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One evening Amal and Hana both drive to a concert in a city that lies between their home towns. Together they drive a total of 297 miles to the concert. Amal drives an average speed of 5 miles per hour faster than Hanna. If Amal and Hanna both arrive at the concert after 3 hours, what is the average speed of Amal's car? A. 57 mph B. 47 mph C. 59 mph D. 52 mph

Let Hanna's average speed=H, the Amal average speed=H+5, but we have,

3H + 3(H+5)=297

3H + 3H + 15=297

6H=297 - 15

6H=282 divide both sides by 6

H=282/6

H=47 miles average speed of Hanna,but we have

47+5=52 miles average speed of Amal.

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Does the D=rt equation work with this problem? 

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2.2521008071930811e94

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-7x+8y=56, -89x-4y=776

Solve the following system:
{8 y-7 x = 56 |     (equation 1)
-89 x-4 y = 776 |     (equation 2)
Swap equation 1 with equation 2:
{-(89 x)-4 y = 776 |     (equation 1)
-(7 x)+8 y = 56 |     (equation 2)
Subtract 7/89 × (equation 1) from equation 2:
{-(89 x)-4 y = 776 |     (equation 1)
0 x+(740 y)/89 = -448/89 |     (equation 2)
Multiply equation 2 by 89/4:
{-(89 x)-4 y = 776 |     (equation 1)
0 x+185 y = -112 |     (equation 2)
Divide equation 2 by 185:
{-(89 x)-4 y = 776 |     (equation 1)
0 x+y = -112/185 |     (equation 2)
Add 4 × (equation 2) to equation 1:
{-(89 x)+0 y = 143112/185 |     (equation 1)
0 x+y = -112/185 |     (equation 2)
Divide equation 1 by -89:
{x+0 y = -1608/185 |     (equation 1)
0 x+y = -112/185 |     (equation 2)
Collect results:
Answer: | 
| {x = -1608/185
y = -112/185

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