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\(50mph\)

\(50\times1,609.344\)

\(80467.2m/h\)

\(\frac{80467.2}{3600}\)

\(22.352m/s\)

thanks

Here is a more elegant solution to this problem:

Let her salary be=x

Solve for x:
(39000-x)/(31200-x) = 40/27

Cross multiply:
27 (39000-x) = 40 (31200-x)

Expand out terms of the left hand side:
1053000-27 x = 40 (31200-x)

Expand out terms of the right hand side:
1053000-27 x = 1248000-40 x

Subtract 1053000-40 x from both sides:
13 x = 195000

Divide both sides by 13:
Answer: |  x = 15,000. This is her salary, so that:

31,200 - 15,000=16,200 This is her commission for Jan.2014. Therefore:

16,200/405,000=4% This is her commission rate.

No, jet fuel des not burn at a hot enough temperature to melt steel, but it does make it pretty weak.

If AB is bisected by M and the length of AB is 12, then A must be 6 units away from M.

It's parallel to the x-axis, so only worry about x-coords for now.

-2 is 10 away from -12.

-2 is 8 away from -10

-2 is 6 away from 4

-2 is 6 away from -8

However, -8 makes more sense because it should go A, then M, then B. So the answer is C. (-8,5)

We dont like to talk about 9/11.

Now to a real question: does jet fuel melt steel beams?

:P

Use the calculator.

(Dont encourage him by giving the answer)

Agree because x+(-7)=x-7

Use the slope formula to find the slope that is perpendicular.

Remember the slope formula is y₂-y₁/x₂-x₁.

\({7-1\over5-1}\)

\({6\over4}\)

6/4=3/2.

The OPPOSITE RECIPROCAL of 3/2 is -2/3, so the answer must be B.

2sqrt(2) * 3sqrt(3) * 5sqrt(12)

2 √ 2  *  3 √3  * 5 √12      and since we're multiplying....we can switch the order any way we would like......so we have.....

[ 2 * 3 * 5  ]   *  [ √2 * √3 * √12 ]

[ 30]  *  [ √2 * √3 * √4 * √3 ]

[30] * [ √2 * √3 * 2 * √3 ]

[30 *2] * [ √3 * √3 * √2 ]

60  * [ 3 * √2 ]

60 * 3  * √2 

180 √2

study hard and give it your all.

Log(25) / Log(5)=2, so that:

5^2=25

A window shaped like a parallelogram has an area of 18 and 1 over 3 square feet.The height of the window is 3 and 1 over 3 feet.How long is the base of the window?

18 + 1/3 =   55 / 3

3 + 1/3   =  10 / 3

A_{parallelogram}   =  B * H  ....... so we have

55/3  = B * 10/ 3      multiply both sides by  3 / 10

(55/3) (3/10)   = B  =  55/ 10    =  5 + 5/10 ft    =   5 + 1/2  ft

5.

For Descartes rule you must look at the sign changes of rthew coefficient

\(f(x)=-2x^3+3x^2-5x-2\\ \mbox{-2 then +3 first sign change}\\ \mbox{+3 then -5 second sign change.}\\ \mbox{-5 then -2 Sign did not change}\\ \)

So there is a maximum of 2 roots on the positive x axis. but they could be complex roots so there are either 2 roots or 0 roots on positive x axis.

Now look at f(-x)

\(f(-x)=2x^3+3x^2+5x-2\\ \mbox{+2 then +3 Sign did not change}\\ \mbox{+3 then +5 Sign did not change.}\\ \mbox{+5 then -2 first and only sign change}\\ \)

So there is 1 root on the negative x axis.

So this graph will have  0 or 2 positive roots and 1 negative root.

I've never seen Descarte's rule before.  I like it to find the number of positive roots BUT once you have the number of positive roots it is easy to know how many negative roots there could be.

For the example above the degree is 3.  This means that the graph will change directions up to three times and it MUST finish in the 4th and 2nd quadrants because the leading coefficient is negative.  -2 to be precise.

Since it changes direction up to 3 times, if it has up to 2 positive roots it MUST have 1 negative root.  I don't need descarte's rule to tell me that.  :)

Here is the graph

8/36=2/9 Kilometers, so that the scale on the map should be:

1cm: 2/9 km, so that

36cm x 2/9km=8km.

3.     6 - √6

4.    [x +4 ] [x - (6 + i)] [x - ( 6 - i) ]

       [x + 4 ] [ x^2 -x(6 + i) - x(6 -i) + (6 + i)(6 - i) ]

       [x + 4]  [ x^2  - 6x - ix - 6x + ix + 36 - i^2 ]

       [ x + 4] [ x^2 - 12x + 37]

      x^3  - 12x^2  + 37x

                 4x^2   -  48x  + 148

P(x)  = x^3 - 8x^2 - 11x + 148  = 0

5.   -2x^3 + 3x^2 - 5x - 2  = 0

Possible positive roots =  2 or 0

Possible negative roots test

f(-x)   =  2x^2 + 3x^2 + 5x - 2

So...the number of possible negative roots = 1

The last answer is correct

Let her salary be =x

Let the commission rate=y, then we have:

70,200-2x=y*1,005,000. This is a linear Diophantine equation which might have many solutions. But ONE solution that suits your situation is this:

x=15,000 Shs. This is her monthly salary. And,

y=4% This is her commission rate, so that:

4% x 405,000=16,200 Shs + 15,000=31,200 Shs. This is her income for Jan. 2014.

4% x 600,000=24,000 Shs +15,000=39,000 Shs. This is her income for Feb. 2014.

u dumb lol

6x+15=0

6x=-15

x=-(15/6)

12345678987654321 is the answer to 111111111*111111111

7.4

(tan x - sec x)^2 = (1 - sin x)/(1 + sin x)

tan^2x - 2tanxsecx + sec^2x     

tan^2x - 2tanxsecx + [ tan^2x + 1 ]

2tan^2x -2tanxsecx + 1

2sin^2x/cos^2x  - 2 [sinx]/cos^2x  + [cos^2x / cos^2x ]

[ 2sin^2x - 2sinx  + cos^2x] /  cos^2x

[ 2sin^2x - 2sinx + (1 - sin^2x ) ] / cos^2x

[sin^2x - 2 sinx + 1] / cos^2x          factor the numerator

[sinx -1] [sinx - 1]  / [ 1 - sin^2x] 

[sinx -1]  [sinx - 1 ] / (  [ 1 + sinx ] [ 1 - sinx] )        factor  -1  out of the numerator

- [ 1 - sinx] [ sinx - 1] / ([1 + sinx] [ 1 - sinx ] )

- [sinx -1]  / [ 1 + sinx]

[1 - sin x ] / [ 1 + sin x ]

DUDE THAT"S SO COOL!!!!!!!!!!!!!!!!!!!!!!!!!!!

what do you mean by page to practice?

1)   -1x^2  - x = 3 = 0

Possible rational roots  = all the possible factors of -3 over all the possible factors of -1   = ±1, ± 3

2)    2x^3  + 2x^2 - 19x  + 20  = 0

Well...by cheating...[looking at the answers]....I can see that one root is -4

So....using some synthetic division....we can find the remaining polynomial

-4  [  2   2     - 19     20 ]

            -8        24    -20

       ------------------------

       2   -6       5         0

So....the remaining polynomial  is    2x^2   - 6x + 5

And using the quadratic formula,  the other two roots are 

x =   (  6 ±  √[ 36 - 40] )  / [2(2)] =    [ 3 ± i ] / 2