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The calculator page has (unobtrusive) ads, the forum doesn’t --which reminds me  . . .

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Huh? I'm sorry, but that just looked like a big mess to me. And if it's a website I can't click on it.

https://www.google.az/search?q=trapezoid&espv=2&biw=1366&bih=667&tbm=isch&tbo=u&source=univ&sa=X&ved=0ahUKEwjNhPLYpIzKAhUEFCwKHSLUDhQQsAQIJQ#tbm=isch&q=trapezoid+volume&imgrc=UjjItkeRiDNULM%3A

0.5(5-7x)=8-(4x+6)       note.......0.5   = 1/2

(1/2) ( 5 - 7x)  = 8 - 4x - 6

(1/2) (5 - 7x)  = 2 - 4x    multipy through by 2

5 - 7x   = 4 - 8x         add 8x  to both sides.......subtract 5 from both sides

x = -1

I'm interpreting this very liberally, but we can write this as :

[(3x^2 - 21x) (15x + 20)] / [ (6x + 8) (x^3 - 14x^2 + 49x) ]       factor, where possible

[ 3x ( x - 7) * 5 (3x + 4)] / [ 2 (3x + 4) * x ( x^2 - 14x + 49)] 

[ 3x ( x - 7) * 5 (3x + 4)] / [ 2 (3x + 4) * x ( x - 7)^2 ] 

[15x (x - 7) (3x + 4)] / [ 2x (3x + 4) (x - 7)^2 ]

[15/2]  / (x - 7)

15 / ( 2x - 14)      x cannot be equal  to -4/3 , 0   or  7   because any of these values makes the original expression 0 in the denominator

Factored:

3x² - 21x  =  3x(x - 7)

6x + 8  =  2(3x + 4)

x³ - 14x² + 49  =  <can't be factored>

15x + 20  =  5(x + 4)

To divide fractions, multiply by the reciprocal, so:

=  [3x(x - 7)] / [2(3x + 4)]  times  [5(x + 4] / [ x³ - 14x² + 49 ]

=  [15x(x - 7)(x +4)] / [2(3x + 4)(x³ - 14x² + 49)]

   ...   nothing cancels  ...

I'm using AD Block Plus......it works fine with this site........you also have the option of disabling it on any particular site, if you wish.....

StingSniperscope: You should separate your terms by proper brackets:

Simplify the following:
(3 x^2-21 x)/(((6 x+8) (x^3-14 x^2+49 x))/(15 x+20))

Multiply the numerator of (3 x^2-21 x)/(((6 x+8) (x^3-14 x^2+49 x))/(15 x+20)) by the reciprocal of the denominator. (3 x^2-21 x)/(((6 x+8) (x^3-14 x^2+49 x))/(15 x+20)) = ((3 x^2-21 x) (15 x+20))/((6 x+8) (x^3-14 x^2+49 x)):
((3 x^2-21 x) (15 x+20))/((6 x+8) (x^3-14 x^2+49 x))

Factor 2 out of 6 x+8:
((3 x^2-21 x) (15 x+20))/(2 (3 x+4) (x^3-14 x^2+49 x))

Factor 5 out of 15 x+20:
(5 (3 x+4) (3 x^2-21 x))/(2 (3 x+4) (x^3-14 x^2+49 x))

Factor 3 x out of 3 x^2-21 x:
(5×3 x (x-7) (3 x+4))/(2 (3 x+4) (x^3-14 x^2+49 x))

Factor x out of x^3-14 x^2+49 x:
(3×5 x (x-7) (3 x+4))/(2 x (x^2-14 x+49) (3 x+4))

The factors of 49 that sum to -14 are -7 and -7. So, x^2-14 x+49 = (x-7) (x-7):
(3×5 x (x-7) (3 x+4))/(2 x (x-7) (x-7) (3 x+4))

(x-7) (x-7) = (x-7)^2:
(3×5 x (x-7) (3 x+4))/(2 x (x-7)^2 (3 x+4))

(3 x (x-7)×5 (3 x+4))/(2 (3 x+4) x (x-7)^2) = ((3 x+4) x)/((3 x+4) x)×(3 (x-7)×5)/(2 (x-7)^2) = (3 (x-7)×5)/(2 (x-7)^2):
(3×5 (x-7))/(2 (x-7)^2)

3×5  =  15:
(15 (x-7))/(2 (x-7)^2)

Cancel terms. (15 (x-7))/(2 (x-7)^2)  =  15/(2 (x-7)^(2-1)):
15/(2 (x-7)^2-1)

2-1 = 1:
Answer: | 15/(2 (x-7))

In "Guest"#2, which is mine, I said "your equation is faulty". By that, I meant you set it up slightly wrong. It should look like this: P - .15P=$10.20. This will give you P=$12-the cost per girl BEFORE 15% discount, which is of course right.

Omi 67 :DD

4 sisters!

Hallo guest

GET LOST!.

because 100-15= i get 75 D

Four sisters bought a present for their mother. They received a 15% discount on the original price of the gift. After the discount was taken, each sister paid $10.20. What was the original price of the gift?

Since each sister paid $10.20 after 15% discount, therefore the price was:

$10.20 X 4=$40.80 after 15% discount, therefore:

$40.80/.85=$48.00 The original price of the gift.

P.S. Your equation is faulty!.

10.20x4=40.8 it is the price of gift whith discount

x-0.15x=40.8

75x/100=40.8

x=40.8x100/75

x=54.4 is original price 

i am not sure :)

Hallo StingSniperscope

Simplify the following:
(3 x^2-21 1/6 x x+8)/(x^3+49 1/15 x x-14 x^2+20)

Combine powers. (49 x x)/15 = (49 x^(1+1))/15:
(3 x^2-21 1/6 x x+8)/(x^3+(49 x^1+1)/15-14 x^2+20)

1+1 = 2:
(3 x^2-21 1/6 x x+8)/(x^3+(49 x^2)/15-14 x^2+20)

Put each term in x^3+(49 x^2)/15-14 x^2+20 over the common denominator 15: x^3+(49 x^2)/15-14 x^2+20  =  (15 x^3)/15+(49 x^2)/15-(210 x^2)/15+300/15:
(3 x^2-21 1/6 x x+8)/((15 x^3)/15+(49 x^2)/15-(210 x^2)/15+300/15)

(15 x^3)/15+(49 x^2)/15-(210 x^2)/15+300/15 = (15 x^3+49 x^2-210 x^2+300)/15:
(3 x^2-21 1/6 x x+8)/((15 x^3+49 x^2-210 x^2+300)/15)

49 x^2-210 x^2 = -161 x^2:
(3 x^2-21 1/6 x x+8)/((15 x^3+-161 x^2+300)/15)

-(21 x x)/6 = -(21 x^2)/6:
(3 x^2+-(21 x^2)/6+8)/((15 x^3-161 x^2+300)/15)

The gcd of -21 and 6 is 3, so (-21 x^2)/6 = ((3 (-7)) x^2)/(3×2) = 3/3×(-7 x^2)/2 = (-7 x^2)/2:
(3 x^2+(-7 x^2)/2+8)/((15 x^3-161 x^2+300)/15)

Put each term in 3 x^2-(7 x^2)/2+8 over the common denominator 2: 3 x^2-(7 x^2)/2+8  =  (6 x^2)/2-(7 x^2)/2+16/2:
((6 x^2)/2-(7 x^2)/2+16/2)/((15 x^3-161 x^2+300)/15)

(6 x^2)/2-(7 x^2)/2+16/2 = (6 x^2-7 x^2+16)/2:
((6 x^2-7 x^2+16)/2)/((15 x^3-161 x^2+300)/15)

6 x^2-7 x^2 = -x^2:
(-x^2+16)/(2 (15 x^3-161 x^2+300)/15)

Factor -1 out of 16-x^2:
-(x^2-16)/(2 (15 x^3-161 x^2+300)/15)

x^2-16 = x^2-4^2:
-(x^2-4^2)/(2 (15 x^3-161 x^2+300)/15)

Factor the difference of two squares. x^2-4^2 = (x-4) (x+4):
-(x-4) (x+4)/(2 (15 x^3-161 x^2+300)/15)

Multiply the numerator by the reciprocal of the denominator, -((x-4) (x+4))/(2 (15 x^3-161 x^2+300)/15) = (-(x-4) (x+4))/2×15/(15 x^3-161 x^2+300):
Answer: | -(15 (x-4) (x+4))/(2 (15 x^3-161 x^2+300))

Solve for x:
(240-15 x^2)/(30 x^3-322 x^2+600) = 0

Multiply both sides by 30 x^3-322 x^2+600:
240-15 x^2 = 0

The left hand side factors into a product with three terms:
-15 (x-4) (x+4) = 0

Divide both sides by -15:
(x-4) (x+4) = 0

Split into two equations:
x-4 = 0 or x+4 = 0

Add 4 to both sides:
x = 4 or x+4 = 0

Subtract 4 from both sides:
Answer: | x = 4 or x = -4

http://www.wolframalpha.com/input/?i=%283x%5E2-21x%2F6x%2B8%29%2F%28x%5E3-14x%5E2%2B49x%2F15x%2B20%29

how do I slove this integral? its the integral of(1/3x-1 -1/3x+1)

Take the integral:
integral 0 dx
The integral of zero is an arbitrary constant of integration:
Answer: | =  0+constant

The legs of a right triangle measure 3x and 15. If the hypotenuse measures 3x+3, what is the value of x?

Will use Pythagoras's Theorem:

(3x)^2 + 15^2=(3x + 3)^2

Solve for x:
9 x^2+225 = (3 x+3)^2

Expand out terms of the right hand side:
9 x^2+225 = 9 x^2+18 x+9

Subtract 9 x^2+18 x+9 from both sides:
216-18 x = 0

Factor constant terms from the left hand side:
-18 (x-12) = 0

Divide both sides by -18:
x-12 = 0

Add 12 to both sides:
Answer: | x = 12

No, 1 is not a prime.

Find the sales tax of an item that costs $42 and has a 8.25% sales tax.Round appropriately

$42 X (8.25/100)=$3.47 sales tax @ 8.25%

Just use the calculator here. Click on Pi, then press "x^y" key, then enter 4 followed by = key. That should give you the answer you want.

Dear Melody,

       Thank you for you consideration. I would love to become a member. There is just one small problem. I don't have an email. So you see my predicament. I've asked for an email. But apparently my guardians find it in my best interest to not acquire one till my 15th birthday.