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No, that is NOT right!!. Remember, as the spaceship travels closer and closer to the speed of light, time and ALL clocks on the ship SLOW DOWN. So that, at the speed of light TIME comes to a standstill. At .99c the ratio of time between Earth and spaceship is 7.09:1

Remember something called the "twin paradox?", which says that if you had a twin and one tavelled on spaceship @.999999c, for every 1 year on the spaceship, 707.11 years would have passed on Earth, and the twin that stayed on Earth would have been dead a long time ago. 

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57.6

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Why be mean about it

well idk but 20 out of 16 is 1.25

The answer told em that 0.427 years passed on earth. If you go on this website and look into number 7 the answe is 0.427, I too got 24 but the tect say its 0.427 years which doesn'T make sense.

8% of 720=8/100=.08 X 720=57.6

what is the simplest form of -3 99/100

=-3.99 that is the simplest form. You could also multiply it by 100/100=-399/100

Here you go:1.7724538509055160272981674833411.....................etc.

what is (0.05/12) as an integer?

The answer is NOT an intreger but a small fraction, which is:

=1/240

Multiply (3)(−4)(2)=-24

4% of 70.00=4/100 X 70=2.80

3 years on a spaceship travelling @ .99c would be equivalent to 21.27 years passed on Earth.

You need a numerical approach here.  There are two solutions.  Here is a simple way to iterate towards them:

. 

to die.

3*lg2 → lg2³ → lg8

so 3lg2 + lgx → lg8 + lgx → lg(8x)

so lg(8x) = lg7

so 8x = 7

so x = 7/8

thx

what is 8% of $90.00

8/100=.08

.08 X 90=$7.20

Your equation is missing something.

(9q4-7q3-3)+(6q4-3q-5)

Simplify the following:
9 q^4+6 q^4-7 q^3-3 q-5-3

Grouping like terms, 9 q^4+6 q^4-7 q^3-3 q-5-3 = (9 q^4+6 q^4)-7 q^3-3 q+(-3-5):
(9 q^4+6 q^4)-7 q^3-3 q+(-3-5)

9 q^4+6 q^4 = 15 q^4:
15 q^4-7 q^3-3 q+(-3-5)

-3-5 = -8:
Answer: | 
| 15q^4-7q^3-3q+-8

Here lies poor Melody

Death be now her Boss

Not smothered by an asteroid

But tangled up in Floss

Yes, I'm  am afraid

We'll see our Mel no more

Gee.....I'm gonna' really miss

That poor old dinosaur......

141=4(-7m+8)-3

Solve for m:
141 = 4 (8-7 m)-3

4 (8-7 m) = 32-28 m:
141 = 32-28 m-3

Add like terms. 32-3  =  29:
141 = 29-28 m

141 = 29-28 m is equivalent to 29-28 m = 141:
Answer: | 
| 29-28 m = 141

m=-4