All Answers 358514 Answers

Answer  is 5 

it is just addition but very lengthy

just narrow it down

like 5+5=10

take out the 5+5 from the equation and replace it with a 10

A= -5 

So A*2=-5*2

-10-b*6

b=7

So 7*6=42

-10-42=52

Answer    52

this is what i use to change decimals to fractions

on the keyboard derp

You have to reverse the foil

That is all i can give you

it is a triple foil

example: (x+/-3)(x+/-3)(x+/-3)

What is the the angle measure? B ecause if it is 30 or 60 then it is a 30-60-90 triangle

you write it as 15/8

you put the nominator and then a division mark then the denominator

 the answer is 48

you listen to drake songs and you'll end up at her front door

SSEEEEXXXAAAYYYYY

It's not possible to answer this question unless you are told the relative elevations of Rowena and the top or bottom of the pyramid. That is, is the ground totally flat so that Rowena's feet are on the same level as the base of the pyramid or are they on the same level as the top of the pyramid, or at some other height ?

Write your integrand as $$1.(\log(x))^{n}$$ and integrate by parts, integrating the 1 and differentiating the log.

That gets you a reduction formula which you have to use twice, once for P10 and then again for P9.

I am guessing that there must be an easy result to this question, however I have not yet found it.

I have a WolframAlpha pro account and I did find the following;

the indefinite integral of (logx)^n is given by;

$$\int log^n(x)dx = (-log(x))^-^nlog^n(x)T(n+1,-log(x)) + C$$

Where T(alpha,x) is the incomplete gamma function (and C is off course the constant)

Since I did not feel like computing this myself, I gave WA a shot at your question and after it probably blew up servers in four countries around the world it gave me this;

$$\int_{1}^{e} log(x)^1^0 - 90* \int_{1}^{e} log(x)^8 = -9e$$ 

which to me was as meaningful as 42 (reference: )

To make a long story short (this is funny if you watch s16e06 of south park).

I have the answer, but I dont know how (I'm guessing it must be easier than actually filling in that dreadful formula)

Reinout 

About the only thing I like about the "improved" site is the fact that it keeps me logged on (the "old" site seemingly didn't). The rest of the "new" site is garbage. I'm not sure that  many of the "top responders" are even looking at some of the mistakes that might be nade in the answers given by others. For instance, last night, I made a stupid error on a trig problem that I didn't catch until this morning. Yeah, I went back and "fixed" it, but some smart cookies (like Alan, for instance) would have seen my error immediately and corrected it!! (I don't mind that....we all make some mistakes every now and then!! Where have you gone, Alan??) P.S. .... I also caught an error made by another responder - no, I didn't bother to correct it - but I'm not sure anyone even looked at the answer anyway!! Besides, I had already provided an answer....can't tell if anyone looked at that , either.

I've given up trying to use the "math input" or "math(input=result)" thingys. Maybe somebody else has better success with them than I do, but the "old" "math input" thing worked WAY BETTER and was WAY EASIER to use!!. Also (and I noticed that a person asking a question had the same problem, too), the "superscript" function tends to stay engaged even when you don't want it to...i.e., you can't turn it "off" unless you skip down a few lines and resume typing!!

Im sum.....Andrew's intent to have a "better" site in which to "attract" new members and responders appears to be having the opposite effect.....i.e., the site has discouraged those with questions and those with answers because it's just too frustrating to use!!! Where I come from (the South in the US) we have an old expression...."If it ain't broke, don't try to fix it!!"

The "English" may be incorrect, but I believe that old adage applies in this case..........!!!!

$$((x-1)/x)-2 = ((x-1)/x)-2x/x$$

$$=((x-1-2x)/x) = ((-x-1)/x) = -((x+1)/x)$$

First I multiply 2 by (x/x) which is equal to 1

Then since the denominators are equal I'm allowed to substract 2x from the nominator of the fraction.

This then can be rewritten to $$-((x+1)/x)$$

Reinout

Ooh, and I also forgot;

- I really miss the possibility to edit my post (since for some reason I always think of things after I pressed publish (like this post))

- I also miss the possibility to respond to persons or respond with a quote

This improves the clearity of some posts (especially in the puzzle section) 

Dear mr. Massow,

first of all, thank you for taking the time to improve the website.

I must say that there are indeed still problems but hey, Rome wasn't build in one day!

In my opinion, it might be useful, like the section 'my questions' and 'sticky topics' to have a section alike to 'latest responses'. Which makes it easier for us to see which questions are currently 'live'.

Another possibility might be to give Melody, or maybe even a couple of us the ability to 'bump' questions to the top or towards a 'topics of interest' (which  would be different from the sticky topics). 

Perhaps a part with 'unanswered' questions might also do the trick, however I believe this will not work since not all answers are truely answers to the question (they might add or indicate something about the question)

I understand that you want to try this new Q&A style, and I think that most people who are active on the forum are willing to give it a try, however it is really a necessity to have something alike to the above solutions, because currently it is unworkable. Also I'm not sure how the other users feel about the new Q&A style but personally I must say that the old Q&A style was one of the reasons I really like this forum.

On to another thing...

Would it be possible to give Melody some kind of poweruser rights? Which will help him to redo the sticky topics (since I'm missing a couple and eg. the logic's puzzle probably should be replaced with the general puzzle topic). Also it might genuinly improve the forum to have him be able to delete posts which would censor the forum from language-abuse and other unwanted posts.

I think it's great that many improvements have been made to the forum (especially LaTex even though it is still in the construction phase) !

I'm very happy that we can now make this forum even better than it already was!

Reinout

Oops!!!!!...I made a slight mistake in this problem in the second part.......(sorry)...let me correct thiis...

I wrote

cosx = 1/2

so x = (-pi/6) + 2(pi)n

and x = (pi/6) + 2(pi)n

This should be

cosx = 1/2

so x = (-pi/3) + 2(pi)n

and x = (pi/3) + 2(pi)n

(I should know better than to try to do math late at night!!!)

How do we find the total revenue of a given function p=10-2.5q

Think about this.

if you sell cans of baked beans  for $1.50 per can then p=1.50 dollars

If you sell 8 cans then q=8

The total revenue for the baked beans is $1.50*8 = $12 =  p*q

So TR=price*quantity = (10-2.5q)q = -2.5q² + 10q

There are two sideband frequencies; one at fc+fm (fm is message frequency) and one at fc-fm, in addition to the carrier frequency, fc, itself.

Hi,

Your question has not been answered because circumference is a length and cm2 is an area. So it doesn't make sense.

Melody

Shoe Size 9.5 8.5 12 11.5 13.5 Height (in) 63.7 62.4 69.4 71.5 71.9 Use your calculator to determine the y-intercept of this scatterplot

Using shoe size as the independent variable (x) and height as the dependent variable (y), we have

y = 2.084375x + 44.8518

The y intercept is just the point (0, 44.8518)

If height 1s the dependent variable (x) and shoe size as the independent variable (y), we have

y = 0.422002x  -17.603

 The y intercept here is just (0, -17.603)

(Because the y intercept in the second function is negative, I suspect that shoe size is "x" and height is "y")

BTW....here is an online website that will do this for you.....make sure you don't have any spaces between the "x" and "y" values.......just a comma!!!

http://knowpapa.com/trend-line/

A clock has a radius of 9 inches. If it's 4:00, what's the arc length and the area of the sector of this time? 

I'm assuming that you want the arc length and area of the sector from 12 to 4.

Since this sector represents 1/3 of the total area of the clockface, it must also have an arc length of 1/3 of the total circumference of the clock.

The total circumference is given by 2*pi*9 in = 18pi inches

So 1/3 of the circumference = 6pi inches

And the total area is given by pi * (9 in)^2 = 81pi in^2

And 1/3 of this is just 27pi in^2