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I HATE science! I have science test a little later I've been studying all night. I think I'll fall asleep during it.😜😀😜😀😜😀😜

Be careful Haley there are slight translation differences between Castilian Spanish and puerto ricin Spanish... You are probably learning castillian

OK here is a question for you. You say the moon is moving farther away from the Earth and the Earth is moving closer to the sun.  The Earth is gaining mass from cosmic dust so the gravity is stronger but the moon moves away. The sun gets bigger but looses mass by its nuclear reaction so its getting lighter and the gravity is getting weaker, but the Earth is moving closer.

Why do these two things seem in reverse? 

Looooool! I'd say somewhere between 11-14 usually your questions become more mature when you get older( with the exception of a few people lol). And yours sounded like the type of junk I would post, and I'm 12😜😀😜😀😜😀😜😀😜😀😜😀😜

Hey other guest,

          You can't listen to everything they say, they are just trying to look cool and fit in...

                  -Victoria 

Thanks to your goofing!: Here is your new answer, smart Aleck!.

Solve for x over the real numbers:
5^(x-sqrt(2)) = 25

Take the logarithm base 5 of both sides:
x-sqrt(2) = 2

Add sqrt(2) to both sides:
Answer: |  x = 2+sqrt(2)
 

Hello, if you could please answer the bellow question, with a easy to follow method, I would be most grateful

A language has 7 total letters in their alphabet.  S, NO, WM, AN.  Every word in this language adds up to 7 letters. The letters that are together have to stay together in every word (W will always be followed by M) . For example "snonono" and "sssanwm" are words in this language, and "sssmwan" or "sssawmn" are not

How many total words are there in this alphabet ?

Is  an + no  = ano and  anno in this alphabet ?

If an + no = anno :

\(\begin{array}{rcl} 1 && sssssss \\ 2 && sssssno \\ 3 && ssssswm \\ 4 && sssssan \\ 5 && ssssnos \\ 6 && sssswms \\ 7 && ssssans \\ 8 && sssnoss \\ 9 && sssnono \\ 10 && sssnowm \\ 11 && sssnoan \\ 12 && ssswmss \\ 13 && ssswmno \\ 14 && ssswmwm \\ 15 && ssswman \\ 16 && sssanss \\ 17 && sssanno \\ 18 && sssanwm \\ 19 && sssanan \\ 20 && ssnosss \\ 21 && ssnosno \\ 22 && ssnoswm \\ 23 && ssnosan \\ 24 && ssnonos \\ 25 && ssnowms \\ 26 && ssnoans \\ 27 && sswmsss \\ 28 && sswmsno \\ 29 && sswmswm \\ 30 && sswmsan \\ 31 && sswmnos \\ 32 && sswmwms \\ 33 && sswmans \\ 34 && ssansss \\ 35 && ssansno \\ 36 && ssanswm \\ 37 && ssansan \\ 38 && ssannos \\ 39 && ssanwms \\ 40 && ssanans \\ 41 && snossss \\ 42 && snossno \\ 43 && snosswm \\ 44 && snossan \\ 45 && snosnos \\ 46 && snoswms \\ 47 && snosans \\ 48 && snonoss \\ 49 && snonono \\ 50 && snonowm \\ \end{array} \begin{array}{rcl} 51 && snonoan \\ 52 && snowmss \\ 53 && snowmno \\ 54 && snowmwm \\ 55 && snowman \\ 56 && snoanss \\ 57 && snoanno \\ 58 && snoanwm \\ 59 && snoanan \\ 60 && swmssss \\ 61 && swmssno \\ 62 && swmsswm \\ 63 && swmssan \\ 64 && swmsnos \\ 65 && swmswms \\ 66 && swmsans \\ 67 && swmnoss \\ 68 && swmnono \\ 69 && swmnowm \\ 70 && swmnoan \\ 71 && swmwmss \\ 72 && swmwmno \\ 73 && swmwmwm \\ 74 && swmwman \\ 75 && swmanss \\ 76 && swmanno \\ 77 && swmanwm \\ 78 && swmanan \\ 79 && sanssss \\ 80 && sanssno \\ 81 && sansswm \\ 82 && sanssan \\ 83 && sansnos \\ 84 && sanswms \\ 85 && sansans \\ 86 && sannoss \\ 87 && sannono \\ 88 && sannowm \\ 89 && sannoan \\ 90 && sanwmss \\ 91 && sanwmno \\ 92 && sanwmwm \\ 93 && sanwman \\ 94 && sananss \\ 95 && sananno \\ 96 && sananwm \\ 97 && sananan \\ 98 && nosssss \\ 99 && nosssno \\ 100 && nossswm \\ \end{array} \begin{array}{rcl} 101 && nosssan \\ 102 && nossnos \\ 103 && nosswms \\ 104 && nossans \\ 105 && nosnoss \\ 106 && nosnono \\ 107 && nosnowm \\ 108 && nosnoan \\ 109 && noswmss \\ 110 && noswmno \\ 111 && noswmwm \\ 112 && noswman \\ 113 && nosanss \\ 114 && nosanno \\ 115 && nosanwm \\ 116 && nosanan \\ 117 && nonosss \\ 118 && nonosno \\ 119 && nonoswm \\ 120 && nonosan \\ 121 && nononos \\ 122 && nonowms \\ 123 && nonoans \\ 124 && nowmsss \\ 125 && nowmsno \\ 126 && nowmswm \\ 127 && nowmsan \\ 128 && nowmnos \\ 129 && nowmwms \\ 130 && nowmans \\ 131 && noansss \\ 132 && noansno \\ 133 && noanswm \\ 134 && noansan \\ 135 && noannos \\ 136 && noanwms \\ 137 && noanans \\ 138 && wmsssss \\ 139 && wmsssno \\ 140 && wmssswm \\ 141 && wmsssan \\ 142 && wmssnos \\ 143 && wmsswms \\ 144 && wmssans \\ 145 && wmsnoss \\ 146 && wmsnono \\ 147 && wmsnowm \\ 148 && wmsnoan \\ 149 && wmswmss \\ 150 && wmswmno \\ \end{array} \begin{array}{rcl} 151 && wmswmwm \\ 152 && wmswman \\ 153 && wmsanss \\ 154 && wmsanno \\ 155 && wmsanwm \\ 156 && wmsanan \\ 157 && wmnosss \\ 158 && wmnosno \\ 159 && wmnoswm \\ 160 && wmnosan \\ 161 && wmnonos \\ 162 && wmnowms \\ 163 && wmnoans \\ 164 && wmwmsss \\ 165 && wmwmsno \\ 166 && wmwmswm \\ 167 && wmwmsan \\ 168 && wmwmnos \\ 169 && wmwmwms \\ 170 && wmwmans \\ 171 && wmansss \\ 172 && wmansno \\ 173 && wmanswm \\ 174 && wmansan \\ 175 && wmannos \\ 176 && wmanwms \\ 177 && wmanans \\ 178 && ansssss \\ 179 && ansssno \\ 180 && anssswm \\ 181 && ansssan \\ 182 && anssnos \\ 183 && ansswms \\ 184 && anssans \\ 185 && ansnoss \\ 186 && ansnono \\ 187 && ansnowm \\ 188 && ansnoan \\ 189 && answmss \\ 190 && answmno \\ 191 && answmwm \\ 192 && answman \\ 193 && ansanss \\ 194 && ansanno \\ 195 && ansanwm \\ 196 && ansanan \\ 197 && annosss \\ 198 && annosno \\ 199 && annoswm \\ 200 && annosan \\ \end{array} \begin{array}{rcl} 201 && annonos \\ 202 && annowms \\ 203 && annoans \\ 204 && anwmsss \\ 205 && anwmsno \\ 206 && anwmswm \\ 207 && anwmsan \\ 208 && anwmnos \\ 209 && anwmwms \\ 210 && anwmans \\ 211 && anansss \\ 212 && anansno \\ 213 && ananswm \\ 214 && anansan \\ 215 && anannos \\ 216 && ananwms \\ 217 && ananans \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \end{array}\)

Solve for t over the real numbers:
298 e^(0.027 t) = 370000

298 e^(0.027 t) = 298 e^(27 t/1000):
298 e^((27 t)/1000) = 370000

Divide both sides by 298:
e^((27 t)/1000) = 185000/149

Take the natural logarithm of both sides:
(27 t)/1000 = log(185000/149)

Multiply both sides by 1000/27:
Answer: | t = 1000/27 log(185000/149     t=263.8570

Die 9 Stellen-Methode heisst nur so. Die Einheiten können beliebig gewählt werden, auch innerhalb der Rechnung kann man die Einheit wechseln.

1. Beispiel In zweier Einheiten weiter zerlegen.

\(\begin{array}{lr} 2008\ 00\ 00\ 09\ 70\ 37\ 57\ 00\ 13\ 14\ 00 \\ (1) & 2008 \\ (2) & 00 \\ (3) & 00 \\ (4) & 09 \\ (5) & 70 \\ (6) & 37 \\ (7) & 57 \\ (8) & 00 \\ (9) & 13 \\ (10)& 14 \\ (11)& 00 \\ \end{array}\\ \begin{array}{lr} (1) &2008 ÷ 97 = 20 \text{ Rest } \mathbf{68} \\ (2) &\mathbf{68} 00 ÷ 97 = 70\text{ Rest } \mathbf{10} \\ (3) &\mathbf{10} 00 ÷ 97 = 10 \text{ Rest } \mathbf{30} \\ (4) &\mathbf{30} 09 ÷ 97 = 31 \text{ Rest } \mathbf{2} \\ (5) &\mathbf{02} 70 ÷ 97 = 2 \text{ Rest } \mathbf{76} \\ (6) &\mathbf{76} 37 ÷ 97 = 78 \text{ Rest } \mathbf{71} \\ (7) &\mathbf{71} 57 ÷ 97 = 73 \text{ Rest } \mathbf{76 } \\ (8) &\mathbf{76} 00 ÷ 97 = 78 \text{ Rest } \mathbf{34} \\ (9) &\mathbf{34} 13 ÷ 97 = 35 \text{ Rest } \mathbf{18 } \\ (10)& \mathbf{18} 14 ÷ 97 = 18 \text{ Rest } \mathbf{68} \\ (11)& \mathbf{68} 00 ÷ 97 = 70 \text{ Rest } \mathbf{10} \\ \end{array}\)

II. In Einer Einheiten weiter zerlegen.

\(\begin{array}{lr} 20\ 0\ 8\ 0\ 0\ 0\ 0\ 0\ 9\ 7\ 0\ 3\ 7\ 5\ 7\ 0\ 0\ 1\ 3\ 1\ 4\ 0\ 0\\ ( 1) & 20\\ (2) & 0\\ (3) & 8\\ (4) & 0\\ (5) & 0\\ (6) & 0\\ (7) & 0\\ (8) & 0\\ (9) & 9\\ (10) & 7\\ (11) & 0 \\ (12) & 3\\ (13) & 7\\ (14) & 5\\ (15) & 7\\ (16) & 0\\ (17) & 0\\ (18) & 1\\ (19) & 3\\ (20) & 1\\ (21) & 4 \\ (22) & 0\\ (23) & 0\\ \end{array}\\ \begin{array}{lr} (1) & 20 ÷ 97 = 0 \text{ Rest } \mathbf{20}\\ (2) &\mathbf{20} 0 ÷ 97 = 2 \text{ Rest } \mathbf{6}\\ (3) &\mathbf{ 6} 8 ÷ 97 = 0 \text{ Rest } \mathbf{68}\\ (4) &\mathbf{68} 0 ÷ 97 = 7 \text{ Rest } \mathbf{1}\\ (5) &\mathbf{ 1} 0 ÷ 97 = 0 \text{ Rest } \mathbf{10} \\ (6) &\mathbf{10} 0 ÷ 97 = 1 \text{ Rest } \mathbf{3} \\ (7) &\mathbf{ 3} 0 ÷ 97 = 0 \text{ Rest } \mathbf{30}\\ (8) &\mathbf{30} 0 ÷ 97 = 3 \text{ Rest } \mathbf{9}\\ (9) &\mathbf{ 9} 9 ÷ 97 = 1 \text{ Rest } \mathbf{2}\\ (10) &\mathbf{ 2} 7 ÷ 97 = 0 \text{ Rest } \mathbf{27}\\ (11) &\mathbf{27} 0 ÷ 97 = 2 \text{ Rest } \mathbf{76} \\ (12) &\mathbf{76} 3 ÷ 97 = 7 \text{ Rest } \mathbf{84} \\ (13) &\mathbf{84} 7 ÷ 97 = 8 \text{ Rest } \mathbf{71} \\ (14) &\mathbf{71} 5 ÷ 97 = 7 \text{ Rest } \mathbf{36} \\ (15) &\mathbf{36} 7 ÷ 97 = 3 \text{ Rest } \mathbf{76} \\ (16) &\mathbf{76} 0 ÷ 97 = 7 \text{ Rest } \mathbf{81} \\ (17) &\mathbf{81} 0 ÷ 97 = 8 \text{ Rest } \mathbf{34} \\ (18) &\mathbf{34} 1 ÷ 97 = 3 \text{ Rest } \mathbf{50} \\ (19) &\mathbf{50} 3 ÷ 97 = 5 \text{ Rest } \mathbf{18} \\ (20) &\mathbf{18} 1 ÷ 97 = 1 \text{ Rest } \mathbf{84}\\ (21) &\mathbf{84} 4 ÷ 97 = 8 \text{ Rest } \mathbf{68}\\ (22) &\mathbf{68} 0 ÷ 97 = 7 \text{ Rest } \mathbf{1}\\ (23) &\mathbf{1} 0 ÷ 97 = \text{ Rest } \mathbf{10}\\ \end{array}\)

Wie gesagt, man kann auch beliebige Einheiten kombinieren, es funktioniert immer.

III. In verschiedene Einheiten weiter zerlegen.

\(\begin{array}{lr} 20080000\ 0\ 9\ 7\ 0\ 3\ 7\ 5\ 7\ 0\ 0\ 131400 \\ (1) & 20080000 \\ (2) & 0\\ (3) & 9 \\ (4) & 7\\ (5) & 0 \\ (6) & 3\\ (7) & 7 \\ (8) & 5\\ (9) & 7 \\ (10) & 0\\ (11) & 0 \\ (12) & 131400 \\ \\ \end{array}\\ \begin{array}{lr} (1) &20080000 ÷ 97 = 207010 \text{ Rest } \mathbf{30} \\ (2) &\mathbf{30} 0 ÷ 97 = 3 \text{ Rest } \mathbf{9}\\ (3) &\mathbf{ 9} 9 ÷ 97 = 1 \text{ Rest } \mathbf{2}\\ (4) &\mathbf{ 2} 7 ÷ 97 = 0 \text{ Rest } \mathbf{27}\\ (5) &\mathbf{27} 0 ÷ 97 = 2 \text{ Rest } \mathbf{76} \\ (6) &\mathbf{76} 3 ÷ 97 = 7 \text{ Rest } \mathbf{84} \\ (7) &\mathbf{84} 7 ÷ 97 = 8 \text{ Rest } \mathbf{71} \\ (8) &\mathbf{71} 5 ÷ 97 = 7 \text{ Rest } \mathbf{36} \\ (9) &\mathbf{36} 7 ÷ 97 = 3 \text{ Rest } \mathbf{76} \\ (10) &\mathbf{76} 0 ÷ 97 = 7 \text{ Rest } \mathbf{81} \\ (11) &\mathbf{81} 0 ÷ 97 = 8 \text{ Rest } \mathbf{34} \\ (12) &\mathbf{34} 131400 ÷ 97 = 351870 \text{ Rest } \mathbf{10} \\ \end{array}\)

Actually the equation is not 5 (x-sqrt(2)) = 25, but is 5^(x-sqrt(2)) = 25,  Your answer is wrong.

DEEZ nuts 

Solve for x:
5 (x-sqrt(2)) = 25

Divide both sides of 5 (x-sqrt(2)) = 25 by 5:
(5 (x-sqrt(2)))/(5) = 25/5

5/5 = 1:
x-sqrt(2) = 25/5

The gcd of 25 and 5 is 5, so 25/5 = (5×5)/(5×1) = 5/5×5 = 5:

 x-sqrt(2) = 5
Answer: | x=5 + sqrt(2)
 

Hey all the help has been much appreciated, I can not thank you enough.

All the best to you and your family over the holidays.

Supply

gotta go, Cya all later!! :)

Bye

- Ally

fine then, leave. I've been trying to help you :(

Happy holidays

ommmmmggggggg

Commutative property of multiplication

LOOOL! CPhill that's great!!
And hatman, you're in 7th grade!! O____O

Bye Haley thanks for being there for me

are you staying??

Ok I as going to change my mind but never mind uh good bye

CPhill look at my answer for the question with jesus on it.

7th grade :)