x^2 is x to the power of two and since you don't know what x is just put x^2+15 and x^2+2.5
for area and perimeter
x^2
Light year=365 X 24 X 3,600 X 299,792.458=9,454,254,955,488 Kilometers. Therefore,
400 X 9,454,254,955,488=3,781,701,982,195,200 km-distance to Polaris=~3.8 X 10^15 km.
147.7056
I assume this is:
[6^-1a^-3b^4] / [5^-2 ab^5] = [the constants / variables with the negative exponents are brought across the fraction bar and their exponents change to a positive]
[5^2 * b^4] / [ 6^1 * a^3 * a * b^5] =
[25 b^4] / [ 6 * a^4 * b^5 ] = note...... [b^4 / b^5] = [1 / b]
[25 ] / [ 6* a^4 *b]
\(1ly\) is approximately equal to \(9,460,000,000,000km\)
\(9,460,000,000,000km\times400\)
\(3,784,000,000,000,000km\)
The distance from Earth to Polaris is approximately \(3,84,000,000,000,000km\)
(7^2 a^2 b^5/ 7^-1 a^4 b^3)-1 Does this mean:
[(7^2 a^2 b^5) / (7^-1 a^4 b^3)]-1, if that is what you mean, then we have:
Simplify the following: (7^2 a^2 b^5)/((a^4 b^3)/(7))-1 Multiply the numerator of (7^2 a^2 b^5)/((a^4 b^3)/7) by the reciprocal of the denominator. (7^2 a^2 b^5)/((a^4 b^3)/7) = (7^2 a^2 b^5×7)/(a^4 b^3): (7^2×7 a^2 b^5)/(a^4 b^3)-1 Combine powers. (7^2 a^2 b^5×7)/(a^4 b^3) = 7^2×7 a^(2-4) b^(5-3): 7^2×7 a^2-4 b^5-3-1 2-4 = -2: 7^2×7 a^-2 b^(5-3)-1 5-3 = 2: (7^2×7 b^2)/a^2-1 7^2 = 49: (49×7 b^2)/a^2-1 49×7 = 343: (343 b^2)/a^2-1 Put each term in (343 b^2)/a^2-1 over the common denominator a^2: (343 b^2)/a^2-1 = (343 b^2)/a^2-(a^2)/a^2: (343 b^2)/a^2-a^2/a^2 (343 b^2)/a^2-a^2/a^2 = (343 b^2-a^2)/a^2: Answer: | (343 b^2-a^2)/a^2
\(-(x-6)=6\)
\(-x+6=6\)
\(-x=0\)
\(x=0\)
\(x{}^{2}+x\)
Simplify the expression 6^-1a^-3b^4/5^-2 ab^5 so that it uses postive exponents. only
\(2x+x\)
\(3x\)
i mean x to the power of two
\(cos(\frac{-\pi}{3})\)
\(cos(\frac{\pi}{3})\)
\(\frac{1}{2}\)
\(-10x{}^{0}\)
\(-10\times1\)
\(-10\)
-10x^0=-10 X x^0=-10 X 1=-10
any number to the 0 power is 1 so just multiply -10 by 1
9x - 7 = -7 add 7 to both sides
9x = 0 divide both sides by 9
x = 0
What do you mean "there is no proper square root key"!!!. Did you look carefully just above the "Log" key. It looks like this: √x . Enter you number and press that key followed by = key. That should give your your answer.
There IS a square root key - it's next to the "csc" key.......
f(x) = x^3 – 1 • g(x)=3x+1 • h(x) = 4x – 5. Show that g(f(x)) + xh(x) = 3x^3 + 4x2 – 5x – 2.
g(f(x) = 3(x^3 -1) + 1 = 3x^3 - 3 + 1 = 3x^3 - 2
x* h(x) = x* (4x - 5) = 4x^2 - 5x
So.......combining both results - as was specified- we get :
3x^3 + 4x^2 - 5x - 2
Team 1 second half = 33 7
Team 2 second half = 29 11
Team 3 secong half = 31 9
Team 4 second half = 28 12
Since they each played 40 games in the second half.......Team 1 had the most wins out of 40, i.e., 33.........just as guest said......!!!!!
1 yard=3 feet
51/6 yards X 3 feet=15.5 feet
x*h(x)=4*x^2-5*x f(x)+x*h(x)=4*x^2-5*x+3*x+1=4*x^2-2*x+1 g(x)=3*x+1 g(f(x)+x*h(x))=g(4*x^2-2*x+1) (4*x^2-2*x+1)=x g(4*x^2-2*x+1)=3*(4*x^2-2*x+1)+1=12*x^2+4-6*x
