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Hi again DragonSlayer, this is not a great answer for your exact problem but hopefully it will help you to understand.

Complete the explanation of how can you use and compare data to solve real-world problems.

For numerical real-world data, you can graph the data and identify similarities and differences in corresponding parts of the graph. For categorical real-world data, you can graph the data and compare the centers, spreads, and shapes of the graphs.

Is this correct?   No it is not right.

Say you were going to study something about the cars in the carpark.

1) Examples of numerical staudes that could be done is

Size of engine, length, width, Year of manufacture, how many people arrived in it, age of drive, etc etc  See all thise things will be collections of numbers.

2)  Examples of categorical data could be. Colour of the car, Make of the car,  the ethnicity of the driver. See, none of these are numbers!  [They are all categories]   So you cannot really compare central tendancies or spread of the data.  I suppose you can say that 70% of the cards are white or red. But you can't say t hat the average car is red.  This does not make sense. 

I was actually on my what 2 month disappearance studying the new situation I'm in, appearently on my schedule back in August I for some reason got in the Gifted And Talented Education (it's pretty much the smart kids pack in the school) even though I was not in it last year

I avoided GATE last year because I predicted the  GATE program would be too lame for me, with a bunch of schoolmates I didn't really know that well, a lot more critical grading system, and more strict teachers

and 8th grade was getting weird 

so I went and studyed all over the school learning the ways of 8th Grade and the GATE program, and I mastered most of it by now, but back in August I wasn't doing as well as I used to be, and it ...

DANG IT!!! I got to go now. DANG YOU BEDTIME!!!

looks like I will continue tomorrow

Yes I like HeatherFeather. I think she is smart and a good war correspondent. :)

She should vist because this would be like a home away from home.

MIA = Missing in Action

Look how missed you have been TR      :D

We are all please that you are back.

DragonSlayer554 has just returned too.

This is like a full on reunion!   Yes we need Rosala and Zegroes too!

I was going to upload a celebration pic but then I remembered that pic uploads are not working today!  :((

And may I ask what is MIA?

actually, I wasn't planning a coup or anything

about Heather, she moved to some other school, actually to another state, she still is adjusting to the move, why you ask, you like her?

she told me she will come on soon, but not too often

You were MIA

I figured you and HeatherFeather were plotting a major coup.  Is Heather coming back soon?

This is what I think.

A store receives a shipment of 5,000 MP3 players. In a previous shipment of 5,000 MP3 players, 300 were defective. A store clerk generates random numbers to simulate a random sample of this shipment. The clerk lets the numbers 1 through 300 represent defective MP3 players, and the numbers 301 through 5,000 represent working MP3 players. The results are given.

4,043  889  285  4,955  4,718  301  2,567  257  3,809  4,712      

The sample of 10 has 2 defective ones and 8 good ones

that is, 20% of them are defective.

so

Based on this sample, how many of the MP3 players might the clerk predict would be defective?

20% of 5000 = 1000

 
Management would be basing their expectations on the last shipment. Last time they recieved 5000 and 300 were defective so they would expect the same again I think.

The manager would expect ____300_____ defective players in the shipment.

On the first minute I'm back a few people are ready for another war....interesting...and yet I don't have an army, just me....and nature....

so, did anyone have me declared dead, missing, or what else did I miss?

When was the last time I even posted a comment (excluding this morning)?

Im gonna need to tell ADMIN 1138 (George Lucas Reference) that we need to be able to find our posts again, that feature really was useful to give me laughs for hours

well I'm back

so, hi everyone

im back  

Hi TR.

We need another war. Maybe Rosala will come back and join us.

Calling Rosala! To arms! To arms!

Hi TitaniumRome

It is really good to dee you again  :D

Or if you're like someone who is too lazy to do any of that stuff, you can simply ask Siri or Google, just remember to use those sources wisely, as they might confuse with what you're saying and come up with a completely different result

First find the mean average of the data set.

Add these numbers and divide by 12

56, 47, 67, 77, 55, 76, 85, 80, 87, 69, 47, 58

The mean  = 67.00

Then take each number and subtract 67 from it. If it is negative then just make it positive that is called the absolute value.

56 – 67 = 11

47-67 =  20

 67-67 =  0

77-67 = 10

 55-67 = 12

76-67 =  9

85-67 = 18

 80-67 =  13

87-67 =  20

69-67 =  2

47-67 =  20

58-67 =9

Take the results

11, 20, 0, 10, 12, 9, 18, 13, 20, 2, 20, 9

And find the mean average of this.

It is 12.00 That is the Mean Absolute Deviation.

Now you have to do that for the second set of data.

I did this but I not put all the work on here.  

The mean is 52.08. The MAD is 12.08

Now subtract the lesser mean from the greater mean and that is 67.00-52.08 =  14.92

Now find the mean of the two MADs 12.00 + 12.08 = 24.08. 24.08/2 = 12.04

Then divide by the difference of the means by the mean of the two MADs 14.92/12.04 = 1.24

Rounding to the nearest tenth it is 1.2

This tells us the means of the two data sets differ by about 1.2 times the variability of the two data sets.

This is cool but I not know how to use this in real life yet. 

or you can type it straight into the input line as 8^1.7=     :)

x^2-5=139

x^2=139+5

x^2=144 take the square root of both sides

x=12

Enter 8 first, then press "x^y" key followed by 1.7 and finally press = sign to get your answer.

Type for example, 1/2 to get \(\frac{1}{2}\)

For the Web 2.0 Calculator, just write the numerator, then a slash (/), then the denominator to make a fraction.

On average in its orbit, Mars is about 228,000,000,000 meters away from the sun (that's 2.28 x 1011 m in scientific notation). Light travels at 300,000,000 meters/second (3x 108 m/s). To get the answer, divide the distance by the speed. You'll find that it takes 760 seconds, or 12 minutes and 40 seconds for sunlight to reach Mars. It takes light about 8 minutes to travel from the Sun to Earth.

Source(s):

http://athena.cornell.edu/kids/cs_calvin_questions.html

12 minutes and 40 seconds for sunlight to reach Mars

https://web2.0calc.com/questions/math-question-i-m-back

Yes, I cannot post pics today either :(

DragonsSlayer554, can you please put the address of you unanswered question here please.  I will include it in my next wrap, someone might be able to help you :))

Yes Melody

Since Mars is 1.52x as distant from the Sun as Earth is, then it follows that it will take light that much longer to reach Mars. Since, it takes light about 8 minutes and 20 seconds to reach Earth, it therefore will take it 81/3 X 1.52=12 2/3 minutes to reach Mars. Or about 12 minutes and 40 seconds.

Don't know about mars but to reach earth it takes about 8 minutes

Lets split this into groups.

-83+-9=-92

next

-92--12=-80

next

-80+-17=-97

then

-97-2=-99

then

-99+-24=-123

finally

-123+-73=-196