1200=250(1+x/12)^4.2 how do you find x?
Let (1+x/12)=n, substitute,
1200=250 X n^4.2, divide both sides by 250,
4.8=n^4.2, take the log of 4.8
0.68124=4.2 X n divide both sides by 4.2
n=.1622, this is the log of base 10
n=10^.1622
n=1.452780, but n=(1+x/12), so we have:
1.452780=1+x/12, subtract 1 from both sides,
.452780=x/12, multiply both sides by 12
x=5.4334