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"cosh" is hyperbolic cosine.

The hyperbolic functions are based upon a hyperbola and not a circle.

A good explanation can be found in Wikipedia:  https://en.wikipedia.org/wiki/Hyperbolic_function

Cosh is actually just the ordinary Cosine, though it's name is a little fancier: Hyperbolic Cosine. The same goes for the rest of the trigonometric notations.

Just saying, the correct answer should be 30. You do need to divide by 2. 

Just saying, the correct answer should be 30. You do need to divide by 2. 

-11.36+72=23 

60.64  = 23   ????

Obviously, this isn't true.....!!!!

1 + 1/9   = 10/9     so

7/9 + x  = 10/9     subtract 7/9 from both sides

x = 3/9  =  1/3

f(x) = log₃ (5x − 5) and g(x) = log₃ (x − 1)

f(x) - g(x)  =

log₃ (5x − 5) - log₃ (x − 1)  =

log₃   [ (5x -5) / (x -1) ]  =

log₃ [ 5(x -1) / (x - 1) ]  =

log₃ 5

Give an example and will show you how.

-7 (z - 6)  = - 70     divide both sides by -7

z - 6  =  10        add 6 to both sides

z  = 16

z=16

x^2+5x-14 and 49-x^2

First....let's factor both of these

x^2 + 5x - 14   =  (x +7)(x - 2)

x^2 - 49   = (x + 7) (x -7)

The binomial factor they share is (x + 7)     [ "bi"  means two.....as in "two terms"  ]

So...a "binomial" factor is a factor with two terms....

Julio....I'm assuming that you want to factor this:

16ax + 4x^2 +16a^2    ...if so....pull out the greatest common factor, first  =  4

4 [ 4ax + x^2 + 4a^2]     rearrange the inside terms

4 [ x^2 + 4ax + 4a^2]   factor the inside expression

4 [ x  + 2a] [x + 2a]   =

4 [ x + 2a] ^2

And that's it......!!!

Nope, the answer 144 is correct! Thanks guys!

z = 16

f(x) = log₃ (x + 1)      let's write "y" for f(x)   .....and we have...

y = log₃ (x + 1)

This says that......in exponential form....

3^y  = x + 1       subtract 1 from both sides   

3^y - 1   = x          exchange x and y

3^x - 1  = y         and for y, write  f^-1(x)

So

f^-1(x)  = 3^x - 1        ....and......

f^-1(2)  = 3*2  - 1   = 8

So....the point  (2, 8) is on the inverse

Check to see that the point (8, 2)  is on the original graph....and it is  !!!!

14, 22, 27

http://www.bbc.co.uk/bitesize/standard/maths_ii/relationships/boxplots/revision/1/

$7320 is correct if you add $4 every week,

but if you meant you add your first $4 to $8 (=12), then add that to the third week $12 (=24),

then $7320 would be how much you save in week 60 alone, and the total would be $151,280

Here's a pic of the situation :

m< EAB + m< BAC = 90           given

Since ABC is a right angle, then so is ABE

Then m<EAB + m<BEA = 90   [ three angles of any triangle sum to 180 ]

Then m< EAB + m< BAC  = m<EAB + m<BEA   [  subtract m<EAB  from both sides]

m< BAC = m <BEA

And this means that m<ACB = m<BAE

Then, by AAA, ΔEBA is similar to ΔABC

And in a like manner....we can prove that ΔCBD is similar to ΔABC

But ΔEBA  was already proved to similar ΔABC as well ....so....

ΔCBD is also similar to ΔEBA        

Thus     AB    =   DB

             BE         BC

And, by cross-product equality.....  BE * DB  = AB * BC

And BE = EB    and DB = BD

So......  EB * BD  = AB * BC

You can't divide 0 by 0. You are dividing nothing by nothing

Hello,

 i see that u had put 2 solutions for the denominator in 2 different ways, but on the right side and the last part....does 3x still remain unsolved after u had divided it by 3

2 < 3x | :3

2/3 < 3x 

does the (x) still remain there? or should it look like this:

 2 < 3x | :3

2/3 < 3

You will have:

=$7,320

Divide 72 by 1/4.

72*4=288