.5\\\\
47.5\le fourth<52.5\\\\
$But all the scores were integers so$\\\\
$the lowest possible score for the fourth test was $ 48$$

@@ End of Day Wrap  Wed 1/7/15   Sydney, Australia Time   6:00pm  ♪ ♫

Hi all,

Our great answers today were provided by CPhill, Fiora, Zacismyname, TitaniumRome, Sir-Emo-Chappington, Rosala, KidDanger and Alan.  Thank you  

This quadrilateral is a parallelogram and two of the sides are parallel to the x axis.  

That is why it was so easy for CPhill to determine the area :)

Good thinking Radix  

Complementary angles add to 90

and

Supplementary angles add to 180.                  (just like Chris said)

If you can remember the 2 words it is easy to know which is which because 

2 C's make an S     (one reflected and sitting on top of the other one)          and 2*90=180

Radix has assumed you want, say, (tan θ)^-1

If, instead, you meant tan^-1x  (i.e. the angle whose tangent is x) then choose atan (press 2nd then atan on the calculator here), which is the same thing.

.

Quit your job, Henry!