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$60/$72 = 0.833333...

0.833333 = 83.333%

100% - 83.333% = 16.667% = about 16.7%

The discount is 16.7%

I hope this helps! :)

When dealing with sin, cos, and tan, there are results for a 60^o angle. The cos of 60^o is 1/2, the cos of 30^o is sqr root (3)/2. If I have 12(cos 330^o + i * sin 330^o) I need to know why I simplify that to 30^o.

I just played with my calculator and I see exactly what you're talking about.

Basically what you're saying is: instead of (1+1/n)^n, doing (1+1/n)^(n+0.5) gives you more accurate digits.

(1+1/100)^100 = 2.7048...

(1+1/100)^100.5 = 2.7183 ...  (exactly 2x more accurate digits)

(1+1/1000)^1000 = 2.7169239 ...

(1+1/1000)^1000.5 = 2.71828205... (again 2x more accurate digits)

It's pretty interesting, but I don't know why it would give you more accurate digits. Maybe it is a coincidence?

Hi,

All you need to do is simplify the expression. So....

7+3x+4= 3x+11

Done!

Hope this helps!

Mathcalc

plus it doesn't go in evenly

Melody,

Can u please also explain the other 2? I sent a message to CPhill as well to explain them. I just want to see which method would work best for me.

Sorry if I keep bothering you.

Thanks

Mathcalc

because it can simplify farther than that

What are you trying to do?

If "simplify" is your answer, then the first step to take would be combine like terms.

7+3x+4 = 3x+11

A quick question, why are we simplifying the angles to 30^o instead of 60^o? 330^o is 60⁰ more than 270^o so wouldn't the angles be simplified to 60^o?

There are multiple ways to do this, but here is one way:

$300 - 15%($300)

15% ($300) = 0.15 * $300 = $45.

$300 - $45 = $255

You also could have done $300 * (100%-15%) = $300 * 85% = $300 * 0.85 = $255

I kind of get it now, it's just I didn't know how CPhill figured out his answers. I'll try and ask him.

Thanks so much

Mathcalc

Two buses with 45 riders each = 90........so we have

90 +  5c >=  120   subtract   90  from both sides

5c > = 30      divide both sides by 5

c > = 6        [ you will need at least 6 cars, maybe more, if the number of people exceed 120  ]

Hi  Mathcalc,

A group has an equal number of adults and children. 

Let K be the number of children (kids)    Sinve there is the same number of adults then K is the number of adults too

When n oranges are given to the group, each adult gets two oranges while each child gets one orange

and there are still 5 oranges left.

The adults get 2 oranges each that is 2K oranges and the children get 1 orange each, that is K oranges and there is 5 oranges left over.

SO

n = 2K+K+5

Write an algebraic expression for the number of oranges given to the adults.

n=3K+5

n-5=3K

K=(n-5)/3

but the adults get twice this many oranges so the adults get

2(n-5)/3    oranges.

CPhill's answer is the same, he has just not simplified it. and i used a k instead of an x

Does that help ?

Do you want me to discuss the others as well. OR maybe if you need more explanation, CPhill might like to help you.

We like it when people ask us about our answers.  It means we are really teaching someone :))

(Sometimes we wonder if anyone even reads an answer)

\(\frac{5409}{4} = 1352 \frac{1}{4}\) or 1352.25

I hope this helps :)

Thanks a bunch CPhill.

Mathcalc

First, break up the number into it's prime factors and put everything under the radical.

\(\sqrt{48} = \sqrt{2*2*2*2*3}\)

Then find the pairs, pull them out of the radical, and multiply the radical by that number.

We have 2 pairs of "2s" in the prime factorization of 48, so after removing them, we get

\(2*2\sqrt{3}\) which simplifies to \(4\sqrt{3}\)

Or you can try and factor the original number into perfect squares, for example

\(\sqrt{48} = \sqrt{4*4*3}\) and since √4 is equal to 2, you can remove the √4s inside the radical and replace them with "2s" outside the radical. Both ways will ive you the same answer.

If this was not clear, (I understand if it isn't) speak up so somebody can clarify.

I hope you find this helpful! :)

why is negative 2 squared negative 4

\((-2)^2=-2*-2=+4\\~\\ BUT\\~\\ -2^2=-1*2^2=-1*2*2=-4\\~\\ \mbox{It has to be like this because otherwise } 10-2^2\quad\mbox{would give the same answer as }10+2^2\)

\(\frac{3}{29} \) * 100% = 10.345%

81.9 * \({10}^{-3}\)is not proper scientific notation.

The first number must be equal to or greater than 1, but less than 10.

What you're talking about is supposed to be \(8.19 * {10}^{-2}\) in proper scientific notation.

If you want an answer, we need more details.

1.83 tons is a lot heavier than 2.0 Kilograms, but 1.83 ounces is considerably less than 2.0 pounds.

Give us units to match the numbers! If it's the same unit, common sense ought to tell you that 1.83 < 2.0.

That depends, are the units the same.?  

Without the units neither have any weight so  they are equal in weight.

[2nd][asin] number

Hi Shades,

I know I already answered this question this morning so I am assuming that when this one did not get answered that you reposted.

You are encouraged to repost, reposted questions that are correctly labeled get priority.

BUT

Please Do Not rewrite the question.

Copy the address of your original question and paste it into the post.

(Most of you can do this by highlighting the address in the address bar - right click - choose copy from the menu.  Then place curser where you want it in the new post, right click and choose paste from the drop down menu)

[I added this for other]

This way your question will not be answered twice.  Answerers are too busy for that - there are always other people waiting. 

An example of what you might like to call yours   

"Unanswered complex number question - Please help me."

A note to potential answerers.

Always answer the question on the original post.

It would also be heplful if you posted on the new thread that the question was now answered by you,:)

Simplify the following:
8×4 x^2 y^5 x^4 y^4

y^5×4 x^4 y^4 = y^(5+4)×4 x^4:
8 x^2×4 y^(5+4) x^4

5+4 = 9:
8×4 x^2 y^9 x^4

8 x^2 y^9×4 x^4 = 8 x^(2+4) y^9×4:
8×4 x^(2+4) y^9

2+4 = 6:
8×4 x^6 y^9

8×4  =  32:
Answer: |  32 x^6 y^9