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Well to get that you do 30/.20=150

69 * 65=4485

A typo in:U^2+4U+U=U^2+64, Should read:

:U^2+4U+4=U^2+64

Let U=be the unknown side, the we have the hypotenuse:

U + 2. Now we use Pythogoras' theorem:

(U + 2)^2=U^2 + 8^2

U^2+4U+U=U^2+64,

Solve for U:
(U+2)^2 = U^2+64

Subtract U^2+64 from both sides:
-64-U^2+(U+2)^2 = 0

Expand out terms of the left hand side:
4 U-60 = 0

Factor constant terms from the left hand side:
4 (U-15) = 0

Divide both sides by 4:
U-15 = 0

Add 15 to both sides:
Answer: |  U = 15 feet          Hypotenuse=15+2=17feet

4+4+5+225+23+?=267

4+4+5+225+23+26=267

A rectangular table is three times as long as it is wide.If thearea is 108ft^2, find the legth and the width of the table.

L=3w

L * w = 108

3w * w = 108

w*w = 108/3

w*w=36

w=sqrt(36)=6

L=3*6 = 18

width is 6 feet and length is 18 feet

check

6*18=108ft^2      

The product of two consecutive even integers is 168. Find the integers.

The positive set of correct answer is_12, 14__.

(use a comma t separate answers as needed.)

The negative set of correct answer is -12, -14_.

(use a comma to seperate answers as needed)

Welcome.

What was your score on the test?

Limited
Countless number 630/429 between two numbers relative to two digits after the comma

The translation is not very clear

but

630 / 429 = 1.4685....

this is between

1.46  and  1.47

To two decimal places is is equal to 1.47

I hope that helps.   

الترجمة ليست واضحة جدا
لكن
630/429 = 1.4685 ....
هذا هو بين
1.46 و 1.47
إلى منزلتين عشريتين وتساوي 1.47
وآمل أن يساعد.
 

Yes. That's what happened to me and Alan. Same problem.

Can you solve my math question please?

(1+0.021/12)^1-1

Any number to the power of 1 stays the same so this is

1 + 0.021/12.  - 1

=  0 021/12

= 21/12000

=0.00175

Why would your calc say 2.1?

Thanks havn't learned this rule set yet, but still thank you!

(x + 4) ( x - 12)

21?

x=1

x+x=2

1+1=2

Well.....buubleman......I see that since each side must be an integer quantity and AC > 16......the next integer would be 17

So  AB would be 14 more than this = 31

And BC would be 30 more = 47

So........ 17 + 31 + 47 =   95

thats getting old

Go online and use this good fraction calculator and see if you get the answer:

http://www.calculatorsoup.com/calculators/math/fractions.php

what is 7-?=92 what is the qustion mark

7 - ?=92 move 7 to the RHS and change its sign from + to -

-?=92 - 7

-?=85 multiply both sides by -1

?= -85 which is your answer, because, 7 -(-85)=7 + 85=92.

You have to multiply to get a common denominator. Since 67/890 can't simplify down anymore, you have to figure out what can multiply by 34 to get 890. In this case, you can't mulitply 34 to get 890, so you're going to have to multiply them together to get a common denominator. So mulitply the fraction 12/34 by 890 and the fraction 67/890 by 34 (don't forget to multiply the numerators too). Then add the answers together, you should get 6479/15130.

well if you don't have a calculator just put 92/7 but if you do just approximate the answear!

I understand, but in my answear sheet i don't have 92 the closest i get is 95, 94 and 91!

AB = AC + 14

BC  = AC + 30

And by the triangle inequality :

AB + AC > BC

[AC + 14] + AC > AC + 30

2AC + 14 > AC + 30

AC > 16

Which means that AB > 30     and BC > 46

Then, the minimum perimeter must be something greater than 16 + 30 + 46  = 92 cm

Here's my take on this one:

1. Beatriz is the oldest        2.  Ana is not the oldest        3. Celia is not the youngest

Let's assume that 1 is true.........   then 2 is false........but this is impossible because Beatriz and Ana would both be the oldest - a contradiction......so  T F F  isn't a possibiity

Let's assume 2 is true.........then Ana could be the second oldest or the youngest. Assume that she is the second oldest.......so 3 is false and Celia is the youngest.......but 1 is also false.......which means that Beatriz could be the second youngest [ violating our assumption]........or the youngest - also impossible because we know that 3 is false  and Celia is the youngest

And Ana can't be the youngest if we assume 2 is true, because 3 is false......Celia is the youngest in this scenario.......

So F T F  isn't possible, either

This leaves FFT  as the only possibility.......assume that Celia is the oldest.....then, since 2 is false, Ana would also have to be the oldest........and this is a contradiction

Assume Celia is the second oldest........then, since 2 is false, Ana is the oldest.......and since 1 is also false, Beatriz would be the youngest in this scenario

Thus

FFT   is the only possibility and the correct order  is  A - C - B

There are 60 minutes per hour, and the student must type for 6 hours.

6*60=360

She has to type for 360 minutes.

She has 15 days to type for 360 minutes, and to evenly divide up the work, she must...

360/15=24

...type for 24 minutes every day.