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3*9+5*54/6

27+5*54/6

27+5*9

27+45

72

\(x/24 = 3/4\)

Multiply each side by 24 to cancel the 24 on the left and add it to the right

We multiply both sides because we ewould be changing the equation if we didn't

(3/4)*24 = 18

X=18

x over 24 = 3 4ths. Whats X?

It would be more helpful if you wrote it properly, like this:

[x / 24] =3 /4

Solve for x: x/24 = 3/4 Multiply both sides of x/24 = 3/4 by 24: (24 x)/24 = 24×3/4 24×3/4 = (24×3)/4: (24 x)/24 = (24×3)/4 (24 x)/24 = 24/24×x = x: x = (24×3)/4 24/4 = (4×6)/4 = 6: x = 6×3 6×3 = 18: Answer: | | x = 18

18/24 = 3/4

To get that answer,

x/24 = 3/4

Cross multiply 

x(4) and 3(24)

You get

4x=72

Divide both sides by 4 to isolate x.

x= 18.

P(B or Y)  = P(B) + P(Y) - P(B and Y)

P(B or Y)  = 10/18 + 4/18  -  0  

P(B or Y)  = 14/18  =  7/9

Who is "we"?

-2x^2 - 4x

Note.....this parabola has real roots .....and we can solve this by finding these roots

-2x^2 - 4x  = 0

-2x(x + 2)  = 0     so      x = 0   is a root and so is  x = -2 

The axis of symmetry will be  half-way between these at x = - 1

Here's the graph to prove this : https://www.desmos.com/calculator/onfes11awf

talk to you guys later! ;)

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Real question. Why don't we need this??

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solve it when f(x)=0 so; 

0=2/(x+1)

x=0

x=0

f(x)=2/1

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solving for p, get all intergers on one so;

p=-9+4

p=-5

Yurachan is correct forgot the first x

Nice!

What would YOU do for a Klondike bar?

x+x+x+x+2 = 4x+2

If you need to solve for x,

4x+2 = 0

Subtract 2 from both sides to get x by itself.

4x = -2

Divide both sides by 4 to get x by itself.

x= -2/4

Simplify.

x= -1/2

3x+4

3 of whatever x is

+4

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Alex has 67 quarters and dimes worth $13.45.how many coins of each does he have?

Let the number of quarters=Q

Let the number of dimes    =D

Q + D =67

.25Q + .10D=13.45, so that Alex has:

45 Quarters and

22 Dimes

Solve the following system: {D+Q = 67 | (equation 1) 0.1 D+0.25 Q = 13.45 | (equation 2) Subtract 0.1 × (equation 1) from equation 2: {D+Q = 67 | (equation 1) 0 D+0.15 Q = 6.75 | (equation 2) Divide equation 2 by 0.15: {D+Q = 67 | (equation 1) 0. D+Q = 45. | (equation 2) Subtract equation 2 from equation 1: {D+0 Q = 22. | (equation 1) 0 D+Q = 45. | (equation 2) Collect results: Answer: | | {D = 22. Q = 45.