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No prob, Lunar.......

√​6​​​⋅(8√​42​​​+5√​30​​​)  =

√​6​​​⋅ [8√6*√7 + 5√​6*√​5]  =

6*8√​7 + 6*5*√​5 =

48√​7 + 30√​5

Thanks alot!

For x = (-2)^-3  solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x

x = (-2)^(-3)   = 1 / (-2)^3   = -1/8     so we have

A = [ (-1/8) - 2] [ (-1/8) + 5 ] - [ (-1/8) - 4 ] [(-1/8) + 3] + 4 [ -1/8 ]

A  = [ -17/8] [39/8] - [ -33/8][ 23/8] - 1/2 

A = [ -663 / 64] + [759/64] - 32/64 

A = [ 759 - 663 -  32 ] / 64 

A = 64 / 64  

A = 1

The result of all those expressions=1

2.89x4.01=11.5889

what is 8.6602540378443865 in radical form. It's the aquare root of 75. You should fave squared it and we would have 75=5sqrt(3).

66,473+(13,752*76)+(50,033*178)-(6,755*21)

Look at how I adjusted it. Is that what you want? If so, then the answer is:9,875,644

x / 6 = 10     multiply both sides by 6

x = 60

I'm not sure what you want here.....but.....this can also be written as (ab)^3

CPhill: What is the kid asking? The sum of "1's" in that expression? Shouldn't it be 4?.

The unit digits sum = 5

149+98+1243-2000+678-111=57. I just followed the order in which it is written. Some people may NOT agree with this. Consult your teacher.

1^2  = 1

2^2  = 4

3^2 = 9

4^2 = 16

etc.

[They are just the squares of the first N positive integers]

2 X 2=4,  3 X 3=9,  4 X 4=16,  5 X 5=25.......etc.The products of 4, 9, 16, 25 are perfect squares.

2/2/3 - 2/3/2= If I understand what you want: 1/3 - 1/3=0

Thank you I'm find now and not only Christians pray , the whole world does:)

sorry tin I thought I'd replied you but you should atleast remember your so called enemies birthday, shouldn't you?

How to calculate 49!/(49-3)!3! to get the answer

49!/ (49-3)!*3!=(49 X 48 X 47)/(3 X 2 X1)=18,424

Thanks for that website reference, Guest.......I  never realized that the perimeter of an ellipse  was such a difficult thing to calculate.......!!!!!

34/(cot 34+cot 18)=34 / (1.48256 + 3.07768)=34/4.56024=7.45575

Here's the worked out solution.........

x^2 + 6y = 17    →     y = [17 - x^2] / 6 

y^2 + 4z = 1    →       z = [ 1  - y^2 ] / 4 →   z =  [ 1 -  [(17 - x^2)/6]^2]^2/4

z^2 + 2x = 2  →        [ 1 - (1 - [(17 - x^2)/6]^2)]^2 + 2x  = 2       (3)

Using  (3).....we have

  [ 1 -  [(17 - x^2)/6]^2)]^2 / 4 + 2x  = 2

[ 1 - [ 289 - 34x^2 + x^4]/ 36]^2 /16  + 2x = 2   simplify

[(1/36) (-x^4 + 34x^2 - 289) + 1]^2 / 16  + 2x = 2

[ 1 / 20736] [ (-x^4 + 34x^2 - 289) + 36]^2 + 2x = 2

[ -x^4 + 34x^2 - 253]^2 / 20736  + 2x  = 2

[x^8 -68x^6 +1662x^4-17204x^2 + 64009] / 20736  + 2x  = 2

[x^8 -68x^6 +1662x^4-17204x^2 + 41472x +  64009]  / 20736   = 2

[x^8 -68x^6 +1662x^4-17204x^2 + 41472x +  64009]  = 41472

x^8 -68x^6 + 1662x^4 - 17204x^2 + 41472x + 64009 - 41472 = 0

x^8 -68x^6 + 1662x^4 - 17204x^2 + 41472x + 22537 = 0

Kes, this will be too difficult to solve algebraically........we can either find the real solutions by a graph or by using a solver........WolframAlpha gives the real solutions of :

x ≈ -6.42773      and     x = -0.458115

So  x^2   = either ≈  41.3157129529    or   ≈  0.209869353225

And     x^2 +  6y  = 17   ....so........

41.3157129529 + 6y = 17   →  y ≈ -4.0526   → y^2 ≈  16.42356676     .......or......

0.209869353225 + 6y = 17  →  y ≈ 2.798   → y^2 ≈  7.829

And y^2 + 4z = 1    →   16.42356676 + 4z = 1  → z  ≈ 3.856 → z^2  ≈ 14.869    .....or......

 7.829 + 4z  = 1  →  z ≈ -1.707     →  z^2 ≈  2.914

So...in one case   x^2 + y^2 + z^2  =    41.3157129529 +   16.42356676  +  14.869  = 72.6082797129

OR

x^2 + y^2 + z^2  =    0.209869353225 + 7.829  + 2.914  = 10.952869353225

its 19

One half times five times four= 1/2 X 5 X 4=20/2=10 which is your answer.

-|-101| absolute value=101