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I dont understand

put in term s of x- 2

don t repost the question just write the link to the question and i already answered that question:

Solve for y:
2.8 y+19.2 = 44.4

Subtract 19.2 from both sides:
2.8 y+(19.2-19.2) = 44.4-19.2

19.2-19.2 = 0:
2.8 y = 44.4-19.2

44.4-19.2 = 25.2:
2.8 y = 25.2

Divide both sides of 2.8 y = 25.2 by 2.8:
(2.8 y)/2.8 = 25.2/2.8

2.8/2.8 = 1:
y = 25.2/2.8

25.2/2.8  =  9.:
Answer: |  y = 9.

2nd button acos

thanks Solveit that helps

here is full answer by cymath:

http://www.cymath.com/answer.php?q=3x%5E2%3D-33x-90 

\(\begin{array}{lcl}3x^2=-33x-90\\ 3x^2+33x+90=0 \text{ (:3)}\\ x^2+11x+30=0\\ (x+6)(x+5)=0\\ x_1=-5\\ x_2=-6 \end{array}\)

it's alright thanks for atleast looking at it.

SHOW_OFF

i cant solve i have no idea what factoring is much less how to do it.

tng65 is correct because everything on vine is true so 9+10 is 21 

Through (5,5);parallel to

paralell lines means their slopes are the same

 \(y=mx+b\)

their m s are the same

\( 5=5\times5+b\\ b=-20\\ \text{your equation is: }\\ y=5x-20\)

\(\frac{44!}{(44-4)!}\times4!\)

\(\frac{44!}{40!}\times4!\)

\(\frac{1\times2\times3\times4\times5\times6\times7\times8\times9\times10\times11\times12\times13\times14\times15\times16\times17\times18\times19\times20\times21\times22\times23\times24\times25\times26\times27\times28\times29\times31\times31\times32\times33\times34\times35\times36\times37\times38\times39\times40\times41\times42\times43\times44}{1\times2\times3\times4\times5\times6\times7\times8\times9\times10\times11\times12\times13\times14\times15\times16\times17\times18\times19\times20\times21\times22\times23\times24\times25\times26\times27\times28\times29\times30\times31\times32\times33\times34\times35\times36\times3\times38\times39\times40}\times1\times2\times3\times4\)

\(\frac{2658271574788448768043625811014615890319638528000000000}{1\times2\times3\times4\times5\times6\times7\times8\times9\times10\times11\times12\times13\times14\times15\times16\times17\times18\times19\times20\times21\times22\times23\times24\times25\times26\times27\times28\times29\times30\times31\times32\times33\times34\times35\times36\times3\times38\times39\times40}\times1\times2\times3\times4\)

\(\frac{2658271574788448768043625811014615890319638528000000000}{815915283247897734345611269596115894272000000000}\times1\times2\times3\times4\)

\(\frac{2658271574788448768043625811014615890319638528000000000}{815915283247897734345611269596115894272000000000}\times24\)

\(3258024\times24\)

\(78192576\)

y=1

x=4

This is easy......the horizontal line through (a, b)   always has the eqauation   y = b

So ....   through    (-5, -2)  we have      y = -2

\(-8x-4y=3 \text{ (:4)} \\ -2x-y=12\\ \)

\(-2x-y=\frac34 \\ -2x-y=12\)

they are prallel because their slopes are the same

In the year 1993, the average cost of a radio could be modeled by the equation C = -15t2 + 1000 where t is the number of years since 1993. By the year 2006 the average cost had changed, so it could be modeled by the equation C = -5t2 + 1200. Find the difference in the average costs for a television between 2006 and 1993

I think:

\(C_{1993}-C_{2006}=-15\times 0^2+1000-(-5\times 0^2+1200)=-200\)

Answer: 200

Hello Ce faci ??

The cost of renting a car for a day is given by the linear funtion c(x)= 0.13x+31, where c(x) is in dollars and x is the number of miles driven.Find the cost of driving the car 200 miles.

put in term s of x-200:

\(c(x)=0.13\times200+31=57\)

\(\sqrt{47}\)

Exact answer

\(\sqrt{47}\)

Approximate answer

\(6.8556546004010441...\)

[ 2 + 2/9]   =   20/9

[ 1 + 1/3 ] =     4/3       so we have

[ 20 / 9 ]  /   [4 /3 ]      invert the second fraction and multiply

[20 / 9 ] * [ 3 / 4 ]  =

[20/ 4] * [ 3 / 9 ]  =

5 *  1/3   =

5 / 3   =    1 + 2/3

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36x2 - 9y2 - 24x + 54y - 113 = 0     add 113 to each side

36x^2 - 9y^2 - 24x + 54y  = 113      complete the square on x and y

36 [x^2 - (2/3)x + 1/9] - 9 [y^2 - 6y + 9]  = 113 + 4 - 81    factor and simplify

36(x - 1/3)^2  - 9 (y - 3)^2  = 36        divide both sides by 36

( x - 1/3)^2         -     (y - 3)^2     =     1

      1                            4

That's SF, Shades.....I think what may be giving you problems is completing the square, particulalrly when the lead coefficient isn't = 1.......here's a resource that might help.......http://regentsprep.org/Regents/math/algtrig/ATE3/quadcompletesquare.htm

Center = (1/3, 3)

Vertices =  [x coordinate of the center ± √ [c^2 - b^2] , y coordinate of the center ]

In this case  c =  √5    and b =  2        so   c^2  = 5     and b^2   = 4

  [  1/3 ± √[5 - 4] , 3 ]    =  [  1/3 + 1 , 3]  and [ 1/3 -1, 3]      =   [ 4/3, 3]   and [-2/3, 3]

Asymptotes

y = ± 2/1 (x - 1/3) + 3

y = ± 2( x - 1/3) + 3

y = 2x -2/3 + 3           and      y = -2x + 2/3 + 3

y = 2x + 7/3              and      y = -2x + 11/3

Here's the graph with the pertinent info, Shades :   https://www.desmos.com/calculator/l7ew2an7qj