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-(5/2 + 7/3)

-5/2-7/3= -15/6-14/6= -29/6

 in last link you will find your answer by stepwise 

https://www.symbolab.com 

What is 75-48=27

x^2+x>1/e^4

=x>sqrt(4+e^4)/(2e^2)-1/2

ok,thanks a lot

I'm sure your friend is wrong. The answers I gave you are the CORRECT answers, but unfortunately I can't give you step-by-step breakdown of the answer because my software in not working properly.

I've found the same result but a friend says its incorrect cause it should be (e-2)/2λ

I can't find why it is -2 though

2/3*3/2=?

2/3 X 3/2=6/6=1

Find the following limit:
lim_(x->infinity) x/(2-cos(x))

Applying the quotient rule, write lim_(x->infinity) x/(2-cos(x)) as (lim_(x->infinity) x)/(lim_(x->infinity) (2-cos(x))):
(lim_(x->infinity) x)/(lim_(x->infinity) (2-cos(x)))

The limit of a difference is the difference of the limits:
(lim_(x->infinity) x)/lim_(x->infinity) 2-lim_(x->infinity) cos(x)

Using the fact that cosine is a continuous function, write lim_(x->infinity) cos(x) as cos(lim_(x->infinity) x):
(lim_(x->infinity) x)/(lim_(x->infinity) 2-cos(lim_(x->infinity) x))

lim_(x->infinity) x  =  infinity:
(lim_(x->infinity) x)/(lim_(x->infinity) 2-cos(infinity))

cos(infinity) = -1 to 1:
(lim_(x->infinity) x)/lim_(x->infinity) 2--1 to 1

Since 2 is constant, lim_(x->infinity) 2  =  2:
(lim_(x->infinity) x)/(2--1 to 1)

2--1 to 1 = 1 to 3:
(lim_(x->infinity) x)/1 to 3

lim_(x->infinity) x  =  infinity:
infinity/(1 to 3)

infinity/(1 to 3) = infinity:
Answer: | infinity

Definite integral:

integral_0^(e/lambda) ((lambda x)/e-log(lambda x)) dx = e/(2 lambda)

Indefinite integral:

integral ((lambda x)/e-log(lambda x)) dx = (lambda x^2)/(2 e) -xlog(lambda x)+x+constant

The Queen would surely have no objections in making Dragonlance a Squire????.......nevertheless.......the request is made.......!!!!!

I actually thought that I might make him a Brigadier Squire - Scout.......[ otherwise known as a BS - Scout ]........his main task would be to suss out posts having an excessive amount of BS attached to them................while the occurence of these isn't particularly common, they ARE known to pop up every now and then.......

When he is not busy with this, his other main duty - of course - will be assisting Sisyphus with the continuing search for the elusive Roman Zero......

The Queen hath had enough of this nonsense.  She bids her realm good night :)

No, the Queen will not demote the boy, she cannot for, as yet, he has not been pronounced a squire.

Sir CPhill has not approached the Queen requesting the appointment. 

The Queen would not say 'no' but Sir CPhill would not be so rude as to appoint the boy without the Queens knowledge and good grace.

It would be like marrying a lady without firstly asking her father for her hand.  Only a man of low morals would do such a thing and Sir CPhill is not such a man.

So, Nauseated you hath once again used trickery in an attempt to legitimize an appointment that hath not as yet been granted.

The Queen likes the lad Dragonlance. He doth amuse the Queen.  

The Queen thinks Sir CPhill should approach the Queen and request such an appointment be forthcoming!  :)

If my company asked me to write a basic analysis of what Alan’s equations did, this could be the first sentence.  The second sentence would elaborate on where (what intervals) this phenomenon occurs.

Words can rarely be as complete or precise as mathematical notation. However, they can give a general outline.

Let’s ask Alan if what I wrote is an accurate assessment or not, and if it is clear enough for anyone to understand, if s/he is also able to do the math involved. 

Hmm.........Here is a new twist to deferred annuity:

First thing to notice is that the annuity payments are indexed to inflation rate. This will complicate things a bit but not by much. Notice that they give the 25th and the last payment only. But, it should be relatatively easy to get the 1st. payment, since they increase by a constant inflation rate of 2.50%.Since the 25th and last payment is $111,446.60, then it follows that the first payment would be:$111,446.6(1.025)^-24=$ 61,616.08.

This 1st payment of his annuity is already indexed by 2.50%, so that net payment would be:

$61,616.08/1.025=$60,113.25. This is the payment that he would receive each year for 25 years without being indexed for inflation. Now, we simply have to find the PV of these 25 payments, and that should give us the amount of his annuity when he retired. One slight complication is that we have to find the net interest rate to use for this purpose.

Since we know he earns 6% annual compound and the inflation rate is 2.50%, the net investment rate would be: 1.06/1.025=3.415%. Now, we can find the PV of his 25 even annuity payments of $60,113.25 using this common formula:PV=P{[1 + R]^N - 1.[1 + R]^-N} R^-1=PV OF $1 PER PERIOD. When we plug all the numbers into this formula, we get PV=$1,000,000, which is the balance of his fund at his retirement.

And, of course he earned of:$1,000,000 - $311,804.73=$688,195.27 being the interest on his stripped coupon. Since we have both the PV and FV value of his intitial purchase, we can easily find the rate at which he purchased his stripped coupon:1,000,000=311,804.73(1 + i)^20. When we solve for i, we find that it is 6% compounded annually.

The only thing left unanswered is the total interest he earned on his 25-year annuity. But, since we calculated the 1st payment as being $61,616.08, we simply find the FV of these 25 payments at the inflation rate of 2.5%, using this common formula:FV=P{[1 + R]^N - 1/ R}=FV OF $1 PER PERIOD. When we plug all the numbers into this formula we get FV=$2,104,667.52.

Finally, the total interest he earned on his annuity is=$2,104,667.52 - $1,000,000=$1,104,667.52.

This answers all the above 5 questions.

Thanks Chris,

It was a neat question.  :)

YES I DID !!      HaHaHa     :)

HAHAHAHA!!!!.......I thought you might appreciate a  little "calendar" humor.........

Alan is demonstrating the diverse, sub-liner nature of the series. Certain numerical values slow the convergence to pi . Small changes to these values will accelerate the convergence.

Here’s a question.

Is what I wrote BS or is it true? :)

----------------------------------------------------------------------------------------------

It does not matter if it is true or false.

If you purposely write something intending that it be unintelligable to the intended audience, then it is BS.

That is what you have done so it is BS.   

Chris, you are a SA without the T      LOL :))

Thanks for the info.  

In NSW we would call it the HSC  (Highter School Certificate.)

Our (Australia's) education systems are state based.  NSW, New South Wales, is a state.  

Other states have different exams with different names. :)

Scholastic Aptitude Test (SAT)  - a college admissions test given widely across the US.......

Alternatively.......it's the day that falls in between  FRI  and SUN ..............

Thanks Solveit :)

What country are you in and what does SAT stand for?

Are you referring to the formula that converges to pi. It’s not that hard. I will say I could not “nutshell” it the way Alan did –at least not with any do speed. After reading it I can translate it to words.

Alan is demonstrating the diverse, sub-liner nature of the series. Certain numerical values slow the convergence to pi . Small changes to these values will accelerate the convergence.

Here’s a question.

Is what I wrote BS or is it true? :)

Nice one, Melody.......I like how you did that.....!!!!

"There is one consideration in evaluating Bertie’s error count: Some of his presentations are so advanced, very few would know whether he made an error or not."

Mmm don't know about that one.  

You can tell that he is not BS'ing his way through a problem like certain other members like to do. :)

Alan answered a question tonight ( along with a couple of guests).  They might just as well have been talking Swahili without a single translator in sight LOL